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roberto5 Group Title

(x^-2)(y^0) / (x^3)(y^-2) Plug in x = 2 and y = 5 (2^-2)(5^0) / (2^3)(5^-2) 5^0 = 1 since anything to the power of 0 is 1 2^-2 is the same as 1/(2^2) = 1/4 (1/4)(1) / (8)(1/25) = (1/4) / (8/25) = (1/4) x (25/8) = 25/32

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  1. roberto5 Group Title
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    is correct my anwers

    • 2 years ago
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    @ajprincess

    • 2 years ago
  3. roberto5 Group Title
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    @ajprincess is correct my question

    • 2 years ago
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    yup right:)

    • 2 years ago
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    thanks

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    good work:)

    • 2 years ago
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    Were the values of x and y given?

    • 2 years ago
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