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butterflyprincess Group Title

Major MATH HELP! D: ** Pic included!

  • one year ago
  • one year ago

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  1. butterflyprincess Group Title
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    • one year ago
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  2. butterflyprincess Group Title
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    Help? :(

    • one year ago
  3. STEPHEN1998 Group Title
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    wat

    • one year ago
  4. butterflyprincess Group Title
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    I need some help with this problem

    • one year ago
  5. STEPHEN1998 Group Title
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    ok

    • one year ago
  6. STEPHEN1998 Group Title
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    wats ur answer

    • one year ago
  7. butterflyprincess Group Title
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    I dont have onne, I need help :| I attached a link of the problem

    • one year ago
  8. STEPHEN1998 Group Title
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    i did

    • one year ago
  9. STEPHEN1998 Group Title
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    hold on

    • one year ago
  10. butterflyprincess Group Title
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    thnx (:

    • one year ago
  11. zordoloom Group Title
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    Do you still need help?

    • one year ago
  12. butterflyprincess Group Title
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    Yes please (:

    • one year ago
  13. STEPHEN1998 Group Title
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    ya

    • one year ago
  14. zordoloom Group Title
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    Okay, Do you know how to even start working on this problem?

    • one year ago
  15. butterflyprincess Group Title
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    No :C

    • one year ago
  16. zordoloom Group Title
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    So are you working with vectors?

    • one year ago
  17. butterflyprincess Group Title
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    indeed I am!

    • one year ago
  18. butterflyprincess Group Title
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    Im just tottally lost on this problem

    • one year ago
  19. zordoloom Group Title
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    Ok, so have you done vector proofs before?

    • one year ago
  20. butterflyprincess Group Title
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    no neverO=

    • one year ago
  21. zordoloom Group Title
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    ok, so ob+ba=oa

    • one year ago
  22. zordoloom Group Title
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    0=(0,0) A=(x1,y1) B=(x2,y2)

    • one year ago
  23. zordoloom Group Title
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    Vector BA=A-B=(x1-x2, y1-y2)

    • one year ago
  24. butterflyprincess Group Title
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    okk

    • one year ago
  25. zordoloom Group Title
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    Good so far?

    • one year ago
  26. zordoloom Group Title
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    All what you have to do now is find vecotor OA and vecotr OB

    • one year ago
  27. butterflyprincess Group Title
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    O: oh really but is there like another pic you have to draw/

    • one year ago
  28. zordoloom Group Title
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    no

    • one year ago
  29. butterflyprincess Group Title
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    oh cool

    • one year ago
  30. zordoloom Group Title
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    |dw:1352869007184:dw|

    • one year ago
  31. zordoloom Group Title
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    so vector BA is equal to A-B so when you subtract the points element-wise you get x1-x2 and y1-y2

    • one year ago
  32. zordoloom Group Title
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    |dw:1352869116355:dw|

    • one year ago
  33. butterflyprincess Group Title
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    Oh right, now I find Oa Ob ?How can I do thta again?

    • one year ago
  34. zordoloom Group Title
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    |dw:1352869175679:dw|

    • one year ago
  35. zordoloom Group Title
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    now you do the same for vector ob

    • one year ago
  36. zordoloom Group Title
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    |dw:1352869297947:dw|

    • one year ago
  37. butterflyprincess Group Title
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    So OB is OB = O-B= <0-x2 , 0-y2 > ?

    • one year ago
  38. zordoloom Group Title
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    no, it would be <OB> = B-O = <x2,y2>

    • one year ago
  39. zordoloom Group Title
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    So, now you need to subtract <OB> from <OA>. to prove that it equals <AB>

    • one year ago
  40. butterflyprincess Group Title
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    ohhh right!

    • one year ago
  41. zordoloom Group Title
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    • one year ago
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  42. zordoloom Group Title
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    look at the attachment, the circled ones.

    • one year ago
  43. zordoloom Group Title
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    How would you prove the?

    • one year ago
  44. zordoloom Group Title
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    *them?

