Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Find a parametrization of the surface Σ. Σ is the part of a cylinder x^2+y^2=1 that lies between the planes z=-1 and z=1.

See more answers at
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer


To see the expert answer you'll need to create a free account at Brainly

I'm not sure what you mean by parametrise
Meaning put it into parametric form.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

OK. Forget about the z for a minute \[f(t)=cost \hat{x}+sint \hat{y} \] Is the circle
Gotcha. Im mostly fine with finding. x=rcos(theta) y=rsin(theta). Im not sure how to find z though.
Now, to include the z co-ordinate:\[cost \hat{x}+sint \hat{x}+(\frac{t}{\pi}-1)\hat{z}\] \[ 0
Hmmm, not 100% sure how you go to that point. Could you break it down for me?
Mainly, where did t/pi-1 come from? And what goes into t? The z coordinate says the answer is simply 'zk'
Because \[t=0, (\frac{0}{\pi}-1))=-1\] \[t=0, (\frac{2 \pi}{\pi}-1))=1\]
Hmmm I think I get it a little more now. :/ Still really murky on it though. the way I learned it was to just plug your parametrized x and y back into an equation with z in it and you find your z that way. Ehhh.
I really don't think I even understand the basic concept of this section to be honest.
It certainty doesn't help that I was incorrect. What I actually coded for was|dw:1352927439044:dw|
That is, a spiral rather than a full curve There's cylinder in there. I'll explain if more help needed, sorry for mistake earlier

Not the answer you are looking for?

Search for more explanations.

Ask your own question