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frecy
Group Title
The length of a rectangle is 2 cm greater than the width. The area is 80 cm. Find the length and width.
 one year ago
 one year ago
frecy Group Title
The length of a rectangle is 2 cm greater than the width. The area is 80 cm. Find the length and width.
 one year ago
 one year ago

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irkiz Group TitleBest ResponseYou've already chosen the best response.1
let the width by x cm length= (x+2)cm area = (x+2) times (x) = 80
 one year ago

Fosterthepeople Group TitleBest ResponseYou've already chosen the best response.0
fLength 10cm Width 8 cm Area = Length x Width 80cm(cubed) = 10cm x 8cm
 one year ago

irkiz Group TitleBest ResponseYou've already chosen the best response.1
\[(x+2) \times x = 80\] \[x ^{2} + 2x80 = 0\]
 one year ago

irkiz Group TitleBest ResponseYou've already chosen the best response.1
solve the equation and get x
 one year ago

irkiz Group TitleBest ResponseYou've already chosen the best response.1
or you could do trial and error like fosterthepeople
 one year ago

irkiz Group TitleBest ResponseYou've already chosen the best response.1
but that would be hard for a larger area in another similar question
 one year ago

frecy Group TitleBest ResponseYou've already chosen the best response.0
how did you get 80?
 one year ago

irkiz Group TitleBest ResponseYou've already chosen the best response.1
80 is the area
 one year ago

irkiz Group TitleBest ResponseYou've already chosen the best response.1
length x breadth = area
 one year ago

Fosterthepeople Group TitleBest ResponseYou've already chosen the best response.0
did you see how i did it up there?
 one year ago

frecy Group TitleBest ResponseYou've already chosen the best response.0
Yup, I saw it.
 one year ago

frecy Group TitleBest ResponseYou've already chosen the best response.0
Irkiz and Fosterthepeople THANKS GUYS! BIG HELP!
 one year ago

Fosterthepeople Group TitleBest ResponseYou've already chosen the best response.0
no problem :P
 one year ago
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