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alainabbyboo22

Calculate the length of AD given AB = 7 cm, AC = 25 cm, and AE = 35. A. 3.5 cm B. 5 cm C. 25 cm D. 50 cm

  • one year ago
  • one year ago

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  1. alainabbyboo22
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    • one year ago
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  2. alainabbyboo22
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    @nubeer

    • one year ago
  3. nubeer
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    ok can't figure out this one.

    • one year ago
  4. nubeer
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    sorry.

    • one year ago
  5. JakeV8
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    The numbers given in the problem and the diagram you posted don't seem to go with the answer choices. I'm also not sure how to solve this one, but something seems mixed up also...

    • one year ago
  6. alainabbyboo22
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    that's what the choices are for this question /:

    • one year ago
  7. JakeV8
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    yeah, I'm not doubting you... I just don't know what to do with the situation.

    • one year ago
  8. tcarroll010
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    AC/AD = AE/AB

    • one year ago
  9. tcarroll010
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    So, AD is 5

    • one year ago
  10. JakeV8
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    how did you know to set up a ratio of the short portion of one leg to the whole length of the other leg?

    • one year ago
  11. tcarroll010
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    There is a good website explaining all this. Look at example 2: http://www.pinkmonkey.com/studyguides/subjects/geometry/chap7/g0707701.asp

    • one year ago
  12. tcarroll010
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    It goes with figure 7.21b which is the figure on the right.

    • one year ago
  13. tcarroll010
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    They use different letters for their points, so you have to rewrite the letters, but its almost the exact same problem.

    • one year ago
  14. tcarroll010
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    It's corresponding sides of similar triangles

    • one year ago
  15. JakeV8
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    Very nice... I was thinking ratios for similar triangles, but I didn't catch the fact that the "slanted" base and midsections would cause the ratios to be different. Thanks for the link... my goal of "learn something new daily" has been met :)

    • one year ago
  16. tcarroll010
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    This is sort of obscure, but geometry is way under-rated. Excellent way to build logic.

    • one year ago
  17. tcarroll010
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    A little bit more about the cyclic quadrilateral:

    • one year ago
  18. tcarroll010
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    In that website that I referenced, they alluded to properties of the cyclic quadrilateral and that might have left some here a little empty like it was magic "balck box" stuff. One really has to come to grips with the cyclic quadrilateral first, so here's another website that explains why I could use that ratio: http://www.onlinemathlearning.com/quadrilateral-circle.html

    • one year ago
  19. tcarroll010
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    It's a video (near the bottom) called "Proof for the Cyclic Quadrilateral"

    • one year ago
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