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cscθ-cotθ=sinθ/(1+cosθ) im working on the left side and i got: (1/sinθ) - cosθ/sinθ = (1- cosθ)/sinθ now im stuck. help?

Mathematics
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what did you do to the right? What is the assignment, are you proving one side equal to other, or solving equation?
what the original problem?
yep, that works... keep going:)

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Other answers:

i am proving that both sides are equal and im only allowed to work on one side.
\[\frac{ 1-\cos \theta }{\sin \theta } =\frac {\sin \theta } {1+\cos \theta }\]
oh, only allowed to work on the LHS?
that is what i have so far but im stuck and what does LHS mean?
left hand side
i can work on either side but once i start working on one side im limited to that side.
ok
use sin^2 x + cos ^2 x =1
sin^2 x = 1- cos^2 x = (1+cosx)(1-cosx)
multiply the top and bottom by cos(theta) .right, then use identities to simplify.
sin x / (1-cosx) = (1+cosx)/sin x
or vice versa:)
It requires algebraic manipulation. Continuing from Algebraic work above|dw:1352775535108:dw|
Above is left hand side only, continuing from Algebraic start. Working on lefthand side only.

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