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Evaluate ∫∫ over D (cos(sqrt(x^2+y^2)) dA by changing polar coordinates where the disk is with center of origin and radius 2

Mathematics
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I got up to ∫∫[0 to 2pi] [0 to 2] cos(sqrt(r)) r dr dt
but I can't solve for it! How do integrate r*cos(sqrt(r))
\[\int\limits\int\limits_{D}=\int\limits_{0}^{2\pi} d\theta\ \int\limits_{0}^{2}r \cos rdr\]

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Other answers:

omg you are correct.
spent literally 30 mins trying to see what I did wrong. That was quick thanks a lot man
yw
by the way:int( rcos r) it's done by integration by parts
can't I do substitution
you can try
haha I just did and it didn't work, alright thanks again!
if you have problems look here, :) http://en.wikipedia.org/wiki/Integration_by_parts
there exacly you example
your*
Yeah I got it now, thanks a lot for your help!

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