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privetekBest ResponseYou've already chosen the best response.0
\[\sum_{1}^{\infty} (lnk)/(e ^{\sqrt{k}})\]
 one year ago

privetekBest ResponseYou've already chosen the best response.0
what test did you use?
 one year ago

EarthCitizenBest ResponseYou've already chosen the best response.1
when u find the limiting value \[U_{k+1}/U_{n}\]
 one year ago

EarthCitizenBest ResponseYou've already chosen the best response.1
\[\left U _{k+1}/U_{k} \right\]
 one year ago

privetekBest ResponseYou've already chosen the best response.0
can you kinda show me how you got zero?
 one year ago

EarthCitizenBest ResponseYou've already chosen the best response.1
\[ U_{k} = \ln(k)/e^{k} , U_{k+1} = \ln(k+1)/e^{k+1} \]\[ \therefore \left U_{k+1}/U_{k} \right = \ln(k+1)/e^{k+1} \times e^{k}/\ln(k)\]
 one year ago

EarthCitizenBest ResponseYou've already chosen the best response.1
\[ \ln(1) \times e^{\sqrt(k)\sqrt(k+1)} = 0\]
 one year ago

EarthCitizenBest ResponseYou've already chosen the best response.1
what was the answer in the text book ?
 one year ago

privetekBest ResponseYou've already chosen the best response.0
it wasn't from my textbook so i don't know the right answer but that looks right.
 one year ago
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