anonymous
  • anonymous
Write the equation of the tangent line to the curve y = ln (2/e^2x) at the point (0, ln2).
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
it is really \[\ln(\frac{2}{e^2})\]??
anonymous
  • anonymous
heh.
anonymous
  • anonymous
it's a line... so I doubt it.

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anonymous
  • anonymous
\[\ln(\frac{2}{e^{2x}})\] right?
anonymous
  • anonymous
it is a line
anonymous
  • anonymous
\[\ln(\frac{2}{e^{2x}})=\ln(2)-\ln(e^{2x})=\ln(2)-2x\]
anonymous
  • anonymous
line with slope \(-2\) and \(y\) intercept \(\ln(2)\) so whatever you do , do not use any calculus
anonymous
  • anonymous

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