anonymous
  • anonymous
functions: If f(x)=x^2-x+1, solve: 1) f(x+1) 2) f(-a) 3) 2f(x)-2 4) f(2x)
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
CAN I post my answers and someone check it?
anonymous
  • anonymous
you mean "evaluate"?
anonymous
  • anonymous
probably, sorry

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anonymous
  • anonymous
yeah, lol, just substitute whatever is in f(whatever is in here)
anonymous
  • anonymous
yes i'll check it
anonymous
  • anonymous
1) x^2+x+3 2) -a^2+a+1 (i didn't know if there was any way to simplify this? 3) 2x^2-x 4) 2x^2-2x+1
anonymous
  • anonymous
all wrong, it three right 2 f(x)-2?
anonymous
  • anonymous
its 2*f(x) -2
anonymous
  • anonymous
can you show me how to do them then?
anonymous
  • anonymous
yes
anonymous
  • anonymous
jaersyn i got this
anonymous
  • anonymous
all yours kmalone99
anonymous
  • anonymous
<_<
anonymous
  • anonymous
\[1) f(x+1)= (x+1)^{2}-(x+1)+1\] \[=(x+1)(x+1)-x-1+1\] \[=x ^{2}+2x+1-x=x ^{2}+x+1\]
anonymous
  • anonymous
Ok, I get #1. I just didn't distribute the negative sign.
anonymous
  • anonymous
2) f(-a)=\[f(-a)=(-a)^{2}-(-a)+1=a ^{2}+a+1\]
anonymous
  • anonymous
now retry 3 and 4
anonymous
  • anonymous
i got 2... i dont see what went wrong with 3 and i dont know how to simplify 4
anonymous
  • anonymous
wait- 3 should be 2x^2-2x?
anonymous
  • anonymous
great now on four you just did not square the 2
anonymous
  • anonymous
oh! so it would be 4x^2-2x+1 ?
anonymous
  • anonymous
yes great job you get A+
anonymous
  • anonymous
yay! lol I just always make silly simplifying mistakes or I miss a sign or something simple like that. Oh well, thanks very much ^_^

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