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privetek Group Title

determine whether the series converges or diverges:

  • 2 years ago
  • 2 years ago

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  1. privetek Group Title
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    \[\sum_{1}^{\infty} (lnk)/(e ^{\sqrt{k}})\]

    • 2 years ago
  2. EarthCitizen Group Title
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    0

    • 2 years ago
  3. privetek Group Title
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    what test did you use?

    • 2 years ago
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    when u find the limiting value \[U_{k+1}/U_{n}\]

    • 2 years ago
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    \[\left| U _{k+1}/U_{k} \right|\]

    • 2 years ago
  6. privetek Group Title
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    can you kinda show me how you got zero?

    • 2 years ago
  7. EarthCitizen Group Title
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    \[ U_{k} = \ln(k)/e^{k} , U_{k+1} = \ln(k+1)/e^{k+1} \]\[ \therefore \left| U_{k+1}/U_{k} \right| = \ln(k+1)/e^{k+1} \times e^{k}/\ln(k)\]

    • 2 years ago
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    \[ \ln(1) \times e^{\sqrt(k)-\sqrt(k+1)} = 0\]

    • 2 years ago
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    did that help ?

    • 2 years ago
  10. privetek Group Title
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    great! thanks :)

    • 2 years ago
  11. EarthCitizen Group Title
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    what was the answer in the text book ?

    • 2 years ago
  12. privetek Group Title
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    it wasn't from my textbook so i don't know the right answer but that looks right.

    • 2 years ago
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spraguer (Moderator)
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