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satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0domain: you can only take the log of a positive number, so start with \(x+2>0\) and solve for \(x) in one step

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0for the inverse, set \[x=\ln(y+2)3\] and solve for \(y\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0this takes three steps \[x=\ln(y+2)3\] \[x+3=\ln(y+2)\] \[e^{x+3}=y+2\] \[y=e^{x+3}2\]

jaersyn
 2 years ago
Best ResponseYou've already chosen the best response.0Hey satellite, just out of curiosity, what do you do for a living? Sorry to barge in here, but you don't accept messages from nonfans apparently

liliy
 2 years ago
Best ResponseYou've already chosen the best response.0so is the domain z+, or R ?

liliy
 2 years ago
Best ResponseYou've already chosen the best response.0but using an ln graph, anything less than ln(1) is undefined....
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