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zhenga2

  • 3 years ago

cscθ-cotθ=sinθ/(1+cosθ) im working on the left side and i got: (1/sinθ) - cosθ/sinθ = (1- cosθ)/sinθ now im stuck. help?

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  1. chaguanas
    • 3 years ago
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    what did you do to the right? What is the assignment, are you proving one side equal to other, or solving equation?

  2. rob1525
    • 3 years ago
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    what the original problem?

  3. Algebraic!
    • 3 years ago
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    yep, that works... keep going:)

  4. zhenga2
    • 3 years ago
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    i am proving that both sides are equal and im only allowed to work on one side.

  5. Algebraic!
    • 3 years ago
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    \[\frac{ 1-\cos \theta }{\sin \theta } =\frac {\sin \theta } {1+\cos \theta }\]

  6. Algebraic!
    • 3 years ago
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    oh, only allowed to work on the LHS?

  7. zhenga2
    • 3 years ago
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    that is what i have so far but im stuck and what does LHS mean?

  8. Algebraic!
    • 3 years ago
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    left hand side

  9. zhenga2
    • 3 years ago
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    i can work on either side but once i start working on one side im limited to that side.

  10. Algebraic!
    • 3 years ago
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    ok

  11. Algebraic!
    • 3 years ago
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    use sin^2 x + cos ^2 x =1

  12. Algebraic!
    • 3 years ago
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    sin^2 x = 1- cos^2 x = (1+cosx)(1-cosx)

  13. rob1525
    • 3 years ago
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    multiply the top and bottom by cos(theta) .right, then use identities to simplify.

  14. Algebraic!
    • 3 years ago
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    sin x / (1-cosx) = (1+cosx)/sin x

  15. Algebraic!
    • 3 years ago
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    or vice versa:)

  16. chaguanas
    • 3 years ago
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    It requires algebraic manipulation. Continuing from Algebraic work above|dw:1352775535108:dw|

  17. chaguanas
    • 3 years ago
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    Above is left hand side only, continuing from Algebraic start. Working on lefthand side only.

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