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anlnt4

  • 3 years ago

Write the equation of the tangent line to the curve y = ln (2/e^2x) at the point (0, ln2).

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  1. anonymous
    • 3 years ago
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    it is really \[\ln(\frac{2}{e^2})\]??

  2. Algebraic!
    • 3 years ago
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    heh.

  3. Algebraic!
    • 3 years ago
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    it's a line... so I doubt it.

  4. anonymous
    • 3 years ago
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    \[\ln(\frac{2}{e^{2x}})\] right?

  5. anonymous
    • 3 years ago
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    it is a line

  6. anonymous
    • 3 years ago
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    \[\ln(\frac{2}{e^{2x}})=\ln(2)-\ln(e^{2x})=\ln(2)-2x\]

  7. anonymous
    • 3 years ago
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    line with slope \(-2\) and \(y\) intercept \(\ln(2)\) so whatever you do , do not use any calculus

  8. anlnt4
    • 3 years ago
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    This!

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