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Studentc14

  • 3 years ago

functions: If f(x)=x^2-x+1, solve: 1) f(x+1) 2) f(-a) 3) 2f(x)-2 4) f(2x)

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  1. Studentc14
    • 3 years ago
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    CAN I post my answers and someone check it?

  2. jaersyn
    • 3 years ago
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    you mean "evaluate"?

  3. Studentc14
    • 3 years ago
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    probably, sorry

  4. jaersyn
    • 3 years ago
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    yeah, lol, just substitute whatever is in f(whatever is in here)

  5. kmalone99
    • 3 years ago
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    yes i'll check it

  6. Studentc14
    • 3 years ago
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    1) x^2+x+3 2) -a^2+a+1 (i didn't know if there was any way to simplify this? 3) 2x^2-x 4) 2x^2-2x+1

  7. kmalone99
    • 3 years ago
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    all wrong, it three right 2 f(x)-2?

  8. Studentc14
    • 3 years ago
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    its 2*f(x) -2

  9. Studentc14
    • 3 years ago
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    can you show me how to do them then?

  10. kmalone99
    • 3 years ago
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    yes

  11. kmalone99
    • 3 years ago
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    jaersyn i got this

  12. jaersyn
    • 3 years ago
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    all yours kmalone99

  13. jaersyn
    • 3 years ago
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    <_<

  14. kmalone99
    • 3 years ago
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    \[1) f(x+1)= (x+1)^{2}-(x+1)+1\] \[=(x+1)(x+1)-x-1+1\] \[=x ^{2}+2x+1-x=x ^{2}+x+1\]

  15. Studentc14
    • 3 years ago
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    Ok, I get #1. I just didn't distribute the negative sign.

  16. kmalone99
    • 3 years ago
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    2) f(-a)=\[f(-a)=(-a)^{2}-(-a)+1=a ^{2}+a+1\]

  17. kmalone99
    • 3 years ago
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    now retry 3 and 4

  18. Studentc14
    • 3 years ago
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    i got 2... i dont see what went wrong with 3 and i dont know how to simplify 4

  19. Studentc14
    • 3 years ago
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    wait- 3 should be 2x^2-2x?

  20. kmalone99
    • 3 years ago
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    great now on four you just did not square the 2

  21. Studentc14
    • 3 years ago
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    oh! so it would be 4x^2-2x+1 ?

  22. kmalone99
    • 3 years ago
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    yes great job you get A+

  23. Studentc14
    • 3 years ago
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    yay! lol I just always make silly simplifying mistakes or I miss a sign or something simple like that. Oh well, thanks very much ^_^

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