A community for students.
Here's the question you clicked on:
 0 viewing
satellite73
 4 years ago
@amistre64 please refresh my feeble memory
snap way to find polynomial through (2,4),(0,6),(4,70)
satellite73
 4 years ago
@amistre64 please refresh my feeble memory snap way to find polynomial through (2,4),(0,6),(4,70)

This Question is Closed

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3hmm, my method is to construct it such that each x value causes the unknown constants to zero out

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i thought i had this, but i resorted to a two by two system then i tried writing \[45(x+2)+4x(x+2)\] which worked but it was agony finding those constants i though you had a snap way of finding them

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3if you can do a matrix augment, thats pretty snappy

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah but i wanted the snappy method you used

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0....also interested in "snappy" method :D

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3i believe the method you posted is what i used at first (2,4),(0,6),(4,70) y = a + bx + cx(x+2) ; (0,6) 6 = a +0+0 y = 6 + bx + cx(x+2) ; (2,4) 10 = 2b + 0 ; b=5 y = 6 5x + cx(x+2) ; (4,70) 70+6+20 = c4(4+2) 96/24 = c = 4 y = 6 5x + 4x(x+2)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Expanding this should work as well

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3if there was another method that was snappier; you might have to refresh me memory how it looked to you

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3joes looks kinda legendre to me

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0@joemath314159, your method looks like some numerical methods stuff

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no that was what i was looking for i guess that is what i did, somehow it looked easier when you did it. i guess the grass is always greener hello @Hero hello @joemath314159

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It is legendre, learned it in Linear Algebra

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3its these lighntning fast clickers of mine, just makes it appear rico y suave lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(0,2) (1,1) (2,6) (3,19)

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0@satellite73, are you taking a course?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes, at the school of amistre

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[a+bx+cx(x1)+cx(x1)(x2)+dx(x1)(x2)\] actually i think this is slightly different then legrange, but maybe it is identical

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3(0,2) (1,1) (2,6) (3,19) y = 2 + bx +cx(x1) + dx(x1)(x2) 1 = 2 + b; b= 3 y = 2 + 3x +cx(x1) + dx(x1)(x2) 6 = 2 +6 + 2c ; c=1 y = 2 + 3x +x(x1) + dx(x1)(x2) 19 = 2 + 9 + 6 + d(2); d=3 y = 2 + 3x +x(x1) + 3x(x1)(x2) if i mathed it right

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3legendre i believe zeros out each constant term and omits one zero so that just a single constant is exposed at any time. Newtons method is similar to mine in that new information can be added as needed without have to reconstruct the whole equation

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah legendre looks like what @joemath314159 wrote newtons i am not sure about

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now i can sleep better. thanks!

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3http://nptel.iitm.ac.in/courses/Webcoursecontents/IITKANPUR/mathematics2/node109.html
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.