## anonymous 3 years ago √6x + 5 = √53

1. anonymous

to remove the x from under the square root sign you must involve the inverse function, the square. isolate the x on the left and square both sides: $(\sqrt{6x})^2=(\sqrt{53}-5)^2$ the terms being squared on the right are treated as FOIL

2. anonymous

take the constant 5 to the right side and then square both sides to get x

3. anonymous
4. anonymous

x=+-$sqr{ 78-10\sqrt{53}}/6$

5. anonymous

taking the constant to right side and squaring both sides we get

6. anonymous

|dw:1352829871837:dw|

7. anonymous

As in ur question if a√=b√ Then it means that a=b so as in ur question 6x+5=53. solve now

8. anonymous

6x+5=53. to get X