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roberto5

  • 3 years ago

a^2-b^2/a^3-b^3

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  1. roberto5
    • 3 years ago
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    a^3-b^3-a^2+b^2 =(a^3-b^3)-(a^2-b^2) =(a-b)(a^2+ab+b^2)-(a-b)(a+b) =(a-b)(a^2+ab+b^2-a-b);

  2. ajprincess
    • 3 years ago
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    Is your question? |dw:1352911124259:dw|

  3. roberto5
    • 3 years ago
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    yes

  4. ajprincess
    • 3 years ago
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    |dw:1352911198398:dw|

  5. roberto5
    • 3 years ago
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    A;a+b/b^2+ab+a^2 b;1/a-b c;0

  6. roberto5
    • 3 years ago
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    i think b;b;1/a-b

  7. ajprincess
    • 3 years ago
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    hmm no

  8. roberto5
    • 3 years ago
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    what do you think @ajprincess

  9. ajprincess
    • 3 years ago
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    cancel the common factors in the numerator and the denominator nd tell me the remaining one

  10. roberto5
    • 3 years ago
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    do you think @ajprincess A;a+b/b^2+ab+a^2

  11. ajprincess
    • 3 years ago
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    yup:)

  12. roberto5
    • 3 years ago
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    sure

  13. ajprincess
    • 3 years ago
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    |dw:1352911687600:dw|

  14. roberto5
    • 3 years ago
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    okey thanks

  15. ajprincess
    • 3 years ago
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    welcome:)

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