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butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Help? :(
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
I need some help with this problem
 2 years ago

STEPHEN1998 Group TitleBest ResponseYou've already chosen the best response.0
wats ur answer
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
I dont have onne, I need help : I attached a link of the problem
 2 years ago

STEPHEN1998 Group TitleBest ResponseYou've already chosen the best response.0
hold on
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
thnx (:
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
Do you still need help?
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Yes please (:
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
Okay, Do you know how to even start working on this problem?
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
No :C
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
So are you working with vectors?
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
indeed I am!
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Im just tottally lost on this problem
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
Ok, so have you done vector proofs before?
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
no neverO=
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
ok, so ob+ba=oa
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
0=(0,0) A=(x1,y1) B=(x2,y2)
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
Vector BA=AB=(x1x2, y1y2)
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
okk
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
Good so far?
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
All what you have to do now is find vecotor OA and vecotr OB
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
O: oh really but is there like another pic you have to draw/
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
oh cool
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
dw:1352869007184:dw
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
so vector BA is equal to AB so when you subtract the points elementwise you get x1x2 and y1y2
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
dw:1352869116355:dw
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Oh right, now I find Oa Ob ?How can I do thta again?
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
dw:1352869175679:dw
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
now you do the same for vector ob
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
dw:1352869297947:dw
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
So OB is OB = OB= <0x2 , 0y2 > ?
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
no, it would be <OB> = BO = <x2,y2>
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
So, now you need to subtract <OB> from <OA>. to prove that it equals <AB>
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
ohhh right!
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
look at the attachment, the circled ones.
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
How would you prove the?
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
They are equal.
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
so, by the subtraction of the vectors, you prove that <BA> = <OA><OB>
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
OH theyre equal!! Its < x1x2 , y1y2 > !
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
pretty much.
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
Now to solve part 2, set point c equal to (x3, y3)
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
then I would solve for x3,y3 in terms of the other known quantities, x1,y1 and x2,y2 using the given ratio. the rest is just algebra.
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
So all what xOA is saying is to ditribute the x?
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Oh okay yy
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
dw:1352870110521:dw
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
right?
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Cool thanks ((:
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
<BC>/<CA> =x/y so, (CB)/(AC) =x/y now can, you isolate C from here ? try it...
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
you want me to isolare c from (CB)/(AC) =x/y right?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
u see, how i got, (CB)/(AC) =x/y from given condition, <BC>/<CA> =x/y
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Wait how would you do that because C is being subtracted
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
u mean how to isolate C ? crossmultiply....
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
yea youd get y(cb) = x(ac) ...
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
try to isolate C from that...
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
so I distribute..first then
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
yccb = xa  xc
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yes, distribute then bring all terms with 'c' together, then factor out c
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
its ycyb on the left...
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
So C= xaxc / (yb)
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
there, u were not able to isolate C, notice, c is there on right side also
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
ycyb = xa  xc yc+xc = xa+yb got this step ?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
now can u isolate c ?
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
I thought ititd be yccb = xa  xc since u cross mult tho..
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
dw:1352871594989:dw
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
dw:1352871643318:dw
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
right x)
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
dw:1352871704757:dw
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
yesyes i did that xD
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
what does left side simplify to ?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
knowing that its given that x+y=1
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
C= xa+yb / y+x
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
what is x+y= ?
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Wait but does C equal to that O:
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
oh okay lol Um y+x = .. ?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
its given to be =1 see the question
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Oh cool so it would just be xa+yb
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yes, c=xa+yb now u know what to do next ?
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
PLug it to...
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
we know that C=(x3,y3) and O=(0,0) so can you find <OC> = ?
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
<x30,y30>
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
x3,y3
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
so <OC> =C so we can replace C by <OC> right ?
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
ohhyeauhhh! ool!
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
in same way, we can replace A by ... ? B by ... ?
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
A with x1,y1??
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
<OC> =C so we can replace C by <OC> <OA> =A so we can replace A by <OA> <OB> =B so we can replace B by <OB> right ?
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
yes..
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
so put all those in c=xa+y and see whether u get what needs to be proven..
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
dw:1352872625517:dw
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Do u mean plug in the value sliket his
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
dw:1352872688272:dw
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
OH THATS what you ment I tots get that!
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
all steps clear ? any doubts ?
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Wait and how did u kno that OC=c and OA =A and OB = B ?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
C = (x3,y3) <OC> =CO = (x3,y3)(0,0) = (x30,y30) = (x3,y3) = C same for A and b
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
yea thanks (: Do you think we can do another in like 10 min?? I I need to sleep asap since I need to wake up early tomorrow (x
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
same type ? ....actually even i need to go in few minutes...
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
lets me see the question atleast
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
OK but && Oh and alsoo how did you know that ( C B)/(AC) = x/y
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
it is given that BC /CA = x/y now BC=CB CA=AC
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
remember for any vector XY, we can write it as YX
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
oh okay why is it flipped again?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
flipped again ? means ?
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Oh I mean like why isnt it like BC= Bc instead its CB
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
its the conventional way of representation, but if you take BC=BC , you will get same exact final answer....
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
so its no difference, just a way of representation
 2 years ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Oh right k thnx! lemme post the other problem I dont think we have enough tim :C
 2 years ago
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