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anonymous
 4 years ago
Let z be a complex number than locus represented by iz1 + zi = 2 is : a) a line , b) a circle , c) a pair of straight lines, d) a parabola
anonymous
 4 years ago
Let z be a complex number than locus represented by iz1 + zi = 2 is : a) a line , b) a circle , c) a pair of straight lines, d) a parabola

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think it is a l ine

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sorry for the mistake in the question earlier , the modified quest. is in the post itself. I seek help from the users presented here as soon as possible,

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@satellite73 rethink please :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0scratch that, i think it is a region bounded by two line

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0OK so since it is IIT based so I will say : There may be no answers or multiple answers

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well yes @satellite73 has the answer, it will be a line \(\textbf{segment}\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But I am half way stuck @satellite73 , can you show your work, I think @experimentX is also writing his work :)

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.0put z = x + iy you would get, \[ \sqrt{(y1)^2 + x^2} + \sqrt{x^2 + (y1)^2} = 2\] http://www.wolframalpha.com/input/?i=plot+ \sqrt{%28y1%29^2+%2B+x^2}+%2B+\sqrt{x^2+%2B+%28y1%29^2}+%3D+2 guess it is a circle

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What I can do is : \[\large{(iz1) + (zi) =2}\] \[\large{i(z+i)+zi=2}\] \[\large{iz+i + zi = 2 }\] \[\large{z+i + zi = 2}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1352908224557:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So am I right in my way @experimentX @satellite73 ? (Since I am only given 54 seconds to do these type of questions so I prefer to use shortcuts that is here : not putting z = x + iy , my opinion said , yes ! x will be equal to zero if we are going to solve it! )

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i did it the donkey way but your way is much much better i think

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.0\(z=i\) is a solution

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh! No problem, sometimes we learn a lot from "that say donkey ways" , thanks for your time : @experimentX @satellite73

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.0no wonder it does not show in x's and y's

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.0\(z=i\) is also a solution

experimentX
 4 years ago
Best ResponseYou've already chosen the best response.0the solution is a line segment from +i to i

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.0\[\large{z+i + zi = 2}\] change of variables shift along the complex plane \[w=z+i\] \[{w + w2i = 2}\]

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1352909335544:dw

UnkleRhaukus
 4 years ago
Best ResponseYou've already chosen the best response.0circle + circle = circle?
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