Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

Find \(V_{out}\) of this amplifier...

Engineering
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
|dw:1352781695384:dw|
1. The +ve input is tied to Vin, so the -ve input will attempt to maintain the same voltage. 2. This means that the voltage drop across, and thus the current through, the first 10k resistor is zero. 3. if there's no current through the 1st 10k resistor, then there is no current through the feedback resistor. 4. no current through the feedback resistor means no voltage drop. With no voltage drops the output will see Vin are you sure something isn't grounded in there somewhere?
Should the + not go to ground? If so then it looks like an Op amp inverting amplifier. If resistance is very high ( I hope 10k is enough ) then: \[V _{out} \approx - V _{ in } \frac { R _{ f } }{ R _{ in } }\] hereĀ“s a link to info on similar amps: http://www.renesas.com/edge_ol/engineer/03/index.jsp

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

The resistance Rf can also be named R2, it is the 2nd resistance from the left or the top one if you like.

Not the answer you are looking for?

Search for more explanations.

Ask your own question