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iluvvyyhu

  • 2 years ago

Help with logs?Cant use a calculator?:( Evaluate, without using a calculator 5^(-2)

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  1. iluvvyyhu
    • 2 years ago
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    Oh wait i put the wrong one sowwy :( \[\log _{6}1\]

  2. ludwig457
    • 2 years ago
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    log(a)y = a^y

  3. iluvvyyhu
    • 2 years ago
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    im a little confused.....would it be \[6^{1}\] than?

  4. ludwig457
    • 2 years ago
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    yes :)

  5. iluvvyyhu
    • 2 years ago
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    ohh okay thankyou(: um may you help me with another one? Its a fraction?

  6. ludwig457
    • 2 years ago
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    yesm

  7. iluvvyyhu
    • 2 years ago
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    thankyou!(: okay here it is\[\log _{6}\frac{ 1 }{ \sqrt[5]{36}}\] sorry it took a while to type it lol

  8. ludwig457
    • 2 years ago
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    i did the first one wrong it should be log(a)x = y and a^y =x

  9. iluvvyyhu
    • 2 years ago
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    ohh... okay im confused now :(

  10. ludwig457
    • 2 years ago
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    the second one is a little out of my league lol you should open a new question with that second part!

  11. iluvvyyhu
    • 2 years ago
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    lol alright but may you explain the first one pleaseee?(: <3

  12. ludwig457
    • 2 years ago
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    so log(a)x is the exponent to which the base a must be raised to give x

  13. ludwig457
    • 2 years ago
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    so to raise 6 by a power of zero will give an output of 1. any number raised to zero will give 1

  14. ludwig457
    • 2 years ago
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    x^0=1

  15. ludwig457
    • 2 years ago
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    2^0=1 and so on

  16. iluvvyyhu
    • 2 years ago
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    so.... okay im not 100% sure but would the answer be 1?

  17. iluvvyyhu
    • 2 years ago
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    Oh and another question (sorry lol) so do you always raise the little number by 0?

  18. ludwig457
    • 2 years ago
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    log(6)1=0 6^0=1

  19. ludwig457
    • 2 years ago
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    nope you 'exponentiate' the little number

  20. ludwig457
    • 2 years ago
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    log(6)1=0 since 6^0=1

  21. iluvvyyhu
    • 2 years ago
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    okay okay...what does exponentiate mean im sorry for all these questions

  22. ludwig457
    • 2 years ago
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    The act of raising a quantity to a power :)

  23. iluvvyyhu
    • 2 years ago
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    okay(: but im still confused :'(

  24. ludwig457
    • 2 years ago
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    they confuse me too hehe

  25. ludwig457
    • 2 years ago
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    log(a)x = y <=> a^y = x

  26. ludwig457
    • 2 years ago
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    just remember that a is your base, the base will always be the same for any log

  27. ludwig457
    • 2 years ago
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    any number raised to a power like a^x, a will be your base

  28. ludwig457
    • 2 years ago
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    imm off gluck

  29. iluvvyyhu
    • 2 years ago
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    alright:/ thanks though <3

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