Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

tadhanala

  • 3 years ago

√6x + 5 = √53

  • This Question is Closed
  1. Mathmuse
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    to remove the x from under the square root sign you must involve the inverse function, the square. isolate the x on the left and square both sides: \[(\sqrt{6x})^2=(\sqrt{53}-5)^2\] the terms being squared on the right are treated as FOIL

  2. 03453660
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    take the constant 5 to the right side and then square both sides to get x

  3. tadhanala
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    http://cdn.memegenerator.net/instances/400x/24188597.jpg

  4. jishan
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    x=+-\[sqr{ 78-10\sqrt{53}}/6\]

  5. 03453660
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    taking the constant to right side and squaring both sides we get

  6. 03453660
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1352829871837:dw|

  7. anas2000
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    As in ur question if a√=b√ Then it means that a=b so as in ur question 6x+5=53. solve now

  8. anas2000
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    6x+5=53. to get X

  9. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy