lopus
  • lopus
to melt a snowball, with initial radius of 12 cm, its radius decreases at a constant rate of 0.5 cm / hr. if it starts to melt when t = 0, the rate of decline in the volume of the snowball after 12 hours is: the answer is : A. 50pi cm3/hr B. 60 pi .. C. 72 pi .. D. 120pi .. E. 144pi ..
Mathematics
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
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lopus
  • lopus
\[v=\frac{ 4 }{ 3 }*R ^{3}\]
anonymous
  • anonymous
\[V=\frac{4}{3}\pi r^3\] if i remember correctly taking derivatives you get \[V'=4\pi r^2r'\]
anonymous
  • anonymous
you are told \(r'=-0.5\) and you need \(V'\)

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anonymous
  • anonymous
oh and i guess after 12 hours \(r=6\) so make the replacements and you are done
lopus
  • lopus
why 6? can you explain me
lopus
  • lopus
is 4pi(36)*0.5 = 72
lopus
  • lopus
why not 4pi(0.5*12)^2=144
anonymous
  • anonymous
\(r=6\) cm because it starts at 12 cm and decreases at a rate of 0.5 cm per hour
anonymous
  • anonymous
do you get this, OP?
lopus
  • lopus
is 4pi(36)*0.5 = 72 why not 4pi(0.5*12)^2=144
anonymous
  • anonymous
|dw:1353259541168:dw|
lopus
  • lopus
why not 4pi(0.5*12)^2=144

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