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privetek
 2 years ago
Best ResponseYou've already chosen the best response.0\[\sum_{1}^{\infty} (lnk)/(e ^{\sqrt{k}})\]

privetek
 2 years ago
Best ResponseYou've already chosen the best response.0what test did you use?

EarthCitizen
 2 years ago
Best ResponseYou've already chosen the best response.1when u find the limiting value \[U_{k+1}/U_{n}\]

EarthCitizen
 2 years ago
Best ResponseYou've already chosen the best response.1\[\left U _{k+1}/U_{k} \right\]

privetek
 2 years ago
Best ResponseYou've already chosen the best response.0can you kinda show me how you got zero?

EarthCitizen
 2 years ago
Best ResponseYou've already chosen the best response.1\[ U_{k} = \ln(k)/e^{k} , U_{k+1} = \ln(k+1)/e^{k+1} \]\[ \therefore \left U_{k+1}/U_{k} \right = \ln(k+1)/e^{k+1} \times e^{k}/\ln(k)\]

EarthCitizen
 2 years ago
Best ResponseYou've already chosen the best response.1\[ \ln(1) \times e^{\sqrt(k)\sqrt(k+1)} = 0\]

EarthCitizen
 2 years ago
Best ResponseYou've already chosen the best response.1what was the answer in the text book ?

privetek
 2 years ago
Best ResponseYou've already chosen the best response.0it wasn't from my textbook so i don't know the right answer but that looks right.
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