At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
by 2A do you mean 2x?
If that's the case, then your'e going to do arc cos of 4/11, which yields x, then plug that value of x into cos2x
i dnt get ti can you walk me through it
ok so by 2A did you actually mean cos2x?
why dont you simply use this gem of a formulla : cos 2x = (2cos^2 x) - 1 hope this helps..
no it doesnt help CAUSE I DNT KNOW HOW TO DO IT :(
nevermind,,i cant help you further then :/
Ok so use your graphing calculator and there should be a button that's like cos, and right above it you'll see cos^-1. Plug into your calcultar, cos^-1(4/11), because what that's saying is cos of the whatever that is, is going to be 4/11. Now you have x. Now plug whatever you got for x back into your calculator.
Back into the equation cos2x.
wait y am i doin cos-1 instead of cos
because that's how you're going to find x. It's just like how if you had x^2=4, you'd find the square root of both sides. In this case you're getting rid of the cos.
what do i do after
ok, so is that what you're getting for cos^-1(4/11)?
ok you have that value for x, now plug that in for x in cos2x. So plug in cos(2*68.67). That SHOULD be how you do it, I haven't done stuff like this in two years.
so is it a -.7353878608
Yeah uhhhh that should be it, apologies if it isn't though, I don't have a calculator with me.
use to apply cos2x=cos^2x-sin^2x cox=4/11 sinx=squareroot( 1-cos^2x)