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anonymous
 4 years ago
cscθcotθ=sinθ/(1+cosθ)
im working on the left side and i got:
(1/sinθ)  cosθ/sinθ = (1 cosθ)/sinθ
now im stuck. help?
anonymous
 4 years ago
cscθcotθ=sinθ/(1+cosθ) im working on the left side and i got: (1/sinθ)  cosθ/sinθ = (1 cosθ)/sinθ now im stuck. help?

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what did you do to the right? What is the assignment, are you proving one side equal to other, or solving equation?

rob1525
 4 years ago
Best ResponseYou've already chosen the best response.0what the original problem?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yep, that works... keep going:)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i am proving that both sides are equal and im only allowed to work on one side.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 1\cos \theta }{\sin \theta } =\frac {\sin \theta } {1+\cos \theta }\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh, only allowed to work on the LHS?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that is what i have so far but im stuck and what does LHS mean?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i can work on either side but once i start working on one side im limited to that side.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0use sin^2 x + cos ^2 x =1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sin^2 x = 1 cos^2 x = (1+cosx)(1cosx)

rob1525
 4 years ago
Best ResponseYou've already chosen the best response.0multiply the top and bottom by cos(theta) .right, then use identities to simplify.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sin x / (1cosx) = (1+cosx)/sin x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It requires algebraic manipulation. Continuing from Algebraic work abovedw:1352775535108:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Above is left hand side only, continuing from Algebraic start. Working on lefthand side only.
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