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Find the x and y intercepts 1.) 4y-8=2x

Mathematics
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To get x-intercept put y=0 in the equation to get y-intercept put x=0 in the equation
can you help me do it and explain each step
4y-8=2x FOR x-INTERCEPT, PUT y=0 in that, what u get ?

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|dw:1352781110121:dw| that is what i got
1.) 4y-8=2x Add 8 4y = 8 + 2x Subtract 2x 4y - 2x = 8 Divide by 8 \[\frac{y}{2} + \frac{x}{-4} = 1\] This is called the "Intercept Form". The answers are staring at you.
-8=2x so x= -8/2 = ?
You have it. Now the other?
-4
hartnn
that is correct.
Okay, now start with x = 0 and find the y-intercept.
4y-8=0 4y=8 y=?
2
Now go take a look at that Intercept Form and see if anything looks interesting - particularly the denominators.
thats correct. any more doubts ?

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