Here's the question you clicked on:
heathernelly
awesomeeee.
IS there anything in front of the 3 ?
Or is the question asking the cube root?
Ok so, take this step by step. If you have ^3√24a^10b^6 , start with 24 first. Find a perfect cubed number in 24. Do you know what it is ?
no :/ im really bad at math:(
A perfect cubed number is anything that has the same 3 numbers multiplied. For example, 3*3*3= 27 so 27 is a perfectly cubed number. If you had the number 54, you would look for factors of 54 that would have a perfect cubed number. So factors of 54 are (1, 2, 3, 6, 9, 18, 27, 54) So if you looked through the numbers, you would see that 27 is the perfect cubed number. So, back to the question, go through the factors of 24 and see what number has 3 of the same numbers multiplied to get that number.
6, 2, 3, 4, 24, 1, 12, 8?
No... The factors of 24 are (1, 2, 3, 4, 6, 8, 12, 24) .... Now I told you that 3*3*3=27 so it has to be lower. So do 2*2*2 .. That = 8. 8 is a factor of 24 and it is a perfect square.
So, 24 would break into 8 * 3. The 8 will come out of the cube root as 2 ( because 2*2*2=8) leaving you with the 3 in the inside of the cube root.
so you would have 2, ^3√3a^10 b^6 ... get it?
wait, why did you chose 8? :/ like how do you know if its a perfect square?
ohhh, get it now! your awesome!
Sorry, i meant perfect cube root. What you should do is pull up a list of perfect cube roots. I'll give you the first 10. 13 = 1 23 = 8 33 = 27 43 = 64 53 = 125 63 = 216 73 = 343 83 = 512 93 = 729 103 = 1000
thank you soo much :D!!
Ok wait , we're not done!
and the formulas i gave, it is not 13, 23, 33, in the first column. it is supposed to read 1^3, 2^3, 3^3, etc
So now we have to move on to a^10. How many times does 3 go in evenly to 10? (this is because you have ^3√a^10
When it comes to exponents for letters, you divide normally instead of trying to find the cube root. Example : ^3√a^7 ... 3 would go into 7 twice so you would have a^6 come out with ^3√a left inside. = a^6, ^3√a
sorry sorry a^2 come out with ^3√a in the inside***
So, for ^3√a^10 , how many times does 3 go into 10?
that kinda confused me, 3 times r 1? im not sure
3 will go into 10 , 3 times. (3*3 is 9.) .... So a^3 will come out and merge with the 2 from earlier making it 2a^3 and the last a (since only 9 were taken out) will stay inside. So, so far, we have 2a^3 ^3√3a b^6
it's actually making more sense now, like as we go on :D!
So, then can you figure out what to do for ^3 √b^6