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alainabbyboo22
 2 years ago
Calculate the length of AD given AB = 7 cm, AC = 25 cm, and AE = 35.
A. 3.5 cm
B. 5 cm
C. 25 cm
D. 50 cm
alainabbyboo22
 2 years ago
Calculate the length of AD given AB = 7 cm, AC = 25 cm, and AE = 35. A. 3.5 cm B. 5 cm C. 25 cm D. 50 cm

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nubeer
 2 years ago
Best ResponseYou've already chosen the best response.0ok can't figure out this one.

JakeV8
 2 years ago
Best ResponseYou've already chosen the best response.0The numbers given in the problem and the diagram you posted don't seem to go with the answer choices. I'm also not sure how to solve this one, but something seems mixed up also...

alainabbyboo22
 2 years ago
Best ResponseYou've already chosen the best response.0that's what the choices are for this question /:

JakeV8
 2 years ago
Best ResponseYou've already chosen the best response.0yeah, I'm not doubting you... I just don't know what to do with the situation.

JakeV8
 2 years ago
Best ResponseYou've already chosen the best response.0how did you know to set up a ratio of the short portion of one leg to the whole length of the other leg?

tcarroll010
 2 years ago
Best ResponseYou've already chosen the best response.3There is a good website explaining all this. Look at example 2: http://www.pinkmonkey.com/studyguides/subjects/geometry/chap7/g0707701.asp

tcarroll010
 2 years ago
Best ResponseYou've already chosen the best response.3It goes with figure 7.21b which is the figure on the right.

tcarroll010
 2 years ago
Best ResponseYou've already chosen the best response.3They use different letters for their points, so you have to rewrite the letters, but its almost the exact same problem.

tcarroll010
 2 years ago
Best ResponseYou've already chosen the best response.3It's corresponding sides of similar triangles

JakeV8
 2 years ago
Best ResponseYou've already chosen the best response.0Very nice... I was thinking ratios for similar triangles, but I didn't catch the fact that the "slanted" base and midsections would cause the ratios to be different. Thanks for the link... my goal of "learn something new daily" has been met :)

tcarroll010
 2 years ago
Best ResponseYou've already chosen the best response.3This is sort of obscure, but geometry is way underrated. Excellent way to build logic.

tcarroll010
 2 years ago
Best ResponseYou've already chosen the best response.3A little bit more about the cyclic quadrilateral:

tcarroll010
 2 years ago
Best ResponseYou've already chosen the best response.3In that website that I referenced, they alluded to properties of the cyclic quadrilateral and that might have left some here a little empty like it was magic "balck box" stuff. One really has to come to grips with the cyclic quadrilateral first, so here's another website that explains why I could use that ratio: http://www.onlinemathlearning.com/quadrilateralcircle.html

tcarroll010
 2 years ago
Best ResponseYou've already chosen the best response.3It's a video (near the bottom) called "Proof for the Cyclic Quadrilateral"
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