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gerryliyana

  • 3 years ago

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  1. gerryliyana
    • 3 years ago
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    Determine the solution! \[\frac{ dy }{ dx } =-\frac{ x }{ y }\] for y(0) =4 \[y dy = -x dx\] \[\int\limits_{4}^{y} y dy = - \int\limits_{0}^{x} x dx\] \[\frac{ y ^{2} }{ 2 } - \frac{ (2^{2}) }{ 2 } = -\frac{ x ^{2} }{ 2 } \] \[\frac{ y ^{2} }{ 2 } - 2 = -\frac{ x ^{2} }{ 2 }\] \[\frac{ y ^{2} }{ 2 } = 2 - \frac{ x ^{2} }{ 2 }\] \[y ^{2} = 4 - x ^{2}\] \[y = \sqrt{4 -x ^{2}}\]

  2. gerryliyana
    • 3 years ago
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    hbu @kelly226 ???

  3. kelly226
    • 3 years ago
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    it looks right 2 mee:)

  4. gerryliyana
    • 3 years ago
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    ok, thank u @kelly226 :)

  5. kelly226
    • 3 years ago
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    np :)

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