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heathernelly Group Title

awesomeeee.

  • 2 years ago
  • 2 years ago

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  1. chahnatailor Group Title
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    IS there anything in front of the 3 ?

    • 2 years ago
  2. chahnatailor Group Title
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    Or is the question asking the cube root?

    • 2 years ago
  3. heathernelly Group Title
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    yeah cube root (:

    • 2 years ago
  4. chahnatailor Group Title
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    Ok so, take this step by step. If you have ^3√24a^10b^6 , start with 24 first. Find a perfect cubed number in 24. Do you know what it is ?

    • 2 years ago
  5. heathernelly Group Title
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    no :/ im really bad at math:(

    • 2 years ago
  6. chahnatailor Group Title
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    A perfect cubed number is anything that has the same 3 numbers multiplied. For example, 3*3*3= 27 so 27 is a perfectly cubed number. If you had the number 54, you would look for factors of 54 that would have a perfect cubed number. So factors of 54 are (1, 2, 3, 6, 9, 18, 27, 54) So if you looked through the numbers, you would see that 27 is the perfect cubed number. So, back to the question, go through the factors of 24 and see what number has 3 of the same numbers multiplied to get that number.

    • 2 years ago
  7. heathernelly Group Title
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    3?

    • 2 years ago
  8. heathernelly Group Title
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    6, 2, 3, 4, 24, 1, 12, 8?

    • 2 years ago
  9. chahnatailor Group Title
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    No... The factors of 24 are (1, 2, 3, 4, 6, 8, 12, 24) .... Now I told you that 3*3*3=27 so it has to be lower. So do 2*2*2 .. That = 8. 8 is a factor of 24 and it is a perfect square.

    • 2 years ago
  10. chahnatailor Group Title
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    So, 24 would break into 8 * 3. The 8 will come out of the cube root as 2 ( because 2*2*2=8) leaving you with the 3 in the inside of the cube root.

    • 2 years ago
  11. chahnatailor Group Title
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    so you would have 2, ^3√3a^10 b^6 ... get it?

    • 2 years ago
  12. heathernelly Group Title
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    wait, why did you chose 8? :/ like how do you know if its a perfect square?

    • 2 years ago
  13. heathernelly Group Title
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    ohhh, get it now! your awesome!

    • 2 years ago
  14. chahnatailor Group Title
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    Sorry, i meant perfect cube root. What you should do is pull up a list of perfect cube roots. I'll give you the first 10. 13 = 1 23 = 8 33 = 27 43 = 64 53 = 125 63 = 216 73 = 343 83 = 512 93 = 729 103 = 1000

    • 2 years ago
  15. heathernelly Group Title
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    thank you soo much :D!!

    • 2 years ago
  16. chahnatailor Group Title
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    Ok wait , we're not done!

    • 2 years ago
  17. chahnatailor Group Title
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    and the formulas i gave, it is not 13, 23, 33, in the first column. it is supposed to read 1^3, 2^3, 3^3, etc

    • 2 years ago
  18. chahnatailor Group Title
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    So now we have to move on to a^10. How many times does 3 go in evenly to 10? (this is because you have ^3√a^10

    • 2 years ago
  19. heathernelly Group Title
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    2?

    • 2 years ago
  20. chahnatailor Group Title
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    When it comes to exponents for letters, you divide normally instead of trying to find the cube root. Example : ^3√a^7 ... 3 would go into 7 twice so you would have a^6 come out with ^3√a left inside. = a^6, ^3√a

    • 2 years ago
  21. chahnatailor Group Title
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    sorry sorry a^2 come out with ^3√a in the inside***

    • 2 years ago
  22. chahnatailor Group Title
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    = a^2, ^3√a

    • 2 years ago
  23. chahnatailor Group Title
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    So, for ^3√a^10 , how many times does 3 go into 10?

    • 2 years ago
  24. heathernelly Group Title
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    that kinda confused me, 3 times r 1? im not sure

    • 2 years ago
  25. chahnatailor Group Title
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    3 will go into 10 , 3 times. (3*3 is 9.) .... So a^3 will come out and merge with the 2 from earlier making it 2a^3 and the last a (since only 9 were taken out) will stay inside. So, so far, we have 2a^3 ^3√3a b^6

    • 2 years ago
  26. heathernelly Group Title
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    ohh! got you

    • 2 years ago
  27. heathernelly Group Title
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    it's actually making more sense now, like as we go on :D!

    • 2 years ago
  28. chahnatailor Group Title
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    So, then can you figure out what to do for ^3 √b^6

    • 2 years ago
  29. heathernelly Group Title
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    yess, tyy!

    • 2 years ago
  30. chahnatailor Group Title
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    glad to help :)

    • 2 years ago
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