## KrystaRenee Justify the last two steps of the proof. Given: AC is congruent to BD and ∠ACB is congruent to ∠DBC. Prove: ΔACD is congruent to ΔDBC. Proof: 1. AC is congruent to BD 1. Given 2. ∠ACB is congruent to ∠DBC 2. Given 3. BC is congruent to CB 3. _?_ 4. ΔACB is congruent to ΔDBC 4. _?_ Reflexive Property of ; SSS Symmetric Property of ; SAS Reflexive Property of ; SAS Symmetric Property of ; SSS I think it's the last one.. one year ago one year ago

1. KrystaRenee

2. KrystaRenee

3. campbell_st

it has to be a SAS test I'd just say common side...

4. KrystaRenee

That doesn't make sense..

5. campbell_st

well BC is a side that is common to both triangles.. hence a common side.... we don't worry about the reflective or symmetrical property... we look at it realistically in Australia, and say... common side

6. KrystaRenee

Ok, but that's not one of the choices.

7. campbell_st

its the reflective property where BC is equal to itself... CB... 3. is reflective property so you have 2 sides and the included angle... so its SAS

8. campbell_st

isn't the symmetric a = b so b = a... but this is a = a....

9. campbell_st

the side... is reflective of its self...

10. campbell_st

but BC and CB are the same line...

11. campbell_st

so proof line 3 needs reflective and conclusion line 4 needs SAS but you are give I side, I angle and since BC = CB... (same line) the triangles are congruent by SAS

12. campbell_st

in the proof statements there is nothing about AB and CD

13. campbell_st

so you can't say congrency is proven by SSS

14. campbell_st

lol... why make it hard... use what is presented...

15. campbell_st

its simply a question asking you to fill in the blanks...

16. KrystaRenee

So I was wrong? Lol.

17. KrystaRenee

Ohh ok, well thank you. I'll go with your answer since it seems more logical.