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Algebraic!Best ResponseYou've already chosen the best response.1
what's your question?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
ah I see those are multiple choices...
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
did you get the 'sketch the region' one?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
basically just asking you to pick which of those areas is bounded by y=5, x=4 and the function...
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
the first choice is bounded by y=10, x=4 and the function... the second choice is bounded by y=10, x=0, x=4 and the function...
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
I know the answer for the first picture already, not sure about the 2nd one @Algebraic!
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
For the first picture, i think it is the last one for the 2nd picture, i am thinking either 1st or 4th one , what do u think ?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
naw, the last picture is bounded by x=0 y=0 and the function...
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
so for the first picture, u also think is the last one?
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
for my function, x is not 0 u mean?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
just trace around each of those red regions and see what functions or lines your tracing...
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
what lines do you trace for the last choice?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
dw:1352777609189:dw
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
yea, that's what i have too. dont really know how i got that..but yeah.. Do you possibly know how to volume the volume of this?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
dw:1352777630991:dw
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
dw:1352777716676:dw
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
dont u need to integrate the area function to volume , and then something to do with the height..?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
so... is that the region described in your problem statement??
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
really? your problem statement makes no mention of x=0 or y=0 ...
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
it does mention y=5 however...
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
well, but it says rotate about y= 10, and y= 5
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
then u can kinda know there is a hole in between
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
umm..wait..so which picture do you think it is for the first set of picture? i thought we have the same answer
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
the region is bounded by x=4 y=5 and y=5e^x
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
like I said trace the boundary of the regions you have been given to find which one works with that description..
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
there's no point in guessing here... even though this is multiple guess
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
i still think is the last one..
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
that's why i want to know which one u think it is
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
why is it the last one..
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
are you talking about the first part or the second part?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
because if you do the first part correctly, the answer to the second part should be obvious
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
so do you agree that it is either the bottom left or bottom right picture is correct due to the fact that given y=5
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
then why are you saying it's the last region?
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
why is it not the last picture ..lol dw:1352778179844:dw
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
did you see the sketches where I traced the bounding functions??
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
the curve is y= 5e^x , y =5 , x=4
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
what functions bound the region in the last picture?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
hint: I already did it for you.
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
x=0, y=0..which i dont really get u ..o_o
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
dw:1352778560923:dw
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
what's that portion?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
dw:1352778627593:dw
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
what's that portion?
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
are you trying to say that radius doesnt bound to x=0?
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
which it does indeed make sense when i look in the 2nd part
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
I'd focus on the first part, if I were you..
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
picking which region is bounded by y=5, x=4 and y= 5e^x
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
i'm not sure what u mean by bounded..do you mean by starting from there？
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
trace the boundary of each region
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
like I did... for the last region pictured in your choices...
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
if i do what u did, then the answer will be the bottom left
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
but my question with that picture is.. don't u need to do 5 5e^t in order to get tht area?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
you'll be using washers probably, since you haven't learned about shells yet (I assume)...
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
so the inner radius is 5 and the outer radius is 105e^x
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
yea i didnt yet.. i didnt even learn these stuff much when my assignment is due 2 days after..
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
ya, i do get that part
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
dw:1352779152955:dw
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
is that region not what the last picture look like?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
for the second part... yep.
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
can i ask what does "region " mean..
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
the red areas in the first part.
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
yea..what does that red area mean
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
is it like the path of rotation or something?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
it's the thing you're sweeping around the specified axis in order to generate a solid
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
dw:1352779636199:dw
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
take that region as an example... it's a rectangle...
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
rotate about the x axis and you sweep out a cylinder..
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
so it's kinda you are sweeping that region, and that sweeping motion generate the solid figure?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
dw:1352779702320:dw
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
okay thank you so so much!!!!!!
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
Do you still have time to guide me on filding the volume?
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
the second multiple choice question? or a new question?
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
it's the same question. but it asks to find the volume
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
cuz finding the volume is actually the first part..but the graphing part seems easier so i skipped to that first ..
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
sure... we are using the washers in the sketch (and in the last choice to the second question)
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
inner radius is 5, outer radius is 10  5e^x
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
area of a washer will be pi( (10  5e^x)^2  5^2 )
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
yea..that's all i have too.. not sure how to integrate that..
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
\[\pi \int\limits_{ }^{} (105e^{x})^2  5^2 dx\]
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
\[\pi \int\limits_{0}^{4} 75 100e^{x} +25e^{2x} dx\]
 one year ago

Algebraic!Best ResponseYou've already chosen the best response.1
that should be pretty easy to integrate...
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
oh ok..i didnt combine them.. ok thanks, i will try that out :)
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
@Algebraic! umm.. how can i leave it as exact numbers..?
 one year ago

lovekblueBest ResponseYou've already chosen the best response.0
i got pi ((300+10 e^4  25/2 e^8) (1025/2))
 one year ago
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