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butterflyprincess

  • 2 years ago

Major MATH HELP! D: ** Pic included!

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  1. butterflyprincess
    • 2 years ago
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  2. butterflyprincess
    • 2 years ago
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    Help? :(

  3. STEPHEN1998
    • 2 years ago
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    wat

  4. butterflyprincess
    • 2 years ago
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    I need some help with this problem

  5. STEPHEN1998
    • 2 years ago
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    ok

  6. STEPHEN1998
    • 2 years ago
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    wats ur answer

  7. butterflyprincess
    • 2 years ago
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    I dont have onne, I need help :| I attached a link of the problem

  8. STEPHEN1998
    • 2 years ago
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    i did

  9. STEPHEN1998
    • 2 years ago
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    hold on

  10. butterflyprincess
    • 2 years ago
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    thnx (:

  11. zordoloom
    • 2 years ago
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    Do you still need help?

  12. butterflyprincess
    • 2 years ago
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    Yes please (:

  13. STEPHEN1998
    • 2 years ago
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    ya

  14. zordoloom
    • 2 years ago
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    Okay, Do you know how to even start working on this problem?

  15. butterflyprincess
    • 2 years ago
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    No :C

  16. zordoloom
    • 2 years ago
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    So are you working with vectors?

  17. butterflyprincess
    • 2 years ago
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    indeed I am!

  18. butterflyprincess
    • 2 years ago
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    Im just tottally lost on this problem

  19. zordoloom
    • 2 years ago
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    Ok, so have you done vector proofs before?

  20. butterflyprincess
    • 2 years ago
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    no neverO=

  21. zordoloom
    • 2 years ago
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    ok, so ob+ba=oa

  22. zordoloom
    • 2 years ago
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    0=(0,0) A=(x1,y1) B=(x2,y2)

  23. zordoloom
    • 2 years ago
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    Vector BA=A-B=(x1-x2, y1-y2)

  24. butterflyprincess
    • 2 years ago
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    okk

  25. zordoloom
    • 2 years ago
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    Good so far?

  26. zordoloom
    • 2 years ago
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    All what you have to do now is find vecotor OA and vecotr OB

  27. butterflyprincess
    • 2 years ago
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    O: oh really but is there like another pic you have to draw/

  28. zordoloom
    • 2 years ago
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    no

  29. butterflyprincess
    • 2 years ago
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    oh cool

  30. zordoloom
    • 2 years ago
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    |dw:1352869007184:dw|

  31. zordoloom
    • 2 years ago
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    so vector BA is equal to A-B so when you subtract the points element-wise you get x1-x2 and y1-y2

  32. zordoloom
    • 2 years ago
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    |dw:1352869116355:dw|

  33. butterflyprincess
    • 2 years ago
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    Oh right, now I find Oa Ob ?How can I do thta again?

  34. zordoloom
    • 2 years ago
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    |dw:1352869175679:dw|

  35. zordoloom
    • 2 years ago
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    now you do the same for vector ob

  36. zordoloom
    • 2 years ago
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    |dw:1352869297947:dw|

  37. butterflyprincess
    • 2 years ago
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    So OB is OB = O-B= <0-x2 , 0-y2 > ?

  38. zordoloom
    • 2 years ago
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    no, it would be <OB> = B-O = <x2,y2>

  39. zordoloom
    • 2 years ago
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    So, now you need to subtract <OB> from <OA>. to prove that it equals <AB>

  40. butterflyprincess
    • 2 years ago
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    ohhh right!

  41. zordoloom
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    1 Attachment
  42. zordoloom
    • 2 years ago
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    look at the attachment, the circled ones.

  43. zordoloom
    • 2 years ago
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    How would you prove the?

  44. zordoloom
    • 2 years ago
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    *them?

  45. zordoloom
    • 2 years ago
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    They are equal.

  46. zordoloom
    • 2 years ago
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    so, by the subtraction of the vectors, you prove that <BA> = <OA>-<OB>

  47. butterflyprincess
    • 2 years ago
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    OH theyre equal!! Its < x1-x2 , y1-y2 > !

  48. zordoloom
    • 2 years ago
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    pretty much.

  49. zordoloom
    • 2 years ago
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    Now to solve part 2, set point c equal to (x3, y3)

  50. zordoloom
    • 2 years ago
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    then I would solve for x3,y3 in terms of the other known quantities, x1,y1 and x2,y2 using the given ratio. the rest is just algebra.

  51. butterflyprincess
    • 2 years ago
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    So all what xOA is saying is to ditribute the x?

  52. zordoloom
    • 2 years ago
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    Ya

  53. butterflyprincess
    • 2 years ago
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    Oh okay yy

  54. butterflyprincess
    • 2 years ago
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    |dw:1352870110521:dw|

  55. butterflyprincess
    • 2 years ago
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    right?

  56. zordoloom
    • 2 years ago
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    yes.

  57. butterflyprincess
    • 2 years ago
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    Cool thanks ((:

  58. hartnn
    • 2 years ago
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    <OC>=C-O

  59. hartnn
    • 2 years ago
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    <BC>/<CA> =x/y so, (C-B)/(A-C) =x/y now can, you isolate C from here ? try it...

  60. butterflyprincess
    • 2 years ago
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    you want me to isolare c from (C-B)/(A-C) =x/y right?

  61. hartnn
    • 2 years ago
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    yes,

  62. hartnn
    • 2 years ago
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    u see, how i got, (C-B)/(A-C) =x/y from given condition, <BC>/<CA> =x/y

  63. butterflyprincess
    • 2 years ago
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    Wait how would you do that because C is being subtracted

  64. hartnn
    • 2 years ago
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    u mean how to isolate C ? cross-multiply....

