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anonymous
 3 years ago
Need help in integral area involve 3d objects
anonymous
 3 years ago
Need help in integral area involve 3d objects

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what's your question?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ah I see those are multiple choices...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0did you get the 'sketch the region' one?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0basically just asking you to pick which of those areas is bounded by y=5, x=4 and the function...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the first choice is bounded by y=10, x=4 and the function... the second choice is bounded by y=10, x=0, x=4 and the function...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I know the answer for the first picture already, not sure about the 2nd one @Algebraic!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0For the first picture, i think it is the last one for the 2nd picture, i am thinking either 1st or 4th one , what do u think ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0naw, the last picture is bounded by x=0 y=0 and the function...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so for the first picture, u also think is the last one?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0for my function, x is not 0 u mean?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0just trace around each of those red regions and see what functions or lines your tracing...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what lines do you trace for the last choice?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352777609189:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yea, that's what i have too. dont really know how i got that..but yeah.. Do you possibly know how to volume the volume of this?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352777630991:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352777716676:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dont u need to integrate the area function to volume , and then something to do with the height..?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so... is that the region described in your problem statement??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0really? your problem statement makes no mention of x=0 or y=0 ...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it does mention y=5 however...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well, but it says rotate about y= 10, and y= 5

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then u can kinda know there is a hole in between

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0umm..wait..so which picture do you think it is for the first set of picture? i thought we have the same answer

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the region is bounded by x=4 y=5 and y=5e^x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0like I said trace the boundary of the regions you have been given to find which one works with that description..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0there's no point in guessing here... even though this is multiple guess

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i still think is the last one..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that's why i want to know which one u think it is

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0why is it the last one..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0are you talking about the first part or the second part?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0because if you do the first part correctly, the answer to the second part should be obvious

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so do you agree that it is either the bottom left or bottom right picture is correct due to the fact that given y=5

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then why are you saying it's the last region?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0why is it not the last picture ..lol dw:1352778179844:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0did you see the sketches where I traced the bounding functions??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the curve is y= 5e^x , y =5 , x=4

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what functions bound the region in the last picture?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hint: I already did it for you.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0x=0, y=0..which i dont really get u ..o_o

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352778560923:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352778627593:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0are you trying to say that radius doesnt bound to x=0?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0which it does indeed make sense when i look in the 2nd part

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'd focus on the first part, if I were you..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0picking which region is bounded by y=5, x=4 and y= 5e^x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i'm not sure what u mean by bounded..do you mean by starting from there？

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0trace the boundary of each region

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0like I did... for the last region pictured in your choices...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if i do what u did, then the answer will be the bottom left

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but my question with that picture is.. don't u need to do 5 5e^t in order to get tht area?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you'll be using washers probably, since you haven't learned about shells yet (I assume)...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so the inner radius is 5 and the outer radius is 105e^x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yea i didnt yet.. i didnt even learn these stuff much when my assignment is due 2 days after..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ya, i do get that part

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352779152955:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is that region not what the last picture look like?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0for the second part... yep.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can i ask what does "region " mean..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the red areas in the first part.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yea..what does that red area mean

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is it like the path of rotation or something?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it's the thing you're sweeping around the specified axis in order to generate a solid

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352779636199:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0take that region as an example... it's a rectangle...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0rotate about the x axis and you sweep out a cylinder..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so it's kinda you are sweeping that region, and that sweeping motion generate the solid figure?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352779702320:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay thank you so so much!!!!!!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Do you still have time to guide me on filding the volume?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the second multiple choice question? or a new question?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it's the same question. but it asks to find the volume

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0cuz finding the volume is actually the first part..but the graphing part seems easier so i skipped to that first ..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0sure... we are using the washers in the sketch (and in the last choice to the second question)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0inner radius is 5, outer radius is 10  5e^x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0area of a washer will be pi( (10  5e^x)^2  5^2 )

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yea..that's all i have too.. not sure how to integrate that..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\pi \int\limits_{ }^{} (105e^{x})^2  5^2 dx\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\pi \int\limits_{0}^{4} 75 100e^{x} +25e^{2x} dx\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that should be pretty easy to integrate...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh ok..i didnt combine them.. ok thanks, i will try that out :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Algebraic! umm.. how can i leave it as exact numbers..?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i got pi ((300+10 e^4  25/2 e^8) (1025/2))
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