    • one year ago
  45. zordoloom Group Title
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    They are equal.

    • one year ago
  46. zordoloom Group Title
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    so, by the subtraction of the vectors, you prove that <BA> = <OA>-<OB>

    • one year ago
  47. butterflyprincess Group Title
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    OH theyre equal!! Its < x1-x2 , y1-y2 > !

    • one year ago
  48. zordoloom Group Title
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    pretty much.

    • one year ago
  49. zordoloom Group Title
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    Now to solve part 2, set point c equal to (x3, y3)

    • one year ago
  50. zordoloom Group Title
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    then I would solve for x3,y3 in terms of the other known quantities, x1,y1 and x2,y2 using the given ratio. the rest is just algebra.

    • one year ago
  51. butterflyprincess Group Title
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    So all what xOA is saying is to ditribute the x?

    • one year ago
  52. zordoloom Group Title
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    Ya

    • one year ago
  53. butterflyprincess Group Title
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    Oh okay yy

    • one year ago
  54. butterflyprincess Group Title
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    |dw:1352870110521:dw|

    • one year ago
  55. butterflyprincess Group Title
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    right?

    • one year ago
  56. zordoloom Group Title
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    yes.

    • one year ago
  57. butterflyprincess Group Title
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    Cool thanks ((:

    • one year ago
  58. hartnn Group Title
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    <OC>=C-O

    • one year ago
  59. hartnn Group Title
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    <BC>/<CA> =x/y so, (C-B)/(A-C) =x/y now can, you isolate C from here ? try it...

    • one year ago
  60. butterflyprincess Group Title
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    you want me to isolare c from (C-B)/(A-C) =x/y right?

    • one year ago
  61. hartnn Group Title
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    yes,

    • one year ago
  62. hartnn Group Title
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    u see, how i got, (C-B)/(A-C) =x/y from given condition, <BC>/<CA> =x/y

    • one year ago
  63. butterflyprincess Group Title
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    Wait how would you do that because C is being subtracted

    • one year ago
  64. hartnn Group Title
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    u mean how to isolate C ? cross-multiply....

    • one year ago
  65. butterflyprincess Group Title
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    yea youd get y(c-b) = x(a-c) ...

    • one year ago
  66. hartnn Group Title
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    try to isolate C from that...

    • one year ago
  67. butterflyprincess Group Title
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    so I distribute..first then

    • one year ago
  68. butterflyprincess Group Title
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    yc-cb = xa - xc

    • one year ago
  69. hartnn Group Title
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    yes, distribute then bring all terms with 'c' together, then factor out c

    • one year ago
  70. hartnn Group Title
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    its yc-yb on the left...

    • one year ago
  71. butterflyprincess Group Title
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    So C= xa-xc / (y-b)

    • one year ago
  72. hartnn Group Title
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    there, u were not able to isolate C, notice, c is there on right side also

    • one year ago
  73. hartnn Group Title
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    yc-yb = xa - xc yc+xc = xa+yb got this step ?

    • one year ago
  74. hartnn Group Title
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    now can u isolate c ?

    • one year ago
  75. butterflyprincess Group Title
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    I thought ititd be yc-cb = xa - xc since u cross mult tho..

    • one year ago
  76. butterflyprincess Group Title
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    |dw:1352871594989:dw|

    • one year ago
  77. hartnn Group Title
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    |dw:1352871643318:dw|

    • one year ago
  78. butterflyprincess Group Title
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    right x)

    • one year ago
  79. hartnn Group Title
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    |dw:1352871704757:dw|

    • one year ago
  80. butterflyprincess Group Title
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    yesyes i did that xD

    • one year ago
  81. hartnn Group Title
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    what does left side simplify to ?

    • one year ago
  82. hartnn Group Title
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    knowing that its given that x+y=1

    • one year ago
  83. butterflyprincess Group Title
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    C= xa+yb / y+x

    • one year ago
  84. hartnn Group Title
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    what is x+y= ?

    • one year ago
  85. butterflyprincess Group Title
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    Wait but does C equal to that O:

    • one year ago
  86. hartnn Group Title
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    yes.

