Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
satellite73
Group Title
@amistre64 please refresh my feeble memory
snap way to find polynomial through (2,4),(0,6),(4,70)
 2 years ago
 2 years ago
satellite73 Group Title
@amistre64 please refresh my feeble memory snap way to find polynomial through (2,4),(0,6),(4,70)
 2 years ago
 2 years ago

This Question is Closed

amistre64 Group TitleBest ResponseYou've already chosen the best response.3
hmm, my method is to construct it such that each x value causes the unknown constants to zero out
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
i thought i had this, but i resorted to a two by two system then i tried writing \[45(x+2)+4x(x+2)\] which worked but it was agony finding those constants i though you had a snap way of finding them
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.3
if you can do a matrix augment, thats pretty snappy
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
yeah but i wanted the snappy method you used
 2 years ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
....also interested in "snappy" method :D
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.3
i believe the method you posted is what i used at first (2,4),(0,6),(4,70) y = a + bx + cx(x+2) ; (0,6) 6 = a +0+0 y = 6 + bx + cx(x+2) ; (2,4) 10 = 2b + 0 ; b=5 y = 6 5x + cx(x+2) ; (4,70) 70+6+20 = c4(4+2) 96/24 = c = 4 y = 6 5x + 4x(x+2)
 2 years ago

joemath314159 Group TitleBest ResponseYou've already chosen the best response.1
Expanding this should work as well
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.3
if there was another method that was snappier; you might have to refresh me memory how it looked to you
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.3
joes looks kinda legendre to me
 2 years ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
@joemath314159, your method looks like some numerical methods stuff
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
no that was what i was looking for i guess that is what i did, somehow it looked easier when you did it. i guess the grass is always greener hello @Hero hello @joemath314159
 2 years ago

joemath314159 Group TitleBest ResponseYou've already chosen the best response.1
It is legendre, learned it in Linear Algebra
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.3
its these lighntning fast clickers of mine, just makes it appear rico y suave lol
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
(0,2) (1,1) (2,6) (3,19)
 2 years ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
@satellite73, are you taking a course?
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
yes, at the school of amistre
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
\[a+bx+cx(x1)+cx(x1)(x2)+dx(x1)(x2)\] actually i think this is slightly different then legrange, but maybe it is identical
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.3
(0,2) (1,1) (2,6) (3,19) y = 2 + bx +cx(x1) + dx(x1)(x2) 1 = 2 + b; b= 3 y = 2 + 3x +cx(x1) + dx(x1)(x2) 6 = 2 +6 + 2c ; c=1 y = 2 + 3x +x(x1) + dx(x1)(x2) 19 = 2 + 9 + 6 + d(2); d=3 y = 2 + 3x +x(x1) + 3x(x1)(x2) if i mathed it right
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.3
legendre i believe zeros out each constant term and omits one zero so that just a single constant is exposed at any time. Newtons method is similar to mine in that new information can be added as needed without have to reconstruct the whole equation
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
yeah legendre looks like what @joemath314159 wrote newtons i am not sure about
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
now i can sleep better. thanks!
 2 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.3
http://nptel.iitm.ac.in/courses/Webcoursecontents/IITKANPUR/mathematics2/node109.html
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.