A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Calculate the length of AD given AB = 7 cm, AC = 25 cm, and AE = 35.
A. 3.5 cm
B. 5 cm
C. 25 cm
D. 50 cm
anonymous
 4 years ago
Calculate the length of AD given AB = 7 cm, AC = 25 cm, and AE = 35. A. 3.5 cm B. 5 cm C. 25 cm D. 50 cm

This Question is Open

Nubeer
 4 years ago
Best ResponseYou've already chosen the best response.0ok can't figure out this one.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The numbers given in the problem and the diagram you posted don't seem to go with the answer choices. I'm also not sure how to solve this one, but something seems mixed up also...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that's what the choices are for this question /:

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah, I'm not doubting you... I just don't know what to do with the situation.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how did you know to set up a ratio of the short portion of one leg to the whole length of the other leg?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0There is a good website explaining all this. Look at example 2: http://www.pinkmonkey.com/studyguides/subjects/geometry/chap7/g0707701.asp

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It goes with figure 7.21b which is the figure on the right.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0They use different letters for their points, so you have to rewrite the letters, but its almost the exact same problem.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It's corresponding sides of similar triangles

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Very nice... I was thinking ratios for similar triangles, but I didn't catch the fact that the "slanted" base and midsections would cause the ratios to be different. Thanks for the link... my goal of "learn something new daily" has been met :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0This is sort of obscure, but geometry is way underrated. Excellent way to build logic.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0A little bit more about the cyclic quadrilateral:

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0In that website that I referenced, they alluded to properties of the cyclic quadrilateral and that might have left some here a little empty like it was magic "balck box" stuff. One really has to come to grips with the cyclic quadrilateral first, so here's another website that explains why I could use that ratio: http://www.onlinemathlearning.com/quadrilateralcircle.html

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It's a video (near the bottom) called "Proof for the Cyclic Quadrilateral"
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.