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anonymous
 3 years ago
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anonymous
 3 years ago
prove this:

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{\sqrt{18}  4}  \sqrt{\sqrt{38}  6} > 0\]

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1square and rearrange until you get rid of radicals

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i did that and got an answer. but i also moved the negated radical to the right of > before solving and also got a different answer. now i wonder which is correct.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can someone help please?

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1353051057058:dw

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1353051257753:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i think you made a mistake. but i solved it with your help @experimentX can you please check if this is correct? https://pbs.twimg.com/media/A75awD_CMAAK9Uu.jpg:large

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1the photo doesn't load well .. seems correct!!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0how about this image? @experimentX

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1yeah that's correct ... i made mistake up there.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0did you see my image correctly?

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1yeah!! i had problem with internet previously.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok thank you very much. can you image i lost 4 points for this question in a test?! haha. i'm happy i can finish it off if it should come my way again

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1all right ... i hope you can so similar problems.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0with your help, now yes!
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