A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Let z be a complex number than locus represented by iz1 + zi = 2 is : a) a line , b) a circle , c) a pair of straight lines, d) a parabola
anonymous
 3 years ago
Let z be a complex number than locus represented by iz1 + zi = 2 is : a) a line , b) a circle , c) a pair of straight lines, d) a parabola

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i think it is a l ine

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Sorry for the mistake in the question earlier , the modified quest. is in the post itself. I seek help from the users presented here as soon as possible,

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@satellite73 rethink please :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0scratch that, i think it is a region bounded by two line

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0OK so since it is IIT based so I will say : There may be no answers or multiple answers

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Well yes @satellite73 has the answer, it will be a line \(\textbf{segment}\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0But I am half way stuck @satellite73 , can you show your work, I think @experimentX is also writing his work :)

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.0put z = x + iy you would get, \[ \sqrt{(y1)^2 + x^2} + \sqrt{x^2 + (y1)^2} = 2\] http://www.wolframalpha.com/input/?i=plot+ \sqrt{%28y1%29^2+%2B+x^2}+%2B+\sqrt{x^2+%2B+%28y1%29^2}+%3D+2 guess it is a circle

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What I can do is : \[\large{(iz1) + (zi) =2}\] \[\large{i(z+i)+zi=2}\] \[\large{iz+i + zi = 2 }\] \[\large{z+i + zi = 2}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352908224557:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So am I right in my way @experimentX @satellite73 ? (Since I am only given 54 seconds to do these type of questions so I prefer to use shortcuts that is here : not putting z = x + iy , my opinion said , yes ! x will be equal to zero if we are going to solve it! )

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i did it the donkey way but your way is much much better i think

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.0\(z=i\) is a solution

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh! No problem, sometimes we learn a lot from "that say donkey ways" , thanks for your time : @experimentX @satellite73

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.0no wonder it does not show in x's and y's

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.0\(z=i\) is also a solution

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.0the solution is a line segment from +i to i

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.0\[\large{z+i + zi = 2}\] change of variables shift along the complex plane \[w=z+i\] \[{w + w2i = 2}\]

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352909335544:dw

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.0circle + circle = circle?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.