richyw
Was trying to help someone with a highschool geometry problem. Now I am stuck myself
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Hero
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This ought to be interesting
richyw
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|dw:1352873514894:dw|
Hero
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And what exactly were you asked to do with that?
richyw
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given that \(m\angle Q=42^{\circ}\), and the line NQ bisects \(\angle MNP\), and the line PQ bisects \(\angle MPR\) Find \(m\angle M\)
richyw
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not sure if it's the notation that is throwing me off?
UnkleRhaukus
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|dw:1352873934959:dw|
UnkleRhaukus
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the internal angle sum of a triangle is 180°
the internal angle sum of a quadrilateral is 360°
UnkleRhaukus
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are the lines QM and RN parallel by any chance?
richyw
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I wasn't sure, but I tried under that assumption.
richyw
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oh the answer is 84 by the way. This isn't what I got
richyw
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yup just tried again. is anyone actually trying this?
UnkleRhaukus
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im trying
UnkleRhaukus
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i dont think those lines could be parallel
richyw
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that is what I figured as well. so I attempted by just assuming that N,P and R all lie on one line. But then I can't figure out if there is a solution.
UnkleRhaukus
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|dw:1352875825955:dw|
Hero
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More assumptions
richyw
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I have to give up! If someone figures it out please post it. I really don't know.
Shadowys
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The question seems to be missing something. Is there a length somewhere? Or maybe it's cylic? It's brings me to a wild goose chase....
Shadowys
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What's the answer? 84? if it's 84 then its parallel...
richyw
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how did you work that out?
Shadowys
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|dw:1352887526794:dw|
Hero
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@Shadowy, your logic appears to be flawed:
2(42) + 2x = 180? How?
Shadowys
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Well,since \(\Delta \)MPN is an isosceles triangle, angle MPN=angle MNP, so at the point P, y=42, 2y+2x=180.
Hero
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Bro, there's no evidence that suggests MPN is isosceles
Hero
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@Shadowys
Shadowys
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If and only if the MQ and NP is parallel, then as shown above, QM=MP=MN.
And the answer happens to be 84. So this assumption is right.