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psk981
 2 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{C}^{} F.T ds \] for a vector field F=x ^{2}iyj

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1along the straight line? what is T ?

experimentX
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1352897206497:dw

psk981
 2 years ago
Best ResponseYou've already chosen the best response.0how did u get r(t) i know you used the points but why did u pick t for the second set of points

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1the t used is just a variable scalar to stretch the vector to all point along the line from the point used to anchor it to the line

psk981
 2 years ago
Best ResponseYou've already chosen the best response.0so how would i find F. dr/dt where T=dr/dt?

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1i dont recall the flow stuff to clearly, but does this look familiar? \[\frac{dr}{dt}=\frac{dr}{dx}\frac{dx}{dt}+\frac{dr}{dy}\frac{dy}{dt}\]

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1this is a line integral right?

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1http://tutorial.math.lamar.edu/Classes/CalcIII/LineIntegralsVectorFields.aspx ive always found this to be a rather good read. so im going over it

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1i believe we also need r'

psk981
 2 years ago
Best ResponseYou've already chosen the best response.0how would i get it i know its a derivative would it be r(t)= i3j

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1then thats its; dot F and r' together to get a scalar equation to integrate right?

psk981
 2 years ago
Best ResponseYou've already chosen the best response.0i am not sure abt the dr/dt part

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1r= <2t, 43t> r'= <(2t)', (43t)'> r'= <1, 3>

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1F=<(2t)^2 ,4+3t> dot r'=< 1 , 3 >  (2t^2)+129t

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1got me ^2 in the wrong side ... :/

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1the line is from t=0 to t=1 giving us\[\int_{0}^{1}4t^2+4t9t+12~dt\]\[\int_{0}^{1}t^25t+8~dt\]

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1do you have an answer key to check with by chance?

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1well, weve followed the simple directions from pauls site; so it should be good ;)

psk981
 2 years ago
Best ResponseYou've already chosen the best response.0these vector fields so confusing

psk981
 2 years ago
Best ResponseYou've already chosen the best response.0i have another vector question

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1the Force equation gives us the force at each for each x,y point along the line the lines vector equation gives us the x and y values along the path F(r) is just defining the forces along the path; dotting with r' tho has me a little baffled at an explanation at the moment tho ;)

psk981
 2 years ago
Best ResponseYou've already chosen the best response.0how do i draw a vector field

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1for each lattice point on a graph you draw a little arrow indicating the direction and magnitude of the vector associated with the values of x and y (or whatever reference frame your using) at that point
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