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weekskeith15

  • 3 years ago

Which is the equation of the line with slope 3 that contains point (-1, 5)? y – 5 = 3(x + 1) y – 1 = 3(x + 5) y – 1 = 3(x – 5) y – 5 = 3(x - 1)

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  1. privetek
    • 3 years ago
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    x=5, y=-1, m=3 \[y-y _{1}=m(x-x _{1})\] y-5 = 3(x-(-1)) y-5 = 3(x+1)

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