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 2 years ago
Use the quadratic formula to solve the equation?
4x2 – 6x – 10 = 0 is anybody able to show me work?
 2 years ago
Use the quadratic formula to solve the equation? 4x2 – 6x – 10 = 0 is anybody able to show me work?

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Rezz5
 2 years ago
Best ResponseYou've already chosen the best response.1the quadratic formula is b (±)Sqrt[b4ac]/2a\[b \pm \frac{ \sqrt{b4ac}}{ 2a}\]

Rezz5
 2 years ago
Best ResponseYou've already chosen the best response.1where ax^2 +bx +c just substitute and you will get your answer.

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.0\[\Large x = \frac{b\pm\sqrt{b^24ac}}{2a}\] \[\Large x = \frac{(6)\pm\sqrt{(6)^24(4)(10)}}{2(4)}\] \[\Large x = \frac{6\pm\sqrt{36(160)}}{8}\] I'll let you finish.

whadduptori
 2 years ago
Best ResponseYou've already chosen the best response.0I have all that work! I just get confused with the last part? like would i subtract 36(160)

Rezz5
 2 years ago
Best ResponseYou've already chosen the best response.136160? well double negative is positive, so? 36+160

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.036(160) is the same as 36+160

whadduptori
 2 years ago
Best ResponseYou've already chosen the best response.0so it would become 196?

whadduptori
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1352933217966:dw

whadduptori
 2 years ago
Best ResponseYou've already chosen the best response.0so would that be the answer?

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.0you can keep going and there's a + between the 6 and square root

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.0you should have \[\Large x = \frac{6\pm\sqrt{196}}{8}\] but you can keep going

Rezz5
 2 years ago
Best ResponseYou've already chosen the best response.1(6*14)/8 =(3*14)/4 =(3*7)/2 =21/2

whadduptori
 2 years ago
Best ResponseYou've already chosen the best response.0wait where did you get the 6*14/8

jim_thompson5910
 2 years ago
Best ResponseYou've already chosen the best response.0the square root of 196 is 14, so... \[\Large x = \frac{6\pm\sqrt{196}}{8}\] becomes \[\Large x = \frac{6\pm14}{8}\]

Rezz5
 2 years ago
Best ResponseYou've already chosen the best response.1above is very clear and correct, so first you do the plus sign which is (6+14)/8 this is ONE OF YOUR x's the you do (614)/8 this is your other x value so your x values are: 5/2 and 1

whadduptori
 2 years ago
Best ResponseYou've already chosen the best response.0THank you so much! I didnt know how to find that! but you just made it clear for me! thank you both for your help! (:
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