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privetek Group TitleBest ResponseYou've already chosen the best response.0
\[\sum_{1}^{\infty} (lnk)/(e ^{\sqrt{k}})\]
 one year ago

privetek Group TitleBest ResponseYou've already chosen the best response.0
what test did you use?
 one year ago

EarthCitizen Group TitleBest ResponseYou've already chosen the best response.1
when u find the limiting value \[U_{k+1}/U_{n}\]
 one year ago

EarthCitizen Group TitleBest ResponseYou've already chosen the best response.1
\[\left U _{k+1}/U_{k} \right\]
 one year ago

privetek Group TitleBest ResponseYou've already chosen the best response.0
can you kinda show me how you got zero?
 one year ago

EarthCitizen Group TitleBest ResponseYou've already chosen the best response.1
\[ U_{k} = \ln(k)/e^{k} , U_{k+1} = \ln(k+1)/e^{k+1} \]\[ \therefore \left U_{k+1}/U_{k} \right = \ln(k+1)/e^{k+1} \times e^{k}/\ln(k)\]
 one year ago

EarthCitizen Group TitleBest ResponseYou've already chosen the best response.1
\[ \ln(1) \times e^{\sqrt(k)\sqrt(k+1)} = 0\]
 one year ago

EarthCitizen Group TitleBest ResponseYou've already chosen the best response.1
did that help ?
 one year ago

privetek Group TitleBest ResponseYou've already chosen the best response.0
great! thanks :)
 one year ago

EarthCitizen Group TitleBest ResponseYou've already chosen the best response.1
what was the answer in the text book ?
 one year ago

privetek Group TitleBest ResponseYou've already chosen the best response.0
it wasn't from my textbook so i don't know the right answer but that looks right.
 one year ago
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