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functions:
If f(x)=x^2x+1, solve:
1) f(x+1)
2) f(a)
3) 2f(x)2
4) f(2x)
 one year ago
 one year ago
functions: If f(x)=x^2x+1, solve: 1) f(x+1) 2) f(a) 3) 2f(x)2 4) f(2x)
 one year ago
 one year ago

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Studentc14Best ResponseYou've already chosen the best response.0
CAN I post my answers and someone check it?
 one year ago

jaersynBest ResponseYou've already chosen the best response.0
yeah, lol, just substitute whatever is in f(whatever is in here)
 one year ago

Studentc14Best ResponseYou've already chosen the best response.0
1) x^2+x+3 2) a^2+a+1 (i didn't know if there was any way to simplify this? 3) 2x^2x 4) 2x^22x+1
 one year ago

kmalone99Best ResponseYou've already chosen the best response.1
all wrong, it three right 2 f(x)2?
 one year ago

Studentc14Best ResponseYou've already chosen the best response.0
can you show me how to do them then?
 one year ago

kmalone99Best ResponseYou've already chosen the best response.1
\[1) f(x+1)= (x+1)^{2}(x+1)+1\] \[=(x+1)(x+1)x1+1\] \[=x ^{2}+2x+1x=x ^{2}+x+1\]
 one year ago

Studentc14Best ResponseYou've already chosen the best response.0
Ok, I get #1. I just didn't distribute the negative sign.
 one year ago

kmalone99Best ResponseYou've already chosen the best response.1
2) f(a)=\[f(a)=(a)^{2}(a)+1=a ^{2}+a+1\]
 one year ago

Studentc14Best ResponseYou've already chosen the best response.0
i got 2... i dont see what went wrong with 3 and i dont know how to simplify 4
 one year ago

Studentc14Best ResponseYou've already chosen the best response.0
wait 3 should be 2x^22x?
 one year ago

kmalone99Best ResponseYou've already chosen the best response.1
great now on four you just did not square the 2
 one year ago

Studentc14Best ResponseYou've already chosen the best response.0
oh! so it would be 4x^22x+1 ?
 one year ago

kmalone99Best ResponseYou've already chosen the best response.1
yes great job you get A+
 one year ago

Studentc14Best ResponseYou've already chosen the best response.0
yay! lol I just always make silly simplifying mistakes or I miss a sign or something simple like that. Oh well, thanks very much ^_^
 one year ago
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