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PhiBeeandJay

  • 3 years ago

Help! Ivan walks to school one mile/hr. faster than when he walks back home. If it takes him 12 min. (0.20 hr.) to walk to school and 18 min. (0.30 hr.) to walk back, how fast does he walk to school and how far does he have to walk to school?

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  1. gerryliyana
    • 3 years ago
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    @PhiBeeandJay u can use the simply formula: v = s/t where v is speed, s is distance or displacement, and t is time

  2. gerryliyana
    • 3 years ago
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    @PhiBeeandJay u got it??

  3. gerryliyana
    • 3 years ago
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    please try

  4. PhiBeeandJay
    • 3 years ago
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    I'm trying to come up with equation you just gave me.

  5. Mathmuse
    • 3 years ago
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    Distance is your constant value so you can set the to and from school distances equal to each other: \[s_1=s_2\] use the equation that @gerryliyana gave you but in a different form so that you can get rid of the distance. You will also have to introduce a variable x is the speed that Ivan walks home from school: \[s_1*t_1=s_2*t_2\] \[(x+1)*0.2=x*0.3\]

  6. gerryliyana
    • 3 years ago
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    vs = 1 mil/hr + vh s/0.2 = 1+ (s/0.3) So s?? (where vs is speed Ivan walks to school , and vh is speed he walks back home )

  7. PhiBeeandJay
    • 3 years ago
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    do I multiply by 0.2 on both sides now?

  8. gerryliyana
    • 3 years ago
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    yess

  9. gerryliyana
    • 3 years ago
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    @PhiBeeandJay : So What Did You Get?

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