## KiArUnsYu 2 years ago √(9y4)+12√(y2)-3√(y6)-√(4y4)

1. zordoloom

Are you trying to simplify?

2. KiArUnsYu

find the exact value

3. zordoloom

Are the variables to a power. Ex. 9y^4.....y^2 ?

4. KiArUnsYu

yea. sorry bout that.

5. zordoloom

So, you are solving for y?

6. zordoloom

So I got 3 real y values. and 4 imaginary.

7. KiArUnsYu

these are the answers: 8y2 + 9y3 11y2 11y5 2y2 + 9y3

8. zordoloom

I didn't get any of those.

9. KiArUnsYu

ugh. stupid math.

10. zordoloom

I have the answer. Are looking for a simplified version, or for the zeros?

11. zordoloom

You still there?

12. KiArUnsYu

simplified

13. zordoloom

~((9y^(4)))+12~(y^(2))-3~(y^(6))-~(4y^(4)) Remove the parentheses. ~(9y^(4))+12~(y^(2))-3~(y^(6))-~(4y^(4)) Pull all perfect square roots out from under the radical. In this case, remove the 3y^(2) because it is a perfect square. 3y^(2)+12~(y^(2))-3~(y^(6))-~(4y^(4)) Pull all perfect square roots out from under the radical. In this case, remove the y because it is a perfect square. 3y^(2)+(12*y)-3~(y^(6))-~(4y^(4)) Multiply 12 by y to get 12y. 3y^(2)+(12y)-3~(y^(6))-~(4y^(4)) Remove the parentheses around the expression 12y. 3y^(2)+12y-3~(y^(6))-~(4y^(4)) Pull all perfect square roots out from under the radical. In this case, remove the y^(3) because it is a perfect square. 3y^(2)+12y+(-3*y^(3))-~(4y^(4)) Multiply -3 by y^(3) to get -3y^(3). 3y^(2)+12y+(-3y^(3))-~(4y^(4)) Remove the parentheses around the expression -3y^(3). 3y^(2)+12y-3y^(3)-~(4y^(4)) Pull all perfect square roots out from under the radical. In this case, remove the 2y^(2) because it is a perfect square. 3y^(2)+12y-3y^(3)-2y^(2) Since 3y^(2) and -2y^(2) are like terms, add -2y^(2) to 3y^(2) to get y^(2). y^(2)+12y-3y^(3) Reorder the polynomial y^(2)+12y-3y^(3) alphabetically from left to right, starting with the highest order term. -3y^(3)+y^(2)+12y

14. KiArUnsYu

THATS WHAT I GOT TOO!

15. zordoloom

hmm. Why didn't you post it eariler?

16. KiArUnsYu

cause i thought it wasn't the right answer

17. zordoloom

I see....