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liliy

find the domain and the inverse of the function: f(x)=ln(x+2)-3

  • one year ago
  • one year ago

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  1. satellite73
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    domain: you can only take the log of a positive number, so start with \(x+2>0\) and solve for \(x) in one step

    • one year ago
  2. satellite73
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    for the inverse, set \[x=\ln(y+2)-3\] and solve for \(y\)

    • one year ago
  3. satellite73
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    this takes three steps \[x=\ln(y+2)-3\] \[x+3=\ln(y+2)\] \[e^{x+3}=y+2\] \[y=e^{x+3}-2\]

    • one year ago
  4. jaersyn
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    Hey satellite, just out of curiosity, what do you do for a living? Sorry to barge in here, but you don't accept messages from non-fans apparently

    • one year ago
  5. liliy
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    so is the domain z+, or R ?

    • one year ago
  6. satellite73
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    neither

    • one year ago
  7. liliy
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    but using an ln graph, anything less than ln(1) is undefined....

    • one year ago
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