A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
suppose you have a convex lens with focal length 17 cm.if an object is place p cm away from the lens,its image will appear to be q cm from the lens, where p,q and 17 cm are related by the following equation:
1/17=1/p + 1/q
This is known as lens equation.
what the rate of change of p with respect to q?
anonymous
 3 years ago
suppose you have a convex lens with focal length 17 cm.if an object is place p cm away from the lens,its image will appear to be q cm from the lens, where p,q and 17 cm are related by the following equation: 1/17=1/p + 1/q This is known as lens equation. what the rate of change of p with respect to q?

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You might want to differentiate this. Did you attempt it?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0differentiate all or what? i don't know..please help me

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Differentiate the \(\frac{1}{17}=\frac{1}{p}+\frac{1}{q}\) wrt to q. Like this: \(\frac{d(\frac{1}{17})}{dq}=\frac{d(p^{1})}{dq}+\frac{d(q^{1})}{dq}\) \(0=p^{2}p'q^{2}\) So \(p'= \frac{p^2}{q^2}\) Now sub \(p=(\frac{1}{17}\frac{1}{q})^{1}\) into that and you've got it.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes i got it..thanks a lot..:)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.