anonymous
  • anonymous
Can someone help me please? Rewrite with only sin x and cos x. cos 2x + sin x
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Schrodinger
  • Schrodinger
Okay. So this stems from trigonometric identities and double angle formulas. Do you know any double angle formulas?
anonymous
  • anonymous
Not really, no. Sorry
Schrodinger
  • Schrodinger
No prolem. A really good reference for all of these formulas would be this: (one minute.)

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Schrodinger
  • Schrodinger
*No problem. Anyways, here's the webpage with pretty much every possible identity you can imagine for Trig. http://www.sosmath.com/trig/Trig5/trig5/trig5.html You'll notice that under the double angle formulas section, Cos(2x) has three different accompanying equations. Can I ask what math you're in right now, i'm assuming Precalc?
anonymous
  • anonymous
You are correct, I'm in precalc. And thanks for the link btw. That is awesome.
Schrodinger
  • Schrodinger
\[\cos(2x) = \cos ^{2}(x) - \sin ^{2}(x)\]\[\cos(2x) = 2\cos ^{2}(x)-1\]\[\cos(2x) = 1 - 2\sin ^{2}(x)\]
Schrodinger
  • Schrodinger
No problem. Okay, given these formulas, we can substitute cos(2x) for other things without double angles. Right now, we've got \[\cos(2x) + \sin(x)\], correct?
anonymous
  • anonymous
Yes
Schrodinger
  • Schrodinger
(Sorry for asking something you obviously know the answer to, just giving myself time to think LOL. I haven't done this in a while.)
anonymous
  • anonymous
No you're doing great. You're helping me way more than anyone has thus far. Take all the time you need I really appreciate your helping me out man.
Schrodinger
  • Schrodinger
No worries. I'm a little confused about the vague instructions. While you can rewrite it with those terms, i'm wondering if it's acceptable to have only sine, only cosine, or whether cosine or sine squared is acceptable. After all, that is basically what these are. Guess every case might be worked out.
anonymous
  • anonymous
If it helps, the possible answers are: 1 + 3 sin x 1 + 3 sin2x 1 - 2 sin2x + sin x 1 + 2 sin2x + sin x
anonymous
  • anonymous
The last 3 are (sin^2 x) btw
Schrodinger
  • Schrodinger
Oh, lol, okay then. That's WAY simpler than what I was about to do. My bad, I was like, half-trying to solve a trig identity. So yeah, just take a look at the formulas I put up, and substitute them. From there it's super easy to see which one makes sense with the possible answers.
Schrodinger
  • Schrodinger
Don't try to solve anything, just see which substitution would get you closest to the answers given. It should be a single step.
Schrodinger
  • Schrodinger
You follow?
anonymous
  • anonymous
I think so. So the answer would just be 1 - 2 sin2x + sin x
Schrodinger
  • Schrodinger
Exactly, but I have to say, don't be afraid of using the carat symbol (^) if you're ever writing something on a computer and can't put in a fancy superscript like: \[\sin ^{2}x\] to denote when a value is squared. People could very, very easily misread it as sin(2x) instead of sin^2(x), and that could mess up a whole problem.
anonymous
  • anonymous
Thanks for the tip and all your help. I can't thank you enough.
Schrodinger
  • Schrodinger
No problem. Good luck with Precalc. I struggled a lot with it when I first learned it.
Schrodinger
  • Schrodinger
(Heck, i'm still learning it, albeit different forms.)
anonymous
  • anonymous
Haha. I guess it never really ends does it?
Schrodinger
  • Schrodinger
Nope. We're dumb forever. :P PS, I don't know if this would apply to you, but do you use flash cards to study?
anonymous
  • anonymous
sometimes. I guess it depends on what I am studying. If there are a lot of vocabulary words or something I will usually use flashcards.

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