Find the center, vertices, and foci of the ellipse with equation 2x^2 + 9y^2 = 18

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Find the center, vertices, and foci of the ellipse with equation 2x^2 + 9y^2 = 18

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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|dw:1352907058035:dw| details are given here http://en.wikipedia.org/wiki/Ellipse#Focus
but what would the next step be?? @experimentX

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Other answers:

find the eccentricity ... the vertex is given by 'a' and the foci are given by 'a times eccentricity'
2x^2 - 9y^2 = 18 Dividing by 18 on both sides, x^2/9 - y^2/2 = 1 which is a hyperbola and that too a standard one. Please refer Math class XI for further details on this topic. Source(s): I was a JEE topper :-)

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