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Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.0Lol...@satellite73 r u alright ?

sara1234
 2 years ago
Best ResponseYou've already chosen the best response.0Find sin θ if cot θ = –4 and cos θ < 0.

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1352819529461:dw

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1first we forget about the minus sign, we will worry about that later i just drew a right triangle with the "adjacent side" of 4 and the "opposite side" of 1 because \(\frac{4}{1}=4\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1what is missing is the hypotenuse, and we find that by pythagoras \[h^2=1^2+4^2\] \[h^2=17\] \[h=\sqrt{17}\] now we can finish labelling the triangle

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0\[(sin^2 + cos^2 = 1)/sin^2\] \[1 + cot^2 = csc^2\] \[1 + (4)^2 = csc^2\] \[17 = csc^2\] \[\sqrt{17} = csc\] \[\frac{\sqrt{17}}{17} = sin\]

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0maybe do a + for the sqrt to account for a quadrant

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{1}{\sqrt{17}}=\frac{1}{\sqrt{17}}\times \frac{\sqrt{17}}{\sqrt{17}}=\frac{\sqrt{17}}{17}\]
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