zhenga2
cscθcotθ=sinθ/(1+cosθ)
im working on the left side and i got:
(1/sinθ)  cosθ/sinθ = (1 cosθ)/sinθ
now im stuck. help?



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chaguanas
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what did you do to the right? What is the assignment, are you proving one side equal to other, or solving equation?

rob1525
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what the original problem?

Algebraic!
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yep, that works... keep going:)

zhenga2
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i am proving that both sides are equal and im only allowed to work on one side.

Algebraic!
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\[\frac{ 1\cos \theta }{\sin \theta } =\frac {\sin \theta } {1+\cos \theta }\]

Algebraic!
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oh, only allowed to work on the LHS?

zhenga2
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that is what i have so far but im stuck and what does LHS mean?

Algebraic!
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left hand side

zhenga2
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i can work on either side but once i start working on one side im limited to that side.

Algebraic!
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ok

Algebraic!
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use sin^2 x + cos ^2 x =1

Algebraic!
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sin^2 x = 1 cos^2 x = (1+cosx)(1cosx)

rob1525
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multiply the top and bottom by cos(theta) .right, then use identities to simplify.

Algebraic!
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sin x / (1cosx) = (1+cosx)/sin x

Algebraic!
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or vice versa:)

chaguanas
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It requires algebraic manipulation. Continuing from Algebraic work abovedw:1352775535108:dw

chaguanas
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Above is left hand side only, continuing from Algebraic start. Working on lefthand side only.