Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Verify the following identity:

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

|dw:1352855287144:dw|
is that:\[\frac{ \cos(x) }{ 1 + \sin(x) }+ \frac{ 1 + \sin(x) }{ \cos(x) } = 2\sec(x)\]? (Just making sure.)
Yes, that's exactly right

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Okay. The way I was taught in general to solve problems like this is always to take the more complex side, which was generally the one with two terms, and then work towards the side with less. That being said, (one second.)
I guess what you could first do it multiply both of your numerators and denominators by the opposite denominator to make sure both numerators can be dealt with. e.g.: \[\frac{ \cos(x) }{1+\sin(x) }+\frac{ 1+\sin(x) }{\cos(x) }=2\sec(x)\]...\[\frac{ (cosx)(cosx) + (1+sinx)(1+sinx) }{(1+sinx)(cosx)}\]...\[\frac{ \cos ^{2}x + \sin ^{2}x +2sinx+1 }{ sinxcosx + cosx }\]From here, \[\sin ^{2}x+\cos ^{2}x\]can be simplified to 1. Follow so far?
Ok... I think I get it What comes next?
Sorry, multitasking. Well, let's make sure you do. Is there anything, ANYTHING at all you don't understand? I'm not your math teacher, and you're not in a classroom, don't be afraid to ask if you don't get something.

Not the answer you are looking for?

Search for more explanations.

Ask your own question