Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

satellite73

  • 3 years ago

find sin(x) if cot(x)=-4

  • This Question is Closed
  1. Yahoo!
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Lol...@satellite73 r u alright ?

  2. sara1234
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Find sin θ if cot θ = –4 and cos θ < 0.

  3. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1352819529461:dw|

  4. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    first we forget about the minus sign, we will worry about that later i just drew a right triangle with the "adjacent side" of 4 and the "opposite side" of 1 because \(\frac{4}{1}=4\)

  5. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what is missing is the hypotenuse, and we find that by pythagoras \[h^2=1^2+4^2\] \[h^2=17\] \[h=\sqrt{17}\] now we can finish labelling the triangle

  6. amistre64
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[(sin^2 + cos^2 = 1)/sin^2\] \[1 + cot^2 = csc^2\] \[1 + (-4)^2 = csc^2\] \[17 = csc^2\] \[\sqrt{17} = csc\] \[\frac{\sqrt{17}}{17} = sin\]

  7. amistre64
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    maybe do a +- for the sqrt to account for a quadrant

  8. anonymous
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\frac{1}{\sqrt{17}}=\frac{1}{\sqrt{17}}\times \frac{\sqrt{17}}{\sqrt{17}}=\frac{\sqrt{17}}{17}\]

  9. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy