anonymous
  • anonymous
find the limit of (7n-8)/(2-sqrtn) as n goes to infinity
Mathematics
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anonymous
  • anonymous
find the limit of (7n-8)/(2-sqrtn) as n goes to infinity
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
|dw:1352868502561:dw|
anonymous
  • anonymous
yes it is
anonymous
  • anonymous
|dw:1352869767197:dw|

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anonymous
  • anonymous
Think about this logically. Which one approaches infinity faster?
anonymous
  • anonymous
thanks.. the answer is negative infinity, does that mean it diverges, right?
anonymous
  • anonymous
Actually... It's infinity. Not - Infinity.
anonymous
  • anonymous
Think. Which n term approaches infinity faster. In other words, does 7n and a square root approach infinity faster?
anonymous
  • anonymous
or a square root*
anonymous
  • anonymous
if you do L'Hopital's rule, you get 7/(-1/(2sqrtn)) = -14sqrtn limit of that is negative infinity
anonymous
  • anonymous
Lol. Okay fine We can use L'hopital's rule if you want.
anonymous
  • anonymous
Yes, then it is -Infinity. It diverges then.
anonymous
  • anonymous
:) Thanks
anonymous
  • anonymous
No problem :) .

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