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anu143
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wts d integration of (x^2+a^2)dy/dx=(y+b)(x+sqrt(x^2+a^2))
 2 years ago
 2 years ago
anu143 Group Title
wts d integration of (x^2+a^2)dy/dx=(y+b)(x+sqrt(x^2+a^2))
 2 years ago
 2 years ago

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him1618 Group TitleBest ResponseYou've already chosen the best response.0
you need to solve the diff eqn?
 2 years ago

anu143 Group TitleBest ResponseYou've already chosen the best response.0
ya by variable separable
 2 years ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
x wali sari expressions ek side karlo
 2 years ago

anu143 Group TitleBest ResponseYou've already chosen the best response.0
its nt workin :(
 2 years ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
you have dy / (y+b) = (x+sqrt(x^2 + a^2))dx / (x^2 + a^2) isnt it?
 2 years ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
so now wheres the problem?
 2 years ago

anu143 Group TitleBest ResponseYou've already chosen the best response.0
m nt gettin hw 2 go ahead
 2 years ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
ok the left hand side is clear to you isnt it??
 2 years ago

anu143 Group TitleBest ResponseYou've already chosen the best response.0
yup d right one s mes
 2 years ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
so fr the right side break the fraction into 2 parts
 2 years ago

him1618 Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{x}{x^2 + a^2} + \frac{1}{\sqrt(x^2 + a^2)}\]
 2 years ago

anu143 Group TitleBest ResponseYou've already chosen the best response.0
i gt it thanks:)
 2 years ago

anu143 Group TitleBest ResponseYou've already chosen the best response.0
can i hav ur id??
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
\[(x^2+a^2)\frac{\text dy}{\text dx}=(y+b)(x+\sqrt{x^2+a^2})\] \[\frac{\text dy}{y+b}=\frac{x+\sqrt{x^2+a^2}}{x^2+a^2}{\text dx}\] \[\int\frac{\text dy}{y+b}=\int\frac{x+\sqrt{x^2+a^2}}{x^2+a^2}{\text dx}\]
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
then uses these standard integrals for \(\alpha,\beta,\gamma\in\mathbb R\) \[\int\frac{\text du}{u+\alpha}=\lnu+\alpha\] \[\int\frac{v}{v^2+\beta^2}\text dv=\frac12\lnv^2+\beta^2\] \[\int\frac1{\sqrt{w^2\pm \gamma^2}}\text dw=2\sqrt{ x\pm\gamma}=\]
 2 years ago
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