A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Use the quadratic formula to solve the equation?
4x2 – 6x – 10 = 0 is anybody able to show me work?
anonymous
 3 years ago
Use the quadratic formula to solve the equation? 4x2 – 6x – 10 = 0 is anybody able to show me work?

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the quadratic formula is b (±)Sqrt[b4ac]/2a\[b \pm \frac{ \sqrt{b4ac}}{ 2a}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0where ax^2 +bx +c just substitute and you will get your answer.

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1\[\Large x = \frac{b\pm\sqrt{b^24ac}}{2a}\] \[\Large x = \frac{(6)\pm\sqrt{(6)^24(4)(10)}}{2(4)}\] \[\Large x = \frac{6\pm\sqrt{36(160)}}{8}\] I'll let you finish.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I have all that work! I just get confused with the last part? like would i subtract 36(160)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.036160? well double negative is positive, so? 36+160

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.136(160) is the same as 36+160

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so it would become 196?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1352933217966:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so would that be the answer?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1you can keep going and there's a + between the 6 and square root

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1you should have \[\Large x = \frac{6\pm\sqrt{196}}{8}\] but you can keep going

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0(6*14)/8 =(3*14)/4 =(3*7)/2 =21/2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0wait where did you get the 6*14/8

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1the square root of 196 is 14, so... \[\Large x = \frac{6\pm\sqrt{196}}{8}\] becomes \[\Large x = \frac{6\pm14}{8}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0above is very clear and correct, so first you do the plus sign which is (6+14)/8 this is ONE OF YOUR x's the you do (614)/8 this is your other x value so your x values are: 5/2 and 1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0THank you so much! I didnt know how to find that! but you just made it clear for me! thank you both for your help! (:
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.