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Help! Ivan walks to school one mile/hr. faster than when he walks back home. If it takes him 12 min. (0.20 hr.) to walk to school and 18 min. (0.30 hr.) to walk back, how fast does he walk to school and how far does he have to walk to school?
 one year ago
 one year ago
Help! Ivan walks to school one mile/hr. faster than when he walks back home. If it takes him 12 min. (0.20 hr.) to walk to school and 18 min. (0.30 hr.) to walk back, how fast does he walk to school and how far does he have to walk to school?
 one year ago
 one year ago

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gerryliyanaBest ResponseYou've already chosen the best response.1
@PhiBeeandJay u can use the simply formula: v = s/t where v is speed, s is distance or displacement, and t is time
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.1
@PhiBeeandJay u got it??
 one year ago

PhiBeeandJayBest ResponseYou've already chosen the best response.0
I'm trying to come up with equation you just gave me.
 one year ago

MathmuseBest ResponseYou've already chosen the best response.0
Distance is your constant value so you can set the to and from school distances equal to each other: \[s_1=s_2\] use the equation that @gerryliyana gave you but in a different form so that you can get rid of the distance. You will also have to introduce a variable x is the speed that Ivan walks home from school: \[s_1*t_1=s_2*t_2\] \[(x+1)*0.2=x*0.3\]
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.1
vs = 1 mil/hr + vh s/0.2 = 1+ (s/0.3) So s?? (where vs is speed Ivan walks to school , and vh is speed he walks back home )
 one year ago

PhiBeeandJayBest ResponseYou've already chosen the best response.0
do I multiply by 0.2 on both sides now?
 one year ago

gerryliyanaBest ResponseYou've already chosen the best response.1
@PhiBeeandJay : So What Did You Get?
 one year ago
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