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RonrickDaano
Group Title
Given that 2.004<log10101<2.005, how many digits are there in the decimal representation of 101101?
Clarification: The decimal representation of 210 is 210=1024, which has 4 digits.
 2 years ago
 2 years ago
RonrickDaano Group Title
Given that 2.004<log10101<2.005, how many digits are there in the decimal representation of 101101? Clarification: The decimal representation of 210 is 210=1024, which has 4 digits.
 2 years ago
 2 years ago

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Shadowys Group TitleBest ResponseYou've already chosen the best response.0
10101 in binary? then 210 shouldn't be binary....
 2 years ago

jishan Group TitleBest ResponseYou've already chosen the best response.0
( 101101)base2=( 45)decimal binary no always power of 2 therefore 2power 6= 64 hence 6 digit req..
 2 years ago

shubham.bagrecha Group TitleBest ResponseYou've already chosen the best response.0
brilliant!
 one year ago

shubham.bagrecha Group TitleBest ResponseYou've already chosen the best response.0
it is 101^101
 one year ago

shubham.bagrecha Group TitleBest ResponseYou've already chosen the best response.0
@ParthKohli
 one year ago

shubham.bagrecha Group TitleBest ResponseYou've already chosen the best response.0
help!
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Well, find out \(\log_{10} 101^{101}\)
 one year ago

shubham.bagrecha Group TitleBest ResponseYou've already chosen the best response.0
then
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
That's it.
 one year ago

shubham.bagrecha Group TitleBest ResponseYou've already chosen the best response.0
that is the no. of digits?
 one year ago

shubham.bagrecha Group TitleBest ResponseYou've already chosen the best response.0
how log can help calculate no. of digits?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Yes, it does. Try it!
 one year ago

shubham.bagrecha Group TitleBest ResponseYou've already chosen the best response.0
202 is incorrect
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
You also have to consider the assumptions given in your question.
 one year ago

shubham.bagrecha Group TitleBest ResponseYou've already chosen the best response.0
what else is given?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Actually, you have to find \(1 + \log_{10} 101^{101}\). Don't write in the answer, let me check first.
 one year ago

shubham.bagrecha Group TitleBest ResponseYou've already chosen the best response.0
ok
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
You can do something else while I check. Thanks :)
 one year ago

shubham.bagrecha Group TitleBest ResponseYou've already chosen the best response.0
ok
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
And so I was correct :)
 one year ago

shubham.bagrecha Group TitleBest ResponseYou've already chosen the best response.0
why add 1?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Because the number of digits in \(100\) is not \(\log_{10} 100\), but it's \(1+\log_{10}100\)
 one year ago

shubham.bagrecha Group TitleBest ResponseYou've already chosen the best response.0
ok thanks
 one year ago

shubham.bagrecha Group TitleBest ResponseYou've already chosen the best response.0
can it be used for counting digits in any expansion?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Expansion? You mean number base?
 one year ago

shubham.bagrecha Group TitleBest ResponseYou've already chosen the best response.0
like this type of question
 one year ago

shubham.bagrecha Group TitleBest ResponseYou've already chosen the best response.0
ok thanks
 one year ago
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