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anlnt4
 2 years ago
Write the equation of the tangent line to the curve y = ln (2/e^2x) at the point (0, ln2).
anlnt4
 2 years ago
Write the equation of the tangent line to the curve y = ln (2/e^2x) at the point (0, ln2).

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satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1it is really \[\ln(\frac{2}{e^2})\]??

Algebraic!
 2 years ago
Best ResponseYou've already chosen the best response.1it's a line... so I doubt it.

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1\[\ln(\frac{2}{e^{2x}})\] right?

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1\[\ln(\frac{2}{e^{2x}})=\ln(2)\ln(e^{2x})=\ln(2)2x\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1line with slope \(2\) and \(y\) intercept \(\ln(2)\) so whatever you do , do not use any calculus
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