anonymous
  • anonymous
Major MATH HELP! D: ** Pic included!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
Help? :(
anonymous
  • anonymous
wat

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anonymous
  • anonymous
I need some help with this problem
anonymous
  • anonymous
ok
anonymous
  • anonymous
wats ur answer
anonymous
  • anonymous
I dont have onne, I need help :| I attached a link of the problem
anonymous
  • anonymous
i did
anonymous
  • anonymous
hold on
anonymous
  • anonymous
thnx (:
anonymous
  • anonymous
Do you still need help?
anonymous
  • anonymous
Yes please (:
anonymous
  • anonymous
ya
anonymous
  • anonymous
Okay, Do you know how to even start working on this problem?
anonymous
  • anonymous
No :C
anonymous
  • anonymous
So are you working with vectors?
anonymous
  • anonymous
indeed I am!
anonymous
  • anonymous
Im just tottally lost on this problem
anonymous
  • anonymous
Ok, so have you done vector proofs before?
anonymous
  • anonymous
no neverO=
anonymous
  • anonymous
ok, so ob+ba=oa
anonymous
  • anonymous
0=(0,0) A=(x1,y1) B=(x2,y2)
anonymous
  • anonymous
Vector BA=A-B=(x1-x2, y1-y2)
anonymous
  • anonymous
okk
anonymous
  • anonymous
Good so far?
anonymous
  • anonymous
All what you have to do now is find vecotor OA and vecotr OB
anonymous
  • anonymous
O: oh really but is there like another pic you have to draw/
anonymous
  • anonymous
no
anonymous
  • anonymous
oh cool
anonymous
  • anonymous
|dw:1352869007184:dw|
anonymous
  • anonymous
so vector BA is equal to A-B so when you subtract the points element-wise you get x1-x2 and y1-y2
anonymous
  • anonymous
|dw:1352869116355:dw|
anonymous
  • anonymous
Oh right, now I find Oa Ob ?How can I do thta again?
anonymous
  • anonymous
|dw:1352869175679:dw|
anonymous
  • anonymous
now you do the same for vector ob
anonymous
  • anonymous
|dw:1352869297947:dw|
anonymous
  • anonymous
So OB is OB = O-B= <0-x2 , 0-y2 > ?
anonymous
  • anonymous
no, it would be = B-O =
anonymous
  • anonymous
So, now you need to subtract from . to prove that it equals
anonymous
  • anonymous
ohhh right!
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
look at the attachment, the circled ones.
anonymous
  • anonymous
How would you prove the?
anonymous
  • anonymous
*them?
anonymous
  • anonymous
They are equal.
anonymous
  • anonymous
so, by the subtraction of the vectors, you prove that = -
anonymous
  • anonymous
OH theyre equal!! Its < x1-x2 , y1-y2 > !
anonymous
  • anonymous
pretty much.
anonymous
  • anonymous
Now to solve part 2, set point c equal to (x3, y3)
anonymous
  • anonymous
then I would solve for x3,y3 in terms of the other known quantities, x1,y1 and x2,y2 using the given ratio. the rest is just algebra.
anonymous
  • anonymous
So all what xOA is saying is to ditribute the x?
anonymous
  • anonymous
Ya
anonymous
  • anonymous
Oh okay yy
anonymous
  • anonymous
|dw:1352870110521:dw|
anonymous
  • anonymous
right?
anonymous
  • anonymous
yes.
anonymous
  • anonymous
Cool thanks ((:
hartnn
  • hartnn
=C-O
hartnn
  • hartnn
/ =x/y so, (C-B)/(A-C) =x/y now can, you isolate C from here ? try it...
anonymous
  • anonymous
you want me to isolare c from (C-B)/(A-C) =x/y right?
hartnn
  • hartnn
yes,
hartnn
  • hartnn
u see, how i got, (C-B)/(A-C) =x/y from given condition, / =x/y
anonymous
  • anonymous
Wait how would you do that because C is being subtracted
hartnn
  • hartnn
u mean how to isolate C ? cross-multiply....
anonymous
  • anonymous
yea youd get y(c-b) = x(a-c) ...
hartnn
  • hartnn
try to isolate C from that...
