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whadduptori
Group Title
Use the quadratic formula to solve the equation?
4x2 – 6x – 10 = 0 is anybody able to show me work?
 one year ago
 one year ago
whadduptori Group Title
Use the quadratic formula to solve the equation? 4x2 – 6x – 10 = 0 is anybody able to show me work?
 one year ago
 one year ago

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Rezz5 Group TitleBest ResponseYou've already chosen the best response.1
the quadratic formula is b (±)Sqrt[b4ac]/2a\[b \pm \frac{ \sqrt{b4ac}}{ 2a}\]
 one year ago

Rezz5 Group TitleBest ResponseYou've already chosen the best response.1
where ax^2 +bx +c just substitute and you will get your answer.
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
\[\Large x = \frac{b\pm\sqrt{b^24ac}}{2a}\] \[\Large x = \frac{(6)\pm\sqrt{(6)^24(4)(10)}}{2(4)}\] \[\Large x = \frac{6\pm\sqrt{36(160)}}{8}\] I'll let you finish.
 one year ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.0
I have all that work! I just get confused with the last part? like would i subtract 36(160)
 one year ago

Rezz5 Group TitleBest ResponseYou've already chosen the best response.1
36160? well double negative is positive, so? 36+160
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
36(160) is the same as 36+160
 one year ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.0
so it would become 196?
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
it would
 one year ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.0
dw:1352933217966:dw
 one year ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.0
so would that be the answer?
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
you can keep going and there's a + between the 6 and square root
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
you should have \[\Large x = \frac{6\pm\sqrt{196}}{8}\] but you can keep going
 one year ago

Rezz5 Group TitleBest ResponseYou've already chosen the best response.1
(6*14)/8 =(3*14)/4 =(3*7)/2 =21/2
 one year ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.0
yes i have that!
 one year ago

Rezz5 Group TitleBest ResponseYou've already chosen the best response.1
okay, what is wrong?
 one year ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.0
wait where did you get the 6*14/8
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.0
the square root of 196 is 14, so... \[\Large x = \frac{6\pm\sqrt{196}}{8}\] becomes \[\Large x = \frac{6\pm14}{8}\]
 one year ago

Rezz5 Group TitleBest ResponseYou've already chosen the best response.1
above is very clear and correct, so first you do the plus sign which is (6+14)/8 this is ONE OF YOUR x's the you do (614)/8 this is your other x value so your x values are: 5/2 and 1
 one year ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.0
THank you so much! I didnt know how to find that! but you just made it clear for me! thank you both for your help! (:
 one year ago

Rezz5 Group TitleBest ResponseYou've already chosen the best response.1
your most welcome,
 one year ago
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