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whadduptori
Group Title
Use the quadratic formula to solve the equation?
4x2 – 6x – 10 = 0 is anybody able to show me work?
 2 years ago
 2 years ago
whadduptori Group Title
Use the quadratic formula to solve the equation? 4x2 – 6x – 10 = 0 is anybody able to show me work?
 2 years ago
 2 years ago

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Rezz5 Group TitleBest ResponseYou've already chosen the best response.1
the quadratic formula is b (±)Sqrt[b4ac]/2a\[b \pm \frac{ \sqrt{b4ac}}{ 2a}\]
 2 years ago

Rezz5 Group TitleBest ResponseYou've already chosen the best response.1
where ax^2 +bx +c just substitute and you will get your answer.
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
\[\Large x = \frac{b\pm\sqrt{b^24ac}}{2a}\] \[\Large x = \frac{(6)\pm\sqrt{(6)^24(4)(10)}}{2(4)}\] \[\Large x = \frac{6\pm\sqrt{36(160)}}{8}\] I'll let you finish.
 2 years ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.0
I have all that work! I just get confused with the last part? like would i subtract 36(160)
 2 years ago

Rezz5 Group TitleBest ResponseYou've already chosen the best response.1
36160? well double negative is positive, so? 36+160
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
36(160) is the same as 36+160
 2 years ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.0
so it would become 196?
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
it would
 2 years ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.0
dw:1352933217966:dw
 2 years ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.0
so would that be the answer?
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
you can keep going and there's a + between the 6 and square root
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
you should have \[\Large x = \frac{6\pm\sqrt{196}}{8}\] but you can keep going
 2 years ago

Rezz5 Group TitleBest ResponseYou've already chosen the best response.1
(6*14)/8 =(3*14)/4 =(3*7)/2 =21/2
 2 years ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.0
yes i have that!
 2 years ago

Rezz5 Group TitleBest ResponseYou've already chosen the best response.1
okay, what is wrong?
 2 years ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.0
wait where did you get the 6*14/8
 2 years ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
the square root of 196 is 14, so... \[\Large x = \frac{6\pm\sqrt{196}}{8}\] becomes \[\Large x = \frac{6\pm14}{8}\]
 2 years ago

Rezz5 Group TitleBest ResponseYou've already chosen the best response.1
above is very clear and correct, so first you do the plus sign which is (6+14)/8 this is ONE OF YOUR x's the you do (614)/8 this is your other x value so your x values are: 5/2 and 1
 2 years ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.0
THank you so much! I didnt know how to find that! but you just made it clear for me! thank you both for your help! (:
 2 years ago

Rezz5 Group TitleBest ResponseYou've already chosen the best response.1
your most welcome,
 2 years ago
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