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anu143
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wts d integration of (x^2+a^2)dy/dx=(y+b)(x+sqrt(x^2+a^2))
 one year ago
 one year ago
anu143 Group Title
wts d integration of (x^2+a^2)dy/dx=(y+b)(x+sqrt(x^2+a^2))
 one year ago
 one year ago

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him1618 Group TitleBest ResponseYou've already chosen the best response.0
you need to solve the diff eqn?
 one year ago

anu143 Group TitleBest ResponseYou've already chosen the best response.0
ya by variable separable
 one year ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
x wali sari expressions ek side karlo
 one year ago

anu143 Group TitleBest ResponseYou've already chosen the best response.0
its nt workin :(
 one year ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
you have dy / (y+b) = (x+sqrt(x^2 + a^2))dx / (x^2 + a^2) isnt it?
 one year ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
so now wheres the problem?
 one year ago

anu143 Group TitleBest ResponseYou've already chosen the best response.0
m nt gettin hw 2 go ahead
 one year ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
ok the left hand side is clear to you isnt it??
 one year ago

anu143 Group TitleBest ResponseYou've already chosen the best response.0
yup d right one s mes
 one year ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
so fr the right side break the fraction into 2 parts
 one year ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{x}{x^2 + a^2} + \frac{1}{\sqrt(x^2 + a^2)}\]
 one year ago

anu143 Group TitleBest ResponseYou've already chosen the best response.0
i gt it thanks:)
 one year ago

anu143 Group TitleBest ResponseYou've already chosen the best response.0
can i hav ur id??
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
\[(x^2+a^2)\frac{\text dy}{\text dx}=(y+b)(x+\sqrt{x^2+a^2})\] \[\frac{\text dy}{y+b}=\frac{x+\sqrt{x^2+a^2}}{x^2+a^2}{\text dx}\] \[\int\frac{\text dy}{y+b}=\int\frac{x+\sqrt{x^2+a^2}}{x^2+a^2}{\text dx}\]
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
then uses these standard integrals for \(\alpha,\beta,\gamma\in\mathbb R\) \[\int\frac{\text du}{u+\alpha}=\lnu+\alpha\] \[\int\frac{v}{v^2+\beta^2}\text dv=\frac12\lnv^2+\beta^2\] \[\int\frac1{\sqrt{w^2\pm \gamma^2}}\text dw=2\sqrt{ x\pm\gamma}=\]
 one year ago
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