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tadhanala

  • 2 years ago

√6x + 5 = √53

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  1. Mathmuse
    • 2 years ago
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    to remove the x from under the square root sign you must involve the inverse function, the square. isolate the x on the left and square both sides: \[(\sqrt{6x})^2=(\sqrt{53}-5)^2\] the terms being squared on the right are treated as FOIL

  2. 03453660
    • 2 years ago
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    take the constant 5 to the right side and then square both sides to get x

  3. tadhanala
    • 2 years ago
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    http://cdn.memegenerator.net/instances/400x/24188597.jpg

  4. jishan
    • 2 years ago
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    x=+-\[sqr{ 78-10\sqrt{53}}/6\]

  5. 03453660
    • 2 years ago
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    taking the constant to right side and squaring both sides we get

  6. 03453660
    • 2 years ago
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    |dw:1352829871837:dw|

  7. anas2000
    • 2 years ago
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    As in ur question if a√=b√ Then it means that a=b so as in ur question 6x+5=53. solve now

  8. anas2000
    • 2 years ago
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    6x+5=53. to get X

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