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Study23
Group Title
Implicit Differentiation? Don't Understand it :( PLEASE HELP! Here's the problem I am looking at: \(\ \large x^3+x^2y+4x^2=6 .\)
Find \(\ \frac{dy}{dx}. \) Please show me STEP by STEP!!
 one year ago
 one year ago
Study23 Group Title
Implicit Differentiation? Don't Understand it :( PLEASE HELP! Here's the problem I am looking at: \(\ \large x^3+x^2y+4x^2=6 .\) Find \(\ \frac{dy}{dx}. \) Please show me STEP by STEP!!
 one year ago
 one year ago

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Ventricate Group TitleBest ResponseYou've already chosen the best response.1
3x^2+2xy+2x dy/dx +8x= 0 then isolate dy/dx and simplify from there. Do you get that or need me to explain it?
 one year ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
Could you explain it to me please?
 one year ago

Ventricate Group TitleBest ResponseYou've already chosen the best response.1
Are you familiar with the derivative rules?
 one year ago

Ventricate Group TitleBest ResponseYou've already chosen the best response.1
Ok so the first part 3x^2 is from the normal derivative way and then when we move on to derive x^2y we have to use the product rule : (x^2)(y) The product rule I hope you know already is (a'(x)*b)+(a*b'(x)) for ab respectively. Do you understand up to here?
 one year ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
How does the product rule look like when you derive \(\ x^2y?\)
 one year ago

Ventricate Group TitleBest ResponseYou've already chosen the best response.1
It should be f'(x) *y + f(x) *y'. Derivative of x^2 is 2x and derivative of y is dy/dx.
 one year ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
Could you show me the product rule in terms of \(\ x^2y \text{, please?}\)
 one year ago

Ventricate Group TitleBest ResponseYou've already chosen the best response.1
Sure (2x)(y) +(x^2)(dy/dx)
 one year ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
What does the dy/dx mean? dy/dx of x^2? or y?
 one year ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
I'm REALLY Confused BY this! !
 one year ago

Ventricate Group TitleBest ResponseYou've already chosen the best response.1
it's the derivative of y
 one year ago

Ventricate Group TitleBest ResponseYou've already chosen the best response.1
Let's say you had y^3 you would derive it as \[3y^2 \frac{ dy }{ dx }\]
 one year ago
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