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anonymous
 3 years ago
Help! Ivan walks to school one mile/hr. faster than when he walks back home. If it takes him 12 min. (0.20 hr.) to walk to school and 18 min. (0.30 hr.) to walk back, how fast does he walk to school and how far does he have to walk to school?
anonymous
 3 years ago
Help! Ivan walks to school one mile/hr. faster than when he walks back home. If it takes him 12 min. (0.20 hr.) to walk to school and 18 min. (0.30 hr.) to walk back, how fast does he walk to school and how far does he have to walk to school?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@PhiBeeandJay u can use the simply formula: v = s/t where v is speed, s is distance or displacement, and t is time

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@PhiBeeandJay u got it??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm trying to come up with equation you just gave me.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Distance is your constant value so you can set the to and from school distances equal to each other: \[s_1=s_2\] use the equation that @gerryliyana gave you but in a different form so that you can get rid of the distance. You will also have to introduce a variable x is the speed that Ivan walks home from school: \[s_1*t_1=s_2*t_2\] \[(x+1)*0.2=x*0.3\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0vs = 1 mil/hr + vh s/0.2 = 1+ (s/0.3) So s?? (where vs is speed Ivan walks to school , and vh is speed he walks back home )

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do I multiply by 0.2 on both sides now?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@PhiBeeandJay : So What Did You Get?
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