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richyw Group Title

Find \(V_{out}\) of this amplifier...

  • one year ago
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  1. richyw Group Title
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    |dw:1352781695384:dw|

    • one year ago
  2. Mathmuse Group Title
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    1. The +ve input is tied to Vin, so the -ve input will attempt to maintain the same voltage. 2. This means that the voltage drop across, and thus the current through, the first 10k resistor is zero. 3. if there's no current through the 1st 10k resistor, then there is no current through the feedback resistor. 4. no current through the feedback resistor means no voltage drop. With no voltage drops the output will see Vin are you sure something isn't grounded in there somewhere?

    • one year ago
  3. FrankJakob Group Title
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    Should the + not go to ground? If so then it looks like an Op amp inverting amplifier. If resistance is very high ( I hope 10k is enough ) then: \[V _{out} \approx - V _{ in } \frac { R _{ f } }{ R _{ in } }\] here´s a link to info on similar amps: http://www.renesas.com/edge_ol/engineer/03/index.jsp

    • one year ago
  4. FrankJakob Group Title
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    The resistance Rf can also be named R2, it is the 2nd resistance from the left or the top one if you like.

    • one year ago
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