## tadhanala Group Title √6x + 5 = √53 2 years ago 2 years ago

1. Mathmuse

to remove the x from under the square root sign you must involve the inverse function, the square. isolate the x on the left and square both sides: $(\sqrt{6x})^2=(\sqrt{53}-5)^2$ the terms being squared on the right are treated as FOIL

2. 03453660

take the constant 5 to the right side and then square both sides to get x

4. jishan

x=+-$sqr{ 78-10\sqrt{53}}/6$

5. 03453660

taking the constant to right side and squaring both sides we get

6. 03453660

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7. anas2000

As in ur question if a√=b√ Then it means that a=b so as in ur question 6x+5=53. solve now

8. anas2000

6x+5=53. to get X