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allsmiles
 3 years ago
Evaluate ∫∫ over D (cos(sqrt(x^2+y^2)) dA by changing polar coordinates where the disk is with center of origin and radius 2
allsmiles
 3 years ago
Evaluate ∫∫ over D (cos(sqrt(x^2+y^2)) dA by changing polar coordinates where the disk is with center of origin and radius 2

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allsmiles
 3 years ago
Best ResponseYou've already chosen the best response.0I got up to ∫∫[0 to 2pi] [0 to 2] cos(sqrt(r)) r dr dt

allsmiles
 3 years ago
Best ResponseYou've already chosen the best response.0but I can't solve for it! How do integrate r*cos(sqrt(r))

myko
 3 years ago
Best ResponseYou've already chosen the best response.1\[\int\limits\int\limits_{D}=\int\limits_{0}^{2\pi} d\theta\ \int\limits_{0}^{2}r \cos rdr\]

allsmiles
 3 years ago
Best ResponseYou've already chosen the best response.0spent literally 30 mins trying to see what I did wrong. That was quick thanks a lot man

myko
 3 years ago
Best ResponseYou've already chosen the best response.1by the way:int( rcos r) it's done by integration by parts

allsmiles
 3 years ago
Best ResponseYou've already chosen the best response.0can't I do substitution

allsmiles
 3 years ago
Best ResponseYou've already chosen the best response.0haha I just did and it didn't work, alright thanks again!

myko
 3 years ago
Best ResponseYou've already chosen the best response.1if you have problems look here, :) http://en.wikipedia.org/wiki/Integration_by_parts

allsmiles
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah I got it now, thanks a lot for your help!
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