anonymous
  • anonymous
Find a parametrization of the surface Σ. Σ is the part of a cylinder x^2+y^2=1 that lies between the planes z=-1 and z=1.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
|dw:1352924458586:dw|
anonymous
  • anonymous
I'm not sure what you mean by parametrise
anonymous
  • anonymous
Meaning put it into parametric form.

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anonymous
  • anonymous
OK. Forget about the z for a minute \[f(t)=cost \hat{x}+sint \hat{y} \] Is the circle
anonymous
  • anonymous
\[0
anonymous
  • anonymous
Gotcha. Im mostly fine with finding. x=rcos(theta) y=rsin(theta). Im not sure how to find z though.
anonymous
  • anonymous
Now, to include the z co-ordinate:\[cost \hat{x}+sint \hat{x}+(\frac{t}{\pi}-1)\hat{z}\] \[ 0
anonymous
  • anonymous
Hmmm, not 100% sure how you go to that point. Could you break it down for me?
anonymous
  • anonymous
Mainly, where did t/pi-1 come from? And what goes into t? The z coordinate says the answer is simply 'zk'
anonymous
  • anonymous
Because \[t=0, (\frac{0}{\pi}-1))=-1\] \[t=0, (\frac{2 \pi}{\pi}-1))=1\]
anonymous
  • anonymous
Hmmm I think I get it a little more now. :/ Still really murky on it though. the way I learned it was to just plug your parametrized x and y back into an equation with z in it and you find your z that way. Ehhh.
anonymous
  • anonymous
I really don't think I even understand the basic concept of this section to be honest.
anonymous
  • anonymous
It certainty doesn't help that I was incorrect. What I actually coded for was|dw:1352927439044:dw|
anonymous
  • anonymous
That is, a spiral rather than a full curve
anonymous
  • anonymous
http://tutorial.math.lamar.edu/Classes/CalcIII/ParametricSurfaces.aspx There's cylinder in there. I'll explain if more help needed, sorry for mistake earlier

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