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zordoloomBest ResponseYou've already chosen the best response.0
Are you trying to simplify?
 one year ago

KiArUnsYuBest ResponseYou've already chosen the best response.0
find the exact value
 one year ago

zordoloomBest ResponseYou've already chosen the best response.0
Are the variables to a power. Ex. 9y^4.....y^2 ?
 one year ago

KiArUnsYuBest ResponseYou've already chosen the best response.0
yea. sorry bout that.
 one year ago

zordoloomBest ResponseYou've already chosen the best response.0
So, you are solving for y?
 one year ago

zordoloomBest ResponseYou've already chosen the best response.0
So I got 3 real y values. and 4 imaginary.
 one year ago

KiArUnsYuBest ResponseYou've already chosen the best response.0
these are the answers: 8y2 + 9y3 11y2 11y5 2y2 + 9y3
 one year ago

zordoloomBest ResponseYou've already chosen the best response.0
I didn't get any of those.
 one year ago

zordoloomBest ResponseYou've already chosen the best response.0
I have the answer. Are looking for a simplified version, or for the zeros?
 one year ago

zordoloomBest ResponseYou've already chosen the best response.0
~((9y^(4)))+12~(y^(2))3~(y^(6))~(4y^(4)) Remove the parentheses. ~(9y^(4))+12~(y^(2))3~(y^(6))~(4y^(4)) Pull all perfect square roots out from under the radical. In this case, remove the 3y^(2) because it is a perfect square. 3y^(2)+12~(y^(2))3~(y^(6))~(4y^(4)) Pull all perfect square roots out from under the radical. In this case, remove the y because it is a perfect square. 3y^(2)+(12*y)3~(y^(6))~(4y^(4)) Multiply 12 by y to get 12y. 3y^(2)+(12y)3~(y^(6))~(4y^(4)) Remove the parentheses around the expression 12y. 3y^(2)+12y3~(y^(6))~(4y^(4)) Pull all perfect square roots out from under the radical. In this case, remove the y^(3) because it is a perfect square. 3y^(2)+12y+(3*y^(3))~(4y^(4)) Multiply 3 by y^(3) to get 3y^(3). 3y^(2)+12y+(3y^(3))~(4y^(4)) Remove the parentheses around the expression 3y^(3). 3y^(2)+12y3y^(3)~(4y^(4)) Pull all perfect square roots out from under the radical. In this case, remove the 2y^(2) because it is a perfect square. 3y^(2)+12y3y^(3)2y^(2) Since 3y^(2) and 2y^(2) are like terms, add 2y^(2) to 3y^(2) to get y^(2). y^(2)+12y3y^(3) Reorder the polynomial y^(2)+12y3y^(3) alphabetically from left to right, starting with the highest order term. 3y^(3)+y^(2)+12y
 one year ago

KiArUnsYuBest ResponseYou've already chosen the best response.0
THATS WHAT I GOT TOO!
 one year ago

zordoloomBest ResponseYou've already chosen the best response.0
hmm. Why didn't you post it eariler?
 one year ago

KiArUnsYuBest ResponseYou've already chosen the best response.0
cause i thought it wasn't the right answer
 one year ago
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