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find the limit of (7n-8)/(2-sqrtn) as n goes to infinity

Mathematics
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yes it is
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Other answers:

Think about this logically. Which one approaches infinity faster?
thanks.. the answer is negative infinity, does that mean it diverges, right?
Actually... It's infinity. Not - Infinity.
Think. Which n term approaches infinity faster. In other words, does 7n and a square root approach infinity faster?
or a square root*
if you do L'Hopital's rule, you get 7/(-1/(2sqrtn)) = -14sqrtn limit of that is negative infinity
Lol. Okay fine We can use L'hopital's rule if you want.
Yes, then it is -Infinity. It diverges then.
:) Thanks
No problem :) .

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