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anonymous
 3 years ago
√(9y4)+12√(y2)3√(y6)√(4y4)
anonymous
 3 years ago
√(9y4)+12√(y2)3√(y6)√(4y4)

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Are you trying to simplify?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Are the variables to a power. Ex. 9y^4.....y^2 ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yea. sorry bout that.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So, you are solving for y?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0So I got 3 real y values. and 4 imaginary.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0these are the answers: 8y2 + 9y3 11y2 11y5 2y2 + 9y3

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I didn't get any of those.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I have the answer. Are looking for a simplified version, or for the zeros?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0~((9y^(4)))+12~(y^(2))3~(y^(6))~(4y^(4)) Remove the parentheses. ~(9y^(4))+12~(y^(2))3~(y^(6))~(4y^(4)) Pull all perfect square roots out from under the radical. In this case, remove the 3y^(2) because it is a perfect square. 3y^(2)+12~(y^(2))3~(y^(6))~(4y^(4)) Pull all perfect square roots out from under the radical. In this case, remove the y because it is a perfect square. 3y^(2)+(12*y)3~(y^(6))~(4y^(4)) Multiply 12 by y to get 12y. 3y^(2)+(12y)3~(y^(6))~(4y^(4)) Remove the parentheses around the expression 12y. 3y^(2)+12y3~(y^(6))~(4y^(4)) Pull all perfect square roots out from under the radical. In this case, remove the y^(3) because it is a perfect square. 3y^(2)+12y+(3*y^(3))~(4y^(4)) Multiply 3 by y^(3) to get 3y^(3). 3y^(2)+12y+(3y^(3))~(4y^(4)) Remove the parentheses around the expression 3y^(3). 3y^(2)+12y3y^(3)~(4y^(4)) Pull all perfect square roots out from under the radical. In this case, remove the 2y^(2) because it is a perfect square. 3y^(2)+12y3y^(3)2y^(2) Since 3y^(2) and 2y^(2) are like terms, add 2y^(2) to 3y^(2) to get y^(2). y^(2)+12y3y^(3) Reorder the polynomial y^(2)+12y3y^(3) alphabetically from left to right, starting with the highest order term. 3y^(3)+y^(2)+12y

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0THATS WHAT I GOT TOO!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hmm. Why didn't you post it eariler?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0cause i thought it wasn't the right answer
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