  65. butterflyprincess
    • 2 years ago
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    yea youd get y(c-b) = x(a-c) ...

  66. hartnn
    • 2 years ago
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    try to isolate C from that...

  67. butterflyprincess
    • 2 years ago
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    so I distribute..first then

  68. butterflyprincess
    • 2 years ago
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    yc-cb = xa - xc

  69. hartnn
    • 2 years ago
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    yes, distribute then bring all terms with 'c' together, then factor out c

  70. hartnn
    • 2 years ago
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    its yc-yb on the left...

  71. butterflyprincess
    • 2 years ago
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    So C= xa-xc / (y-b)

  72. hartnn
    • 2 years ago
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    there, u were not able to isolate C, notice, c is there on right side also

  73. hartnn
    • 2 years ago
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    yc-yb = xa - xc yc+xc = xa+yb got this step ?

  74. hartnn
    • 2 years ago
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    now can u isolate c ?

  75. butterflyprincess
    • 2 years ago
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    I thought ititd be yc-cb = xa - xc since u cross mult tho..

  76. butterflyprincess
    • 2 years ago
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    |dw:1352871594989:dw|

  77. hartnn
    • 2 years ago
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    |dw:1352871643318:dw|

  78. butterflyprincess
    • 2 years ago
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    right x)

  79. hartnn
    • 2 years ago
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    |dw:1352871704757:dw|

  80. butterflyprincess
    • 2 years ago
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    yesyes i did that xD

  81. hartnn
    • 2 years ago
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    what does left side simplify to ?

  82. hartnn
    • 2 years ago
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    knowing that its given that x+y=1

  83. butterflyprincess
    • 2 years ago
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    C= xa+yb / y+x

  84. hartnn
    • 2 years ago
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    what is x+y= ?

  85. butterflyprincess
    • 2 years ago
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    Wait but does C equal to that O:

  86. hartnn
    • 2 years ago
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    yes.

  87. butterflyprincess
    • 2 years ago
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    oh okay lol Um y+x = .. ?

  88. hartnn
    • 2 years ago
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    its given to be =1 see the question

  89. butterflyprincess
    • 2 years ago
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    Oh cool so it would just be xa+yb

  90. hartnn
    • 2 years ago
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    yes, c=xa+yb now u know what to do next ?

  91. butterflyprincess
    • 2 years ago
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    PLug it to...

  92. hartnn
    • 2 years ago
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    we know that C=(x3,y3) and O=(0,0) so can you find <OC> = ?

  93. butterflyprincess
    • 2 years ago
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    <x3-0,y3-0>

  94. hartnn
    • 2 years ago
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    which is ?

  95. butterflyprincess
    • 2 years ago
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    x3,y3

  96. hartnn
    • 2 years ago
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    so <OC> =C so we can replace C by <OC> right ?

  97. butterflyprincess
    • 2 years ago
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    ohhyeauhhh! ool!

  98. hartnn
    • 2 years ago
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    in same way, we can replace A by ... ? B by ... ?

  99. butterflyprincess
    • 2 years ago
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    A with x1,y1??

  100. hartnn
    • 2 years ago
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    A with <OA>

  101. hartnn
    • 2 years ago
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    <OC> =C so we can replace C by <OC> <OA> =A so we can replace A by <OA> <OB> =B so we can replace B by <OB> right ?

  102. butterflyprincess
    • 2 years ago
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    yes..

  103. hartnn
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    so put all those in c=xa+y and see whether u get what needs to be proven..

  104. butterflyprincess
    • 2 years ago
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    |dw:1352872625517:dw|

  105. butterflyprincess
    • 2 years ago
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    Do u mean plug in the value sliket his

  106. hartnn
    • 2 years ago
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    |dw:1352872688272:dw|

  107. butterflyprincess
    • 2 years ago
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    OH THATS what you ment I tots get that!

  108. hartnn
    • 2 years ago
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    all steps clear ? any doubts ?

  109. butterflyprincess
    • 2 years ago
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    Wait and how did u kno that OC=c and OA =A and OB = B ?

  110. hartnn
    • 2 years ago
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    C = (x3,y3) <OC> =C-O = (x3,y3)-(0,0) = (x3-0,y3-0) = (x3,y3) = C same for A and b

  111. hartnn
    • 2 years ago
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    got it ?

  112. butterflyprincess
    • 2 years ago
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    yea thanks (: Do you think we can do another in like 10 min?? I I need to sleep asap since I need to wake up early tomorrow (x

  113. hartnn
    • 2 years ago
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    same type ? ....actually even i need to go in few minutes...

  114. hartnn
    • 2 years ago
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    lets me see the question atleast

  115. butterflyprincess
    • 2 years ago
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    OK but && Oh and alsoo how did you know that ( C- B)/(A-C) = x/y

  116. hartnn
    • 2 years ago
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    it is given that BC /CA = x/y now BC=C-B CA=A-C

  117. hartnn
    • 2 years ago
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    remember for any vector XY, we can write it as Y-X

  118. butterflyprincess
    • 2 years ago
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    oh okay why is it flipped again?

  119. hartnn
    • 2 years ago
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    flipped again ? means ?

  120. butterflyprincess
    • 2 years ago
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    Oh I mean like why isnt it like BC= B-c instead its C-B

  121. hartnn
    • 2 years ago
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    its the conventional way of representation, but if you take BC=B-C , you will get same exact final answer....

  122. hartnn
    • 2 years ago
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    so its no difference, just a way of representation

  123. butterflyprincess
    • 2 years ago
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    Oh right k thnx! lemme post the other problem I dont think we have enough tim :C

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