\[\int tanxdx\] integration by parts

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\[\int tanxdx\] integration by parts

Mathematics
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i integrate it twice; but i dont know why it failed
separate them into tanx and dx
i did\[(tanx)(x) - \int\limits xsec^{2}dx \]

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Other answers:

integral sin x /cos x put t= cos x
i know..but i want to do it by parts
- ln |cos x| + C proof int tan x dx = int sinx/cos x set u=cosx then we find du=-sinx dx substitute du=-sin x, u=cos x int sinx/cos x= - int of (-1) sin x dx / cosx =- int of du/u Solve the integral = - ln |u| + C substitute back u=cos x = - ln |cos x| + C
i know u-sub i want to do it by parts
http://wiki.answers.com/Q/Integration_by_parts_of_x_tanx
i think it will help you!!!
that's \(xtanx\)
oh!!! sorry
maybe you could try converting tan x to sinx/cosx. then integrate sinxsecx by parts?
ok i will try it
wait. is the ans ln|secx|?
-ln(cosx)
looks the same lol
sec x is (cosx)^-1 bring the -1 to the front
yup thats the answer
ok thanks

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