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pw333125

  • 2 years ago

find derivative: f(x)= ln (3x+1)^4/(2x-1)^3

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  1. irkiz
    • 2 years ago
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    is ln for the entire fraction or just for (3x+1)^4?

  2. irkiz
    • 2 years ago
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    \[\ln \frac{ (3x+1)^{4} }{(2x-1)^{3} } = \ln(3x+1)^{4}- \ln(2x-1)^{3}\]

  3. pw333125
    • 2 years ago
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    yes

  4. irkiz
    • 2 years ago
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    differentiate each one individually in the form of \[\frac{ f'(x) }{ f(x) }\]

  5. irkiz
    • 2 years ago
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    and apply chain rule for each f'(x)

  6. irkiz
    • 2 years ago
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    can you do it now?

  7. pw333125
    • 2 years ago
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    im trying it now....thanks

  8. jishan
    • 2 years ago
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    \[\ln (3x+1)^4/\ln (2x-1)^3= \ln (3x+1)^4-\ln (2x-1)^3= 4*3\ln(3x+1)^3-2*2\ln (2x-1)^2 \]

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