## anlnt4 Group Title Write the equation of the tangent line to the curve y = ln (2/e^2x) at the point (0, ln2). one year ago one year ago

1. satellite73 Group Title

it is really $\ln(\frac{2}{e^2})$??

2. Algebraic! Group Title

heh.

3. Algebraic! Group Title

it's a line... so I doubt it.

4. satellite73 Group Title

$\ln(\frac{2}{e^{2x}})$ right?

5. satellite73 Group Title

it is a line

6. satellite73 Group Title

$\ln(\frac{2}{e^{2x}})=\ln(2)-\ln(e^{2x})=\ln(2)-2x$

7. satellite73 Group Title

line with slope $$-2$$ and $$y$$ intercept $$\ln(2)$$ so whatever you do , do not use any calculus

8. anlnt4 Group Title

This!