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tadhanala
 2 years ago
√6x + 5 = √53
tadhanala
 2 years ago
√6x + 5 = √53

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Mathmuse
 2 years ago
Best ResponseYou've already chosen the best response.2to remove the x from under the square root sign you must involve the inverse function, the square. isolate the x on the left and square both sides: \[(\sqrt{6x})^2=(\sqrt{53}5)^2\] the terms being squared on the right are treated as FOIL

03453660
 2 years ago
Best ResponseYou've already chosen the best response.0take the constant 5 to the right side and then square both sides to get x

jishan
 2 years ago
Best ResponseYou've already chosen the best response.0x=+\[sqr{ 7810\sqrt{53}}/6\]

03453660
 2 years ago
Best ResponseYou've already chosen the best response.0taking the constant to right side and squaring both sides we get

anas2000
 2 years ago
Best ResponseYou've already chosen the best response.0As in ur question if a√=b√ Then it means that a=b so as in ur question 6x+5=53. solve now
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