anonymous
  • anonymous
√6x + 5 = √53
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
to remove the x from under the square root sign you must involve the inverse function, the square. isolate the x on the left and square both sides: \[(\sqrt{6x})^2=(\sqrt{53}-5)^2\] the terms being squared on the right are treated as FOIL
anonymous
  • anonymous
take the constant 5 to the right side and then square both sides to get x
anonymous
  • anonymous
http://cdn.memegenerator.net/instances/400x/24188597.jpg

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anonymous
  • anonymous
x=+-\[sqr{ 78-10\sqrt{53}}/6\]
anonymous
  • anonymous
taking the constant to right side and squaring both sides we get
anonymous
  • anonymous
|dw:1352829871837:dw|
anonymous
  • anonymous
As in ur question if a√=b√ Then it means that a=b so as in ur question 6x+5=53. solve now
anonymous
  • anonymous
6x+5=53. to get X

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