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PhiBeeandJay Group Title

Help! Ivan walks to school one mile/hr. faster than when he walks back home. If it takes him 12 min. (0.20 hr.) to walk to school and 18 min. (0.30 hr.) to walk back, how fast does he walk to school and how far does he have to walk to school?

  • 2 years ago
  • 2 years ago

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  1. gerryliyana Group Title
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    @PhiBeeandJay u can use the simply formula: v = s/t where v is speed, s is distance or displacement, and t is time

    • 2 years ago
  2. gerryliyana Group Title
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    @PhiBeeandJay u got it??

    • 2 years ago
  3. gerryliyana Group Title
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    please try

    • 2 years ago
  4. PhiBeeandJay Group Title
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    I'm trying to come up with equation you just gave me.

    • 2 years ago
  5. Mathmuse Group Title
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    Distance is your constant value so you can set the to and from school distances equal to each other: \[s_1=s_2\] use the equation that @gerryliyana gave you but in a different form so that you can get rid of the distance. You will also have to introduce a variable x is the speed that Ivan walks home from school: \[s_1*t_1=s_2*t_2\] \[(x+1)*0.2=x*0.3\]

    • 2 years ago
  6. gerryliyana Group Title
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    vs = 1 mil/hr + vh s/0.2 = 1+ (s/0.3) So s?? (where vs is speed Ivan walks to school , and vh is speed he walks back home )

    • 2 years ago
  7. PhiBeeandJay Group Title
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    do I multiply by 0.2 on both sides now?

    • 2 years ago
  8. gerryliyana Group Title
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    yess

    • 2 years ago
  9. gerryliyana Group Title
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    @PhiBeeandJay : So What Did You Get?

    • 2 years ago
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