## anonymous 3 years ago Help with logs?Cant use a calculator?:( Evaluate, without using a calculator 5^(-2)

1. anonymous

Oh wait i put the wrong one sowwy :( $\log _{6}1$

2. anonymous

log(a)y = a^y

3. anonymous

im a little confused.....would it be $6^{1}$ than?

4. anonymous

yes :)

5. anonymous

ohh okay thankyou(: um may you help me with another one? Its a fraction?

6. anonymous

yesm

7. anonymous

thankyou!(: okay here it is$\log _{6}\frac{ 1 }{ \sqrt[5]{36}}$ sorry it took a while to type it lol

8. anonymous

i did the first one wrong it should be log(a)x = y and a^y =x

9. anonymous

ohh... okay im confused now :(

10. anonymous

the second one is a little out of my league lol you should open a new question with that second part!

11. anonymous

lol alright but may you explain the first one pleaseee?(: <3

12. anonymous

so log(a)x is the exponent to which the base a must be raised to give x

13. anonymous

so to raise 6 by a power of zero will give an output of 1. any number raised to zero will give 1

14. anonymous

x^0=1

15. anonymous

2^0=1 and so on

16. anonymous

so.... okay im not 100% sure but would the answer be 1?

17. anonymous

Oh and another question (sorry lol) so do you always raise the little number by 0?

18. anonymous

log(6)1=0 6^0=1

19. anonymous

nope you 'exponentiate' the little number

20. anonymous

log(6)1=0 since 6^0=1

21. anonymous

okay okay...what does exponentiate mean im sorry for all these questions

22. anonymous

The act of raising a quantity to a power :)

23. anonymous

okay(: but im still confused :'(

24. anonymous

they confuse me too hehe

25. anonymous

log(a)x = y <=> a^y = x

26. anonymous

just remember that a is your base, the base will always be the same for any log

27. anonymous

any number raised to a power like a^x, a will be your base

28. anonymous

imm off gluck

29. anonymous

alright:/ thanks though <3