anonymous
  • anonymous
do I use sin, tan, cos for this?
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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anonymous
  • anonymous
cos
anonymous
  • anonymous
because the opposite is not defined you cant use sine, but you have adjacent and the hypotnuse which means you can use cosine
anonymous
  • anonymous
yep

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nubeer
  • nubeer
nop its base/hyp
anonymous
  • anonymous
but you dont have the base therefore you must use cosine
nubeer
  • nubeer
so it should be 2.28/4.07
nubeer
  • nubeer
well i think thats the way it should be done.. maybe you can ask someone else to confirm it.
nubeer
  • nubeer
well no cos function will be use.. adjacent = 2.28 , hyp =4.07
nubeer
  • nubeer
yes.
anonymous
  • anonymous
yes, so you cant do sine because it requires you use adjacent
nubeer
  • nubeer
lol no.. its cosine.
nubeer
  • nubeer
Some People Have Curly Brown Hair Through Proper Brushing. now just look first letter of each word. S=sin, P= perpendicular, H= Hyp, C=Cos , B= bAse, T=tan
nubeer
  • nubeer
|dw:1352832846895:dw|
nubeer
  • nubeer
that is a formula for making things easy.. mean when u use sin=perp/hyp cos= base /hyp , tan =perp/base
nubeer
  • nubeer
base and hypotaneous will be the sides with angle.. and perpendicular is the side opposite of the angle on which we are working.
nubeer
  • nubeer
|dw:1352832995681:dw| if we are working on this mark angle then your Hyp base and perp will be this.
nubeer
  • nubeer
|dw:1352833051199:dw| if you are working on this angle then your hyp base and perp are this.
nubeer
  • nubeer
hahah lol i am not crazy :P and yes thats an easy way to remember sides we have to take with cos sin and tan..
anonymous
  • anonymous
Not yet... 0.560 that is the cosine of Angle A. Now you need to use "Inverse Cosine" to get angle A.
anonymous
  • anonymous
do you have calculator? I am using the windows calculator... it has a button called "Inv" (for inverse), so I hit that button, then the "cosine" button. Actually, when I hit "Inv", then my cosine button turns to cos^-1 like: \[\cos ^{-1}\]
anonymous
  • anonymous
cosine = a/c
anonymous
  • anonymous
Yes, that's exactly right :) Nice work.
anonymous
  • anonymous
If you have an angle, you can use the sine, cosine, and tangent ratios to solve for a missing side. If you don't have an angle shown, but you do have side lengths shown, you can use the same ratios, but then with inverse cosine, inverse sine, or inverse tangent to solve for the missing angle.

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