anonymous
  • anonymous
cscθ-cotθ=sinθ/(1+cosθ) im working on the left side and i got: (1/sinθ) - cosθ/sinθ = (1- cosθ)/sinθ now im stuck. help?
Mathematics
katieb
  • katieb
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
what did you do to the right? What is the assignment, are you proving one side equal to other, or solving equation?
rob1525
  • rob1525
what the original problem?
anonymous
  • anonymous
yep, that works... keep going:)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
i am proving that both sides are equal and im only allowed to work on one side.
anonymous
  • anonymous
\[\frac{ 1-\cos \theta }{\sin \theta } =\frac {\sin \theta } {1+\cos \theta }\]
anonymous
  • anonymous
oh, only allowed to work on the LHS?
anonymous
  • anonymous
that is what i have so far but im stuck and what does LHS mean?
anonymous
  • anonymous
left hand side
anonymous
  • anonymous
i can work on either side but once i start working on one side im limited to that side.
anonymous
  • anonymous
ok
anonymous
  • anonymous
use sin^2 x + cos ^2 x =1
anonymous
  • anonymous
sin^2 x = 1- cos^2 x = (1+cosx)(1-cosx)
rob1525
  • rob1525
multiply the top and bottom by cos(theta) .right, then use identities to simplify.
anonymous
  • anonymous
sin x / (1-cosx) = (1+cosx)/sin x
anonymous
  • anonymous
or vice versa:)
anonymous
  • anonymous
It requires algebraic manipulation. Continuing from Algebraic work above|dw:1352775535108:dw|
anonymous
  • anonymous
Above is left hand side only, continuing from Algebraic start. Working on lefthand side only.

Looking for something else?

Not the answer you are looking for? Search for more explanations.