## anonymous 3 years ago cscθ-cotθ=sinθ/(1+cosθ) im working on the left side and i got: (1/sinθ) - cosθ/sinθ = (1- cosθ)/sinθ now im stuck. help?

1. anonymous

what did you do to the right? What is the assignment, are you proving one side equal to other, or solving equation?

2. rob1525

what the original problem?

3. anonymous

yep, that works... keep going:)

4. anonymous

i am proving that both sides are equal and im only allowed to work on one side.

5. anonymous

$\frac{ 1-\cos \theta }{\sin \theta } =\frac {\sin \theta } {1+\cos \theta }$

6. anonymous

oh, only allowed to work on the LHS?

7. anonymous

that is what i have so far but im stuck and what does LHS mean?

8. anonymous

left hand side

9. anonymous

i can work on either side but once i start working on one side im limited to that side.

10. anonymous

ok

11. anonymous

use sin^2 x + cos ^2 x =1

12. anonymous

sin^2 x = 1- cos^2 x = (1+cosx)(1-cosx)

13. rob1525

multiply the top and bottom by cos(theta) .right, then use identities to simplify.

14. anonymous

sin x / (1-cosx) = (1+cosx)/sin x

15. anonymous

or vice versa:)

16. anonymous

It requires algebraic manipulation. Continuing from Algebraic work above|dw:1352775535108:dw|

17. anonymous

Above is left hand side only, continuing from Algebraic start. Working on lefthand side only.