## zhenga2 Group Title cscθ-cotθ=sinθ/(1+cosθ) im working on the left side and i got: (1/sinθ) - cosθ/sinθ = (1- cosθ)/sinθ now im stuck. help? one year ago one year ago

1. chaguanas Group Title

what did you do to the right? What is the assignment, are you proving one side equal to other, or solving equation?

2. rob1525 Group Title

what the original problem?

3. Algebraic! Group Title

yep, that works... keep going:)

4. zhenga2 Group Title

i am proving that both sides are equal and im only allowed to work on one side.

5. Algebraic! Group Title

$\frac{ 1-\cos \theta }{\sin \theta } =\frac {\sin \theta } {1+\cos \theta }$

6. Algebraic! Group Title

oh, only allowed to work on the LHS?

7. zhenga2 Group Title

that is what i have so far but im stuck and what does LHS mean?

8. Algebraic! Group Title

left hand side

9. zhenga2 Group Title

i can work on either side but once i start working on one side im limited to that side.

10. Algebraic! Group Title

ok

11. Algebraic! Group Title

use sin^2 x + cos ^2 x =1

12. Algebraic! Group Title

sin^2 x = 1- cos^2 x = (1+cosx)(1-cosx)

13. rob1525 Group Title

multiply the top and bottom by cos(theta) .right, then use identities to simplify.

14. Algebraic! Group Title

sin x / (1-cosx) = (1+cosx)/sin x

15. Algebraic! Group Title

or vice versa:)

16. chaguanas Group Title

It requires algebraic manipulation. Continuing from Algebraic work above|dw:1352775535108:dw|

17. chaguanas Group Title

Above is left hand side only, continuing from Algebraic start. Working on lefthand side only.