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frecy
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The length of a rectangle is 2 cm greater than the width. The area is 80 cm. Find the length and width.
 2 years ago
 2 years ago
frecy Group Title
The length of a rectangle is 2 cm greater than the width. The area is 80 cm. Find the length and width.
 2 years ago
 2 years ago

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irkiz Group TitleBest ResponseYou've already chosen the best response.1
let the width by x cm length= (x+2)cm area = (x+2) times (x) = 80
 2 years ago

Fosterthepeople Group TitleBest ResponseYou've already chosen the best response.0
fLength 10cm Width 8 cm Area = Length x Width 80cm(cubed) = 10cm x 8cm
 2 years ago

irkiz Group TitleBest ResponseYou've already chosen the best response.1
\[(x+2) \times x = 80\] \[x ^{2} + 2x80 = 0\]
 2 years ago

irkiz Group TitleBest ResponseYou've already chosen the best response.1
solve the equation and get x
 2 years ago

irkiz Group TitleBest ResponseYou've already chosen the best response.1
or you could do trial and error like fosterthepeople
 2 years ago

irkiz Group TitleBest ResponseYou've already chosen the best response.1
but that would be hard for a larger area in another similar question
 2 years ago

frecy Group TitleBest ResponseYou've already chosen the best response.0
how did you get 80?
 2 years ago

irkiz Group TitleBest ResponseYou've already chosen the best response.1
80 is the area
 2 years ago

irkiz Group TitleBest ResponseYou've already chosen the best response.1
length x breadth = area
 2 years ago

Fosterthepeople Group TitleBest ResponseYou've already chosen the best response.0
did you see how i did it up there?
 2 years ago

frecy Group TitleBest ResponseYou've already chosen the best response.0
Yup, I saw it.
 2 years ago

frecy Group TitleBest ResponseYou've already chosen the best response.0
Irkiz and Fosterthepeople THANKS GUYS! BIG HELP!
 2 years ago

Fosterthepeople Group TitleBest ResponseYou've already chosen the best response.0
no problem :P
 2 years ago
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