    • one year ago
  87. butterflyprincess Group Title
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    oh okay lol Um y+x = .. ?

    • one year ago
  88. hartnn Group Title
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    its given to be =1 see the question

    • one year ago
  89. butterflyprincess Group Title
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    Oh cool so it would just be xa+yb

    • one year ago
  90. hartnn Group Title
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    yes, c=xa+yb now u know what to do next ?

    • one year ago
  91. butterflyprincess Group Title
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    PLug it to...

    • one year ago
  92. hartnn Group Title
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    we know that C=(x3,y3) and O=(0,0) so can you find <OC> = ?

    • one year ago
  93. butterflyprincess Group Title
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    <x3-0,y3-0>

    • one year ago
  94. hartnn Group Title
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    which is ?

    • one year ago
  95. butterflyprincess Group Title
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    x3,y3

    • one year ago
  96. hartnn Group Title
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    so <OC> =C so we can replace C by <OC> right ?

    • one year ago
  97. butterflyprincess Group Title
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    ohhyeauhhh! ool!

    • one year ago
  98. hartnn Group Title
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    in same way, we can replace A by ... ? B by ... ?

    • one year ago
  99. butterflyprincess Group Title
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    A with x1,y1??

    • one year ago
  100. hartnn Group Title
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    A with <OA>

    • one year ago
  101. hartnn Group Title
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    <OC> =C so we can replace C by <OC> <OA> =A so we can replace A by <OA> <OB> =B so we can replace B by <OB> right ?

    • one year ago
  102. butterflyprincess Group Title
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    yes..

    • one year ago
  103. hartnn Group Title
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    so put all those in c=xa+y and see whether u get what needs to be proven..

    • one year ago
  104. butterflyprincess Group Title
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    |dw:1352872625517:dw|

    • one year ago
  105. butterflyprincess Group Title
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    Do u mean plug in the value sliket his

    • one year ago
  106. hartnn Group Title
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    |dw:1352872688272:dw|

    • one year ago
  107. butterflyprincess Group Title
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    OH THATS what you ment I tots get that!

    • one year ago
  108. hartnn Group Title
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    all steps clear ? any doubts ?

    • one year ago
  109. butterflyprincess Group Title
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    Wait and how did u kno that OC=c and OA =A and OB = B ?

    • one year ago
  110. hartnn Group Title
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    C = (x3,y3) <OC> =C-O = (x3,y3)-(0,0) = (x3-0,y3-0) = (x3,y3) = C same for A and b

    • one year ago
  111. hartnn Group Title
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    got it ?

    • one year ago
  112. butterflyprincess Group Title
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    yea thanks (: Do you think we can do another in like 10 min?? I I need to sleep asap since I need to wake up early tomorrow (x

    • one year ago
  113. hartnn Group Title
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    same type ? ....actually even i need to go in few minutes...

    • one year ago
  114. hartnn Group Title
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    lets me see the question atleast

    • one year ago
  115. butterflyprincess Group Title
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    OK but && Oh and alsoo how did you know that ( C- B)/(A-C) = x/y

    • one year ago
  116. hartnn Group Title
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    it is given that BC /CA = x/y now BC=C-B CA=A-C

    • one year ago
  117. hartnn Group Title
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    remember for any vector XY, we can write it as Y-X

    • one year ago
  118. butterflyprincess Group Title
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    oh okay why is it flipped again?

    • one year ago
  119. hartnn Group Title
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    flipped again ? means ?

    • one year ago
  120. butterflyprincess Group Title
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    Oh I mean like why isnt it like BC= B-c instead its C-B

    • one year ago
  121. hartnn Group Title
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    its the conventional way of representation, but if you take BC=B-C , you will get same exact final answer....

    • one year ago
  122. hartnn Group Title
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    so its no difference, just a way of representation

    • one year ago
  123. butterflyprincess Group Title
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    Oh right k thnx! lemme post the other problem I dont think we have enough tim :C

    • one year ago
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