## stephcanie 2 years ago Solve the system using elimination. 2x+3y=6 5x-y=-19

1. Lukecrayonz

To eliminate one of the variables, make one of equations have equal variables just negative and positive. To do this, multiply the second equation by 3 to get -y to -3y, but you must multiply the whole equation. 15x-3y=-57 2x+3y=6

2. Lukecrayonz

Add the equations together now! 15x+2x=17x -57+6=-51 17x=-51 x=-3

3. Lukecrayonz

4. jiteshmeghwal9

First equal one of the variable in both of the equations |dw:1352832467734:dw|

5. jiteshmeghwal9

|dw:1352832598245:dw|

6. jiteshmeghwal9

7. jiteshmeghwal9

sure *

8. stephcanie

Thanks guys this really helped.

9. ajprincess

When u multiply the second equation by 2 u get 10x-2y=-38. Let us name that as equation (3). The resultant equation u get by multiplying the first equation by 5 is 10x+15y=30. Let us name this equation(4). Subtracting (3) from (4) (4)-(30=> 10x+15y-10x+2y=30-(-38) 17y=68 y=68/17 y=4

10. ajprincess

@jiteshmeghwal9 guess u forgot abt the negative sign in front of 38.

11. jiteshmeghwal9

oops... yeah sorry

12. ajprincess

that's k.:) that happens sometimes to me too.:)

13. jiteshmeghwal9

U really are a very intelligent OS user :)

14. ajprincess

Thanx for the compliment.:)

15. ajprincess

@stephcanie do u get t?

16. jiteshmeghwal9

No need of thanx.... u really deserve it :)