anlnt4
Write the equation of the tangent line to the curve y = ln (2/e^2x) at the point (0, ln2).



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anonymous
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it is really
\[\ln(\frac{2}{e^2})\]??

Algebraic!
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heh.

Algebraic!
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it's a line... so I doubt it.

anonymous
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\[\ln(\frac{2}{e^{2x}})\] right?

anonymous
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it is a line

anonymous
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\[\ln(\frac{2}{e^{2x}})=\ln(2)\ln(e^{2x})=\ln(2)2x\]

anonymous
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line with slope \(2\) and \(y\) intercept \(\ln(2)\) so whatever you do , do not use any calculus

anlnt4
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This!