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stephcanie

  • 2 years ago

Solve the system using elimination. 2x+3y=6 5x-y=-19

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  1. Lukecrayonz
    • 2 years ago
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    To eliminate one of the variables, make one of equations have equal variables just negative and positive. To do this, multiply the second equation by 3 to get -y to -3y, but you must multiply the whole equation. 15x-3y=-57 2x+3y=6

  2. Lukecrayonz
    • 2 years ago
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    Add the equations together now! 15x+2x=17x -57+6=-51 17x=-51 x=-3

  3. Lukecrayonz
    • 2 years ago
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    Whoops, made a mistake.

  4. jiteshmeghwal9
    • 2 years ago
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    First equal one of the variable in both of the equations |dw:1352832467734:dw|

  5. jiteshmeghwal9
    • 2 years ago
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    |dw:1352832598245:dw|

  6. jiteshmeghwal9
    • 2 years ago
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    @ajprincess m i right becoz i m nt ure about this

  7. jiteshmeghwal9
    • 2 years ago
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    sure *

  8. stephcanie
    • 2 years ago
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    Thanks guys this really helped.

  9. ajprincess
    • 2 years ago
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    When u multiply the second equation by 2 u get 10x-2y=-38. Let us name that as equation (3). The resultant equation u get by multiplying the first equation by 5 is 10x+15y=30. Let us name this equation(4). Subtracting (3) from (4) (4)-(30=> 10x+15y-10x+2y=30-(-38) 17y=68 y=68/17 y=4

  10. ajprincess
    • 2 years ago
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    @jiteshmeghwal9 guess u forgot abt the negative sign in front of 38.

  11. jiteshmeghwal9
    • 2 years ago
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    oops... yeah sorry

  12. ajprincess
    • 2 years ago
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    that's k.:) that happens sometimes to me too.:)

  13. jiteshmeghwal9
    • 2 years ago
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    U really are a very intelligent OS user :)

  14. ajprincess
    • 2 years ago
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    Thanx for the compliment.:)

  15. ajprincess
    • 2 years ago
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    @stephcanie do u get t?

  16. jiteshmeghwal9
    • 2 years ago
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    No need of thanx.... u really deserve it :)

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