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dietrich_harmon
What is the factored form of the expression? s4 – 16 A. (s - 2)2(s + 2)2 B. (s - 2)(s + 2) C. (s - i)(s + i)(s - 2)(s + 2) D. (s - 2i)(s + 2i)(s - 2)(s + 2)
thiink about the problem this way (s^2)^2 - (4)^2 now you have the difference of 2 squares..
\[(s ^{2}-4)(s ^{2}+4)\]
thats the start... after that you will have pair of brackets containing the difference of 2 squares... so factor that as well
option d correct only simplify \[a ^{2}-b ^{2}=(a+b)(a-b) also using i ^{2}=-1\]
then we get (s-2i)(s+2i)(s-2)(s+2)