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Study23
Group Title
Implicit Differentiation? Don't Understand it :( PLEASE HELP! Here's the problem I am looking at: \(\ \large x^3+x^2y+4x^2=6 .\)
Find \(\ \frac{dy}{dx}. \) Please show me STEP by STEP!!
 2 years ago
 2 years ago
Study23 Group Title
Implicit Differentiation? Don't Understand it :( PLEASE HELP! Here's the problem I am looking at: \(\ \large x^3+x^2y+4x^2=6 .\) Find \(\ \frac{dy}{dx}. \) Please show me STEP by STEP!!
 2 years ago
 2 years ago

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Ventricate Group TitleBest ResponseYou've already chosen the best response.1
3x^2+2xy+2x dy/dx +8x= 0 then isolate dy/dx and simplify from there. Do you get that or need me to explain it?
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
Could you explain it to me please?
 2 years ago

Ventricate Group TitleBest ResponseYou've already chosen the best response.1
Are you familiar with the derivative rules?
 2 years ago

Ventricate Group TitleBest ResponseYou've already chosen the best response.1
Ok so the first part 3x^2 is from the normal derivative way and then when we move on to derive x^2y we have to use the product rule : (x^2)(y) The product rule I hope you know already is (a'(x)*b)+(a*b'(x)) for ab respectively. Do you understand up to here?
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
How does the product rule look like when you derive \(\ x^2y?\)
 2 years ago

Ventricate Group TitleBest ResponseYou've already chosen the best response.1
It should be f'(x) *y + f(x) *y'. Derivative of x^2 is 2x and derivative of y is dy/dx.
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
Could you show me the product rule in terms of \(\ x^2y \text{, please?}\)
 2 years ago

Ventricate Group TitleBest ResponseYou've already chosen the best response.1
Sure (2x)(y) +(x^2)(dy/dx)
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
What does the dy/dx mean? dy/dx of x^2? or y?
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
I'm REALLY Confused BY this! !
 2 years ago

Ventricate Group TitleBest ResponseYou've already chosen the best response.1
it's the derivative of y
 2 years ago

Ventricate Group TitleBest ResponseYou've already chosen the best response.1
Let's say you had y^3 you would derive it as \[3y^2 \frac{ dy }{ dx }\]
 2 years ago
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