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Omniscience
 2 years ago
Best ResponseYou've already chosen the best response.0i integrate it twice; but i dont know why it failed

irkiz
 2 years ago
Best ResponseYou've already chosen the best response.0separate them into tanx and dx

Omniscience
 2 years ago
Best ResponseYou've already chosen the best response.0i did\[(tanx)(x)  \int\limits xsec^{2}dx \]

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0integral sin x /cos x put t= cos x

Omniscience
 2 years ago
Best ResponseYou've already chosen the best response.0i know..but i want to do it by parts

mayankdevnani
 2 years ago
Best ResponseYou've already chosen the best response.0 ln cos x + C proof int tan x dx = int sinx/cos x set u=cosx then we find du=sinx dx substitute du=sin x, u=cos x int sinx/cos x=  int of (1) sin x dx / cosx = int of du/u Solve the integral =  ln u + C substitute back u=cos x =  ln cos x + C

Omniscience
 2 years ago
Best ResponseYou've already chosen the best response.0i know usub i want to do it by parts

mayankdevnani
 2 years ago
Best ResponseYou've already chosen the best response.0i think it will help you!!!

irkiz
 2 years ago
Best ResponseYou've already chosen the best response.0maybe you could try converting tan x to sinx/cosx. then integrate sinxsecx by parts?

irkiz
 2 years ago
Best ResponseYou've already chosen the best response.0wait. is the ans lnsecx?

irkiz
 2 years ago
Best ResponseYou've already chosen the best response.0sec x is (cosx)^1 bring the 1 to the front
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