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cscθcotθ=sinθ/(1+cosθ)
im working on the left side and i got:
(1/sinθ)  cosθ/sinθ = (1 cosθ)/sinθ
now im stuck. help?
 one year ago
 one year ago
cscθcotθ=sinθ/(1+cosθ) im working on the left side and i got: (1/sinθ)  cosθ/sinθ = (1 cosθ)/sinθ now im stuck. help?
 one year ago
 one year ago

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chaguanasBest ResponseYou've already chosen the best response.0
what did you do to the right? What is the assignment, are you proving one side equal to other, or solving equation?
 one year ago

rob1525Best ResponseYou've already chosen the best response.0
what the original problem?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
yep, that works... keep going:)
 one year ago

zhenga2Best ResponseYou've already chosen the best response.0
i am proving that both sides are equal and im only allowed to work on one side.
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
\[\frac{ 1\cos \theta }{\sin \theta } =\frac {\sin \theta } {1+\cos \theta }\]
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
oh, only allowed to work on the LHS?
 one year ago

zhenga2Best ResponseYou've already chosen the best response.0
that is what i have so far but im stuck and what does LHS mean?
 one year ago

zhenga2Best ResponseYou've already chosen the best response.0
i can work on either side but once i start working on one side im limited to that side.
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
use sin^2 x + cos ^2 x =1
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
sin^2 x = 1 cos^2 x = (1+cosx)(1cosx)
 one year ago

rob1525Best ResponseYou've already chosen the best response.0
multiply the top and bottom by cos(theta) .right, then use identities to simplify.
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
sin x / (1cosx) = (1+cosx)/sin x
 one year ago

chaguanasBest ResponseYou've already chosen the best response.0
It requires algebraic manipulation. Continuing from Algebraic work abovedw:1352775535108:dw
 one year ago

chaguanasBest ResponseYou've already chosen the best response.0
Above is left hand side only, continuing from Algebraic start. Working on lefthand side only.
 one year ago
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