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butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Help? :(
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
I need some help with this problem
 one year ago

STEPHEN1998 Group TitleBest ResponseYou've already chosen the best response.0
wats ur answer
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
I dont have onne, I need help : I attached a link of the problem
 one year ago

STEPHEN1998 Group TitleBest ResponseYou've already chosen the best response.0
hold on
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
thnx (:
 one year ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
Do you still need help?
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Yes please (:
 one year ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
Okay, Do you know how to even start working on this problem?
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
No :C
 one year ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
So are you working with vectors?
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
indeed I am!
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Im just tottally lost on this problem
 one year ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
Ok, so have you done vector proofs before?
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
no neverO=
 one year ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
ok, so ob+ba=oa
 one year ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
0=(0,0) A=(x1,y1) B=(x2,y2)
 one year ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
Vector BA=AB=(x1x2, y1y2)
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
okk
 one year ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
Good so far?
 one year ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
All what you have to do now is find vecotor OA and vecotr OB
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
O: oh really but is there like another pic you have to draw/
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
oh cool
 one year ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
dw:1352869007184:dw
 one year ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
so vector BA is equal to AB so when you subtract the points elementwise you get x1x2 and y1y2
 one year ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
dw:1352869116355:dw
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Oh right, now I find Oa Ob ?How can I do thta again?
 one year ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
dw:1352869175679:dw
 one year ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
now you do the same for vector ob
 one year ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
dw:1352869297947:dw
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
So OB is OB = OB= <0x2 , 0y2 > ?
 one year ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
no, it would be <OB> = BO = <x2,y2>
 one year ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
So, now you need to subtract <OB> from <OA>. to prove that it equals <AB>
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
ohhh right!
 one year ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
look at the attachment, the circled ones.
 one year ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
How would you prove the?
 one year ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
They are equal.
 one year ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
so, by the subtraction of the vectors, you prove that <BA> = <OA><OB>
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
OH theyre equal!! Its < x1x2 , y1y2 > !
 one year ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
pretty much.
 one year ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
Now to solve part 2, set point c equal to (x3, y3)
 one year ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
then I would solve for x3,y3 in terms of the other known quantities, x1,y1 and x2,y2 using the given ratio. the rest is just algebra.
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
So all what xOA is saying is to ditribute the x?
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Oh okay yy
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
dw:1352870110521:dw
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
right?
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Cool thanks ((:
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
<BC>/<CA> =x/y so, (CB)/(AC) =x/y now can, you isolate C from here ? try it...
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
you want me to isolare c from (CB)/(AC) =x/y right?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
u see, how i got, (CB)/(AC) =x/y from given condition, <BC>/<CA> =x/y
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Wait how would you do that because C is being subtracted
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
u mean how to isolate C ? crossmultiply....
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
yea youd get y(cb) = x(ac) ...
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
try to isolate C from that...
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
so I distribute..first then
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
yccb = xa  xc
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yes, distribute then bring all terms with 'c' together, then factor out c
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
its ycyb on the left...
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
So C= xaxc / (yb)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
there, u were not able to isolate C, notice, c is there on right side also
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
ycyb = xa  xc yc+xc = xa+yb got this step ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
now can u isolate c ?
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
I thought ititd be yccb = xa  xc since u cross mult tho..
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
dw:1352871594989:dw
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
dw:1352871643318:dw
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
right x)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
dw:1352871704757:dw
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
yesyes i did that xD
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
what does left side simplify to ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
knowing that its given that x+y=1
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
C= xa+yb / y+x
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
what is x+y= ?
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Wait but does C equal to that O:
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
oh okay lol Um y+x = .. ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
its given to be =1 see the question
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Oh cool so it would just be xa+yb
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yes, c=xa+yb now u know what to do next ?
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
PLug it to...
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
we know that C=(x3,y3) and O=(0,0) so can you find <OC> = ?
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
<x30,y30>
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
x3,y3
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
so <OC> =C so we can replace C by <OC> right ?
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
ohhyeauhhh! ool!
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
in same way, we can replace A by ... ? B by ... ?
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
A with x1,y1??
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
A with <OA>
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
<OC> =C so we can replace C by <OC> <OA> =A so we can replace A by <OA> <OB> =B so we can replace B by <OB> right ?
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
yes..
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
so put all those in c=xa+y and see whether u get what needs to be proven..
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
dw:1352872625517:dw
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Do u mean plug in the value sliket his
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
dw:1352872688272:dw
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
OH THATS what you ment I tots get that!
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
all steps clear ? any doubts ?
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Wait and how did u kno that OC=c and OA =A and OB = B ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
C = (x3,y3) <OC> =CO = (x3,y3)(0,0) = (x30,y30) = (x3,y3) = C same for A and b
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
yea thanks (: Do you think we can do another in like 10 min?? I I need to sleep asap since I need to wake up early tomorrow (x
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
same type ? ....actually even i need to go in few minutes...
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
lets me see the question atleast
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
OK but && Oh and alsoo how did you know that ( C B)/(AC) = x/y
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
it is given that BC /CA = x/y now BC=CB CA=AC
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
remember for any vector XY, we can write it as YX
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
oh okay why is it flipped again?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
flipped again ? means ?
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Oh I mean like why isnt it like BC= Bc instead its CB
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
its the conventional way of representation, but if you take BC=BC , you will get same exact final answer....
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
so its no difference, just a way of representation
 one year ago

butterflyprincess Group TitleBest ResponseYou've already chosen the best response.0
Oh right k thnx! lemme post the other problem I dont think we have enough tim :C
 one year ago
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