I have a question about breathing gas underwater. Here goes: As we go down, the quantity of gas breathed increases (because the pressure goes up) So for a diver that's going down at a speed of 18m/min until he reaches 60 meters underwater (It would take him 3 minutes and 20 seconds to do so). How would I calculate the amount of gas he's breathing during this 3 minutes and 20 seconds, knowing that the atmospheric pressure is 100kPa and the water's temperature is about 20C and that he's breathing rhythm is about 18L of gas per minute?

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I tried to calculate the average amount of gas breathed by using the quantity of air breathed every minute before the dive and the quantity of air breathed every minute 60 meters underwater. At 0m, I could use the perfect gas formula, PV=nRT, where P = 100kPa; V = 18L; n = ?; T = 293K\[n = (\frac{100*18}{8.314*293})=0.73mol\]At 60m, P = 700kPa; V=18L; n=?; T=293K\[n=\frac{700*18}{8.314*293}=5.17mol\]and calculate the average, is that a good way to do it? (\(Average =(5.17+0.73) /2=2.95mol/minute\\2.95mol/minute*3.33 minutes =3.94mol\))

@TuringTest

Do you know if my work is correct for this kind of situation?

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