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Let z be a complex number than locus represented by iz1 + zi = 2 is : a) a line , b) a circle , c) a pair of straight lines, d) a parabola
 one year ago
 one year ago
Let z be a complex number than locus represented by iz1 + zi = 2 is : a) a line , b) a circle , c) a pair of straight lines, d) a parabola
 one year ago
 one year ago

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satellite73Best ResponseYou've already chosen the best response.1
i think it is a l ine
 one year ago

SheldonEinsteinBest ResponseYou've already chosen the best response.0
Sorry for the mistake in the question earlier , the modified quest. is in the post itself. I seek help from the users presented here as soon as possible,
 one year ago

SheldonEinsteinBest ResponseYou've already chosen the best response.0
@satellite73 rethink please :)
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
scratch that, i think it is a region bounded by two line
 one year ago

SheldonEinsteinBest ResponseYou've already chosen the best response.0
OK so since it is IIT based so I will say : There may be no answers or multiple answers
 one year ago

SheldonEinsteinBest ResponseYou've already chosen the best response.0
Well yes @satellite73 has the answer, it will be a line \(\textbf{segment}\)
 one year ago

SheldonEinsteinBest ResponseYou've already chosen the best response.0
But I am half way stuck @satellite73 , can you show your work, I think @experimentX is also writing his work :)
 one year ago

experimentXBest ResponseYou've already chosen the best response.0
put z = x + iy you would get, \[ \sqrt{(y1)^2 + x^2} + \sqrt{x^2 + (y1)^2} = 2\] http://www.wolframalpha.com/input/?i=plot+\sqrt{%28y1%29^2+%2B+x^2}+%2B+\sqrt{x^2+%2B+%28y1%29^2}+%3D+2 guess it is a circle
 one year ago

SheldonEinsteinBest ResponseYou've already chosen the best response.0
What I can do is : \[\large{(iz1) + (zi) =2}\] \[\large{i(z+i)+zi=2}\] \[\large{iz+i + zi = 2 }\] \[\large{z+i + zi = 2}\]
 one year ago

SheldonEinsteinBest ResponseYou've already chosen the best response.0
dw:1352908224557:dw
 one year ago

SheldonEinsteinBest ResponseYou've already chosen the best response.0
So am I right in my way @experimentX @satellite73 ? (Since I am only given 54 seconds to do these type of questions so I prefer to use shortcuts that is here : not putting z = x + iy , my opinion said , yes ! x will be equal to zero if we are going to solve it! )
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
i did it the donkey way but your way is much much better i think
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
\(z=i\) is a solution
 one year ago

SheldonEinsteinBest ResponseYou've already chosen the best response.0
Oh! No problem, sometimes we learn a lot from "that say donkey ways" , thanks for your time : @experimentX @satellite73
 one year ago

experimentXBest ResponseYou've already chosen the best response.0
z <= 1 and z = i
 one year ago

experimentXBest ResponseYou've already chosen the best response.0
no wonder it does not show in x's and y's
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
\(z=i\) is also a solution
 one year ago

experimentXBest ResponseYou've already chosen the best response.0
the solution is a line segment from +i to i
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
\[\large{z+i + zi = 2}\] change of variables shift along the complex plane \[w=z+i\] \[{w + w2i = 2}\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
dw:1352909335544:dw
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
circle + circle = circle?
 one year ago
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