Lukecrayonz
  • Lukecrayonz
cos 4x - cos 2x = 0 Find all solutions to the equation in the interval [0, 2ð). ð, pi/3 2pi/3 4pi/3 5pi/3, 0? Is that correct?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
ganeshie8
  • ganeshie8
\(\cos^4 x - \cos^2x = 0\) is the equation like above ?
Lukecrayonz
  • Lukecrayonz
No, Cos(4x)-cos(2x)=0
Lukecrayonz
  • Lukecrayonz
@ganeshie8 no idea?:(

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

ganeshie8
  • ganeshie8
could u show me ur work
Lukecrayonz
  • Lukecrayonz
cosx=cos(x+2kpi) Apply Cos C - Cos D formula Cos C - Cos D = 2sin(C+D)/2 Sin(D-C)/2
Lukecrayonz
  • Lukecrayonz
So 0, pi/3, 2pi/3, 4pi/3, 5pi/3 and ð
Lukecrayonz
  • Lukecrayonz
@anas2000 can you help?:D
ganeshie8
  • ganeshie8
hmm that doesnt help me
Lukecrayonz
  • Lukecrayonz
@UnkleRhaukus @robtobey
ganeshie8
  • ganeshie8
cos 4 x - cos 2 x = 0 2cos^2 2x-1 - cos 2x = 0 2u^2 -u -1 = 0 (u-1)(2u+1) = 0 u = 1; u = -1/2 cos 2x = 1 ; cos 2x = -1/2 2x = 0 ; 2x = pi-pi/3, 2x = pi + pi/3 x = 0 + npi; x = pi/3 + npi, x = 2pi/3 + npi x = 0, pi; x = pi/3, 4pi/3, x = 2pi/3, 5pi/3 so solutions will be : x = 0, pi/3, 2pi/3, 4pi/3, 5pi/3, pi looks you got the same solutions wid very less effort... !
Lukecrayonz
  • Lukecrayonz
Thank you! Haha
ganeshie8
  • ganeshie8
np... yw :) good work !

Looking for something else?

Not the answer you are looking for? Search for more explanations.