Here's the question you clicked on:
ballerinaxbb
Verify the following identity:
|dw:1352855287144:dw|
is that:\[\frac{ \cos(x) }{ 1 + \sin(x) }+ \frac{ 1 + \sin(x) }{ \cos(x) } = 2\sec(x)\]? (Just making sure.)
Yes, that's exactly right
Okay. The way I was taught in general to solve problems like this is always to take the more complex side, which was generally the one with two terms, and then work towards the side with less. That being said, (one second.)
I guess what you could first do it multiply both of your numerators and denominators by the opposite denominator to make sure both numerators can be dealt with. e.g.: \[\frac{ \cos(x) }{1+\sin(x) }+\frac{ 1+\sin(x) }{\cos(x) }=2\sec(x)\]...\[\frac{ (cosx)(cosx) + (1+sinx)(1+sinx) }{(1+sinx)(cosx)}\]...\[\frac{ \cos ^{2}x + \sin ^{2}x +2sinx+1 }{ sinxcosx + cosx }\]From here, \[\sin ^{2}x+\cos ^{2}x\]can be simplified to 1. Follow so far?
Ok... I think I get it What comes next?
Sorry, multitasking. Well, let's make sure you do. Is there anything, ANYTHING at all you don't understand? I'm not your math teacher, and you're not in a classroom, don't be afraid to ask if you don't get something.