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lala2

what is the solution of the linear quadratic system of equations? y=x^2+5x-3 y-x=2

  • one year ago
  • one year ago

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  1. lala2
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    can you remind me of how to find y

    • one year ago
  2. hartnn
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    y -x=2 add 'x' on both sides

    • one year ago
  3. lala2
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    y=2+x

    • one year ago
  4. hartnn
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    right, now put y=2+x in 1st equation

    • one year ago
  5. lala2
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    where in the first equation

    • one year ago
  6. hartnn
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    y=x^2+5x-3

    • one year ago
  7. hartnn
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    y= 2+x 2+x=x^2+5x-3 got this ?

    • one year ago
  8. hartnn
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    no, u just replace 'y' by '2+x'

    • one year ago
  9. hartnn
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    2+x=x^2+5x-3 is correct

    • one year ago
  10. hartnn
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    now bring all 'x' terms on one side you'll get a quadratic in x

    • one year ago
  11. hartnn
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    yeah, subtracting 2 from both sides will give you x^2+4x-5 =0 can u solve this quadratic ?

    • one year ago
  12. lala2
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    hold on let me try

    • one year ago
  13. hartnn
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    sure, take your time :)

    • one year ago
  14. hartnn
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    yes :) so x=1,-5

    • one year ago
  15. lala2
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    Because it asks for a solution not solutions

    • one year ago
  16. hartnn
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    no, there are 2 solutions, because this is quadratic system. put, x=1,-5 in y-x=2 to get two corresponding values of y

    • one year ago
  17. hartnn
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    solution of the linear quadratic system of equations will be of the form, (x1,y1) and (x2,y2) so u have 2 values of x and corresponding 2 values of y

    • one year ago
  18. hartnn
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    yes, 1,3 is one solution, correct. what is other ?

    • one year ago
  19. hartnn
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    yes.

    • one year ago
  20. lala2
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    thank you soooo much i really apperciate it!!!

    • one year ago
  21. lala2
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    I now know how to do this!!!

    • one year ago
  22. hartnn
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    thats great! :)

    • one year ago
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