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DLS
 3 years ago
Let (2,1) be a point on line 3x+4y=2.Find the point at distance of 5 units on the line from the given point?
DLS
 3 years ago
Let (2,1) be a point on line 3x+4y=2.Find the point at distance of 5 units on the line from the given point?

This Question is Closed

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1\(\large{distance}(ax+by+c=0, (x_0, y_0)) = \frac{ax_0+by_0+c}{\sqrt{a^2+b^2}}\)

DLS
 3 years ago
Best ResponseYou've already chosen the best response.2How can we solve this using parametric form?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1i didn't get your question actually, (2,1) does NOT lie on that line. can u draw a figure or something ?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1Distance between points (x1,y1) and (x2,y2) is \(\huge d=\sqrt{(x_1x_2)^2+(y_1y_2)^2}\)

DLS
 3 years ago
Best ResponseYou've already chosen the best response.2\[\frac{xx1}{\cos \Theta} = \frac{yy1}{\sin \Theta} = r\]

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1but,(2,1) does NOT lie on that line.

DLS
 3 years ago
Best ResponseYou've already chosen the best response.23x+4y+66=2 3(x2)=4(y+1) \[\frac{x2}{4/5}\frac{y+1}{3/5}=r=+5 or 5\]

DLS
 3 years ago
Best ResponseYou've already chosen the best response.2why did we divide by sqrt of a^2+b^2 that is 5? They say by doing that we get sin Theta and cos Theta

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1so that the two numbers(4/5 and 3/5) here satisfy, a^2+b^2=1 which is the property of sin and cos

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1so we can take one as 4/5 and other as 3/5

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1like here u take cos t =4/5, sin t = 3/5

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1if you did not divide by 5, then 4^2+3^2 does not equal 1 so u cannot take cos t=4, and sin t =3

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1its like normalization....

DLS
 3 years ago
Best ResponseYou've already chosen the best response.2i know that but why did we divide by sqrt of a^2+b^2 only?

DLS
 3 years ago
Best ResponseYou've already chosen the best response.2any special logic or anything?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1for any 2 numbers \(\large(\frac{a}{\sqrt{a^2+b^2}})^2+(\frac{b}{\sqrt{a^2+b^2}})^2=1\) so there is a need to divide by sqrt(....)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1what else can u divide those numbers by, to get their sum of squares =1 ?
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