anonymous
  • anonymous
so I distribute..first then
anonymous
  • anonymous
yc-cb = xa - xc
hartnn
  • hartnn
yes, distribute then bring all terms with 'c' together, then factor out c
hartnn
  • hartnn
its yc-yb on the left...
anonymous
  • anonymous
So C= xa-xc / (y-b)
hartnn
  • hartnn
there, u were not able to isolate C, notice, c is there on right side also
hartnn
  • hartnn
yc-yb = xa - xc yc+xc = xa+yb got this step ?
hartnn
  • hartnn
now can u isolate c ?
anonymous
  • anonymous
I thought ititd be yc-cb = xa - xc since u cross mult tho..
anonymous
  • anonymous
|dw:1352871594989:dw|
hartnn
  • hartnn
|dw:1352871643318:dw|
anonymous
  • anonymous
right x)
hartnn
  • hartnn
|dw:1352871704757:dw|
anonymous
  • anonymous
yesyes i did that xD
hartnn
  • hartnn
what does left side simplify to ?
hartnn
  • hartnn
knowing that its given that x+y=1
anonymous
  • anonymous
C= xa+yb / y+x
hartnn
  • hartnn
what is x+y= ?
anonymous
  • anonymous
Wait but does C equal to that O:
hartnn
  • hartnn
yes.
anonymous
  • anonymous
oh okay lol Um y+x = .. ?
hartnn
  • hartnn
its given to be =1 see the question
anonymous
  • anonymous
Oh cool so it would just be xa+yb
hartnn
  • hartnn
yes, c=xa+yb now u know what to do next ?
anonymous
  • anonymous
PLug it to...
hartnn
  • hartnn
we know that C=(x3,y3) and O=(0,0) so can you find = ?
anonymous
  • anonymous
hartnn
  • hartnn
which is ?
anonymous
  • anonymous
x3,y3
hartnn
  • hartnn
so =C so we can replace C by right ?
anonymous
  • anonymous
ohhyeauhhh! ool!
hartnn
  • hartnn
in same way, we can replace A by ... ? B by ... ?
anonymous
  • anonymous
A with x1,y1??
hartnn
  • hartnn
A with
hartnn
  • hartnn
=C so we can replace C by =A so we can replace A by =B so we can replace B by right ?
anonymous
  • anonymous
yes..
hartnn
  • hartnn
so put all those in c=xa+y and see whether u get what needs to be proven..
anonymous
  • anonymous
|dw:1352872625517:dw|
anonymous
  • anonymous
Do u mean plug in the value sliket his
hartnn
  • hartnn
|dw:1352872688272:dw|
anonymous
  • anonymous
OH THATS what you ment I tots get that!
hartnn
  • hartnn
all steps clear ? any doubts ?
anonymous
  • anonymous
Wait and how did u kno that OC=c and OA =A and OB = B ?
hartnn
  • hartnn
C = (x3,y3) =C-O = (x3,y3)-(0,0) = (x3-0,y3-0) = (x3,y3) = C same for A and b
hartnn
  • hartnn
got it ?
anonymous
  • anonymous
yea thanks (: Do you think we can do another in like 10 min?? I I need to sleep asap since I need to wake up early tomorrow (x
hartnn
  • hartnn
same type ? ....actually even i need to go in few minutes...
hartnn
  • hartnn
lets me see the question atleast
anonymous
  • anonymous
OK but && Oh and alsoo how did you know that ( C- B)/(A-C) = x/y
hartnn
  • hartnn
it is given that BC /CA = x/y now BC=C-B CA=A-C
hartnn
  • hartnn
remember for any vector XY, we can write it as Y-X
anonymous
  • anonymous
oh okay why is it flipped again?
hartnn
  • hartnn
flipped again ? means ?
anonymous
  • anonymous
Oh I mean like why isnt it like BC= B-c instead its C-B
hartnn
  • hartnn
its the conventional way of representation, but if you take BC=B-C , you will get same exact final answer....
hartnn
  • hartnn
so its no difference, just a way of representation
anonymous
  • anonymous
Oh right k thnx! lemme post the other problem I dont think we have enough tim :C

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