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anonymous
 4 years ago
Major MATH HELP! D: ** Pic included!
anonymous
 4 years ago
Major MATH HELP! D: ** Pic included!

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I need some help with this problem

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I dont have onne, I need help : I attached a link of the problem

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do you still need help?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay, Do you know how to even start working on this problem?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So are you working with vectors?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Im just tottally lost on this problem

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok, so have you done vector proofs before?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.00=(0,0) A=(x1,y1) B=(x2,y2)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Vector BA=AB=(x1x2, y1y2)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0All what you have to do now is find vecotor OA and vecotr OB

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0O: oh really but is there like another pic you have to draw/

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1352869007184:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so vector BA is equal to AB so when you subtract the points elementwise you get x1x2 and y1y2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1352869116355:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh right, now I find Oa Ob ?How can I do thta again?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1352869175679:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now you do the same for vector ob

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1352869297947:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So OB is OB = OB= <0x2 , 0y2 > ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no, it would be <OB> = BO = <x2,y2>

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So, now you need to subtract <OB> from <OA>. to prove that it equals <AB>

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0look at the attachment, the circled ones.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0How would you prove the?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so, by the subtraction of the vectors, you prove that <BA> = <OA><OB>

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0OH theyre equal!! Its < x1x2 , y1y2 > !

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Now to solve part 2, set point c equal to (x3, y3)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then I would solve for x3,y3 in terms of the other known quantities, x1,y1 and x2,y2 using the given ratio. the rest is just algebra.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So all what xOA is saying is to ditribute the x?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1352870110521:dw

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1<BC>/<CA> =x/y so, (CB)/(AC) =x/y now can, you isolate C from here ? try it...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you want me to isolare c from (CB)/(AC) =x/y right?

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1u see, how i got, (CB)/(AC) =x/y from given condition, <BC>/<CA> =x/y

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Wait how would you do that because C is being subtracted

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1u mean how to isolate C ? crossmultiply....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yea youd get y(cb) = x(ac) ...

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1try to isolate C from that...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so I distribute..first then

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1yes, distribute then bring all terms with 'c' together, then factor out c

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1its ycyb on the left...

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1there, u were not able to isolate C, notice, c is there on right side also

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1ycyb = xa  xc yc+xc = xa+yb got this step ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I thought ititd be yccb = xa  xc since u cross mult tho..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1352871594989:dw

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1what does left side simplify to ?

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1knowing that its given that x+y=1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Wait but does C equal to that O:

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh okay lol Um y+x = .. ?

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1its given to be =1 see the question

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh cool so it would just be xa+yb

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1yes, c=xa+yb now u know what to do next ?

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1we know that C=(x3,y3) and O=(0,0) so can you find <OC> = ?

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1so <OC> =C so we can replace C by <OC> right ?

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1in same way, we can replace A by ... ? B by ... ?

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1<OC> =C so we can replace C by <OC> <OA> =A so we can replace A by <OA> <OB> =B so we can replace B by <OB> right ?

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1so put all those in c=xa+y and see whether u get what needs to be proven..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1352872625517:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do u mean plug in the value sliket his

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0OH THATS what you ment I tots get that!

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1all steps clear ? any doubts ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Wait and how did u kno that OC=c and OA =A and OB = B ?

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1C = (x3,y3) <OC> =CO = (x3,y3)(0,0) = (x30,y30) = (x3,y3) = C same for A and b

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yea thanks (: Do you think we can do another in like 10 min?? I I need to sleep asap since I need to wake up early tomorrow (x

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1same type ? ....actually even i need to go in few minutes...

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1lets me see the question atleast

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0OK but && Oh and alsoo how did you know that ( C B)/(AC) = x/y

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1it is given that BC /CA = x/y now BC=CB CA=AC

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1remember for any vector XY, we can write it as YX

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh okay why is it flipped again?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh I mean like why isnt it like BC= Bc instead its CB

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1its the conventional way of representation, but if you take BC=BC , you will get same exact final answer....

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1so its no difference, just a way of representation

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh right k thnx! lemme post the other problem I dont think we have enough tim :C
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