privetek
find the limit of (7n8)/(2sqrtn) as n goes to infinity



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Dido525
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dw:1352868502561:dw

privetek
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yes it is

Dido525
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dw:1352869767197:dw

Dido525
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Think about this logically. Which one approaches infinity faster?

privetek
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thanks..
the answer is negative infinity, does that mean it diverges, right?

Dido525
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Actually... It's infinity. Not  Infinity.

Dido525
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Think. Which n term approaches infinity faster.
In other words, does 7n and a square root approach infinity faster?

Dido525
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or a square root*

privetek
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if you do L'Hopital's rule, you get 7/(1/(2sqrtn)) = 14sqrtn
limit of that is negative infinity

Dido525
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Lol. Okay fine We can use L'hopital's rule if you want.

Dido525
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Yes, then it is Infinity. It diverges then.

privetek
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:) Thanks

Dido525
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No problem :) .