awesomeeee.

- anonymous

awesomeeee.

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- schrodinger

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- anonymous

IS there anything in front of the 3 ?

- anonymous

Or is the question asking the cube root?

- anonymous

yeah cube root (:

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## More answers

- anonymous

Ok so, take this step by step. If you have ^3√24a^10b^6 , start with 24 first. Find a perfect cubed number in 24. Do you know what it is ?

- anonymous

no :/ im really bad at math:(

- anonymous

A perfect cubed number is anything that has the same 3 numbers multiplied. For example, 3*3*3= 27 so 27 is a perfectly cubed number.
If you had the number 54, you would look for factors of 54 that would have a perfect cubed number.
So factors of 54 are (1, 2, 3, 6, 9, 18, 27, 54)
So if you looked through the numbers, you would see that 27 is the perfect cubed number.
So, back to the question, go through the factors of 24 and see what number has 3 of the same numbers multiplied to get that number.

- anonymous

3?

- anonymous

6, 2, 3, 4, 24, 1, 12, 8?

- anonymous

No... The factors of 24 are (1, 2, 3, 4, 6, 8, 12, 24) .... Now I told you that 3*3*3=27 so it has to be lower. So do 2*2*2 .. That = 8. 8 is a factor of 24 and it is a perfect square.

- anonymous

So, 24 would break into 8 * 3. The 8 will come out of the cube root as 2 ( because 2*2*2=8) leaving you with the 3 in the inside of the cube root.

- anonymous

so you would have 2, ^3√3a^10 b^6
... get it?

- anonymous

wait, why did you chose 8? :/ like how do you know if its a perfect square?

- anonymous

ohhh, get it now! your awesome!

- anonymous

Sorry, i meant perfect cube root. What you should do is pull up a list of perfect cube roots. I'll give you the first 10.
13 = 1
23 = 8
33 = 27
43 = 64
53 = 125
63 = 216
73 = 343
83 = 512
93 = 729
103 = 1000

- anonymous

thank you soo much :D!!

- anonymous

Ok wait , we're not done!

- anonymous

and the formulas i gave, it is not 13, 23, 33, in the first column. it is supposed to read 1^3, 2^3, 3^3, etc

- anonymous

So now we have to move on to a^10. How many times does 3 go in evenly to 10? (this is because you have ^3√a^10

- anonymous

2?

- anonymous

When it comes to exponents for letters, you divide normally instead of trying to find the cube root. Example : ^3√a^7 ... 3 would go into 7 twice so you would have a^6 come out with ^3√a left inside. = a^6, ^3√a

- anonymous

sorry sorry a^2 come out with ^3√a in the inside***

- anonymous

= a^2, ^3√a

- anonymous

So, for ^3√a^10 , how many times does 3 go into 10?

- anonymous

that kinda confused me, 3 times r 1? im not sure

- anonymous

3 will go into 10 , 3 times. (3*3 is 9.)
.... So a^3 will come out and merge with the 2 from earlier making it 2a^3 and the last a (since only 9 were taken out) will stay inside.
So, so far, we have 2a^3 ^3√3a b^6

- anonymous

ohh! got you

- anonymous

it's actually making more sense now, like as we go on :D!

- anonymous

So, then can you figure out what to do for ^3 √b^6

- anonymous

yess, tyy!

- anonymous

glad to help :)

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