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anonymous
 4 years ago
The length of a rectangle is 2 cm greater than the width. The area is 80 cm. Find the length and width.
anonymous
 4 years ago
The length of a rectangle is 2 cm greater than the width. The area is 80 cm. Find the length and width.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0let the width by x cm length= (x+2)cm area = (x+2) times (x) = 80

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0fLength 10cm Width 8 cm Area = Length x Width 80cm(cubed) = 10cm x 8cm

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[(x+2) \times x = 80\] \[x ^{2} + 2x80 = 0\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0solve the equation and get x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0or you could do trial and error like fosterthepeople

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but that would be hard for a larger area in another similar question

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0length x breadth = area

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0did you see how i did it up there?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Irkiz and Fosterthepeople THANKS GUYS! BIG HELP!
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