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allsmiles Group Title

Evaluate ∫∫ over D (cos(sqrt(x^2+y^2)) dA by changing polar coordinates where the disk is with center of origin and radius 2

  • 2 years ago
  • 2 years ago

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  1. allsmiles Group Title
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    I got up to ∫∫[0 to 2pi] [0 to 2] cos(sqrt(r)) r dr dt

    • 2 years ago
  2. allsmiles Group Title
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    but I can't solve for it! How do integrate r*cos(sqrt(r))

    • 2 years ago
  3. myko Group Title
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    \[\int\limits\int\limits_{D}=\int\limits_{0}^{2\pi} d\theta\ \int\limits_{0}^{2}r \cos rdr\]

    • 2 years ago
  4. allsmiles Group Title
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    omg you are correct.

    • 2 years ago
  5. allsmiles Group Title
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    spent literally 30 mins trying to see what I did wrong. That was quick thanks a lot man

    • 2 years ago
  6. myko Group Title
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    yw

    • 2 years ago
  7. myko Group Title
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    by the way:int( rcos r) it's done by integration by parts

    • 2 years ago
  8. allsmiles Group Title
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    can't I do substitution

    • 2 years ago
  9. myko Group Title
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    you can try

    • 2 years ago
  10. allsmiles Group Title
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    haha I just did and it didn't work, alright thanks again!

    • 2 years ago
  11. myko Group Title
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    if you have problems look here, :) http://en.wikipedia.org/wiki/Integration_by_parts

    • 2 years ago
  12. myko Group Title
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    there exacly you example

    • 2 years ago
  13. myko Group Title
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    your*

    • 2 years ago
  14. allsmiles Group Title
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    Yeah I got it now, thanks a lot for your help!

    • 2 years ago
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