## anonymous 3 years ago Write the equation of the tangent line to the curve y = ln (2/e^2x) at the point (0, ln2).

1. anonymous

it is really $\ln(\frac{2}{e^2})$??

2. anonymous

heh.

3. anonymous

it's a line... so I doubt it.

4. anonymous

$\ln(\frac{2}{e^{2x}})$ right?

5. anonymous

it is a line

6. anonymous

$\ln(\frac{2}{e^{2x}})=\ln(2)-\ln(e^{2x})=\ln(2)-2x$

7. anonymous

line with slope $$-2$$ and $$y$$ intercept $$\ln(2)$$ so whatever you do , do not use any calculus

8. anonymous

This!