anonymous
  • anonymous
PLEASE HELP! (Waiting for an hour..._) Find an equation of the tangent line to the curve at the given point?? \(\ \Large \frac{x^2}{16}-\frac{y^2}{9} =1\) \(\ \Large \text{The point is: } (-5, \frac{9}{4}) \). PLEASE HELP!
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
what math are you in?
anonymous
  • anonymous
AP Calculus BC
anonymous
  • anonymous
what's "BC"

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anonymous
  • anonymous
It's just a level of calculus.... I need to find the derivative of this equation...
anonymous
  • anonymous
solve for y and take the derivative?
anonymous
  • anonymous
This section involves implicit differentiation
anonymous
  • anonymous
ohhh
anonymous
  • anonymous
did you take the derivative?
anonymous
  • anonymous
No I'm still stuck on this problem!!
anonymous
  • anonymous
I don't know how to with those fractions
anonymous
  • anonymous
the derivative of \(\frac{x^2}{16}\) is \(\frac{x}{8}\)
anonymous
  • anonymous
Really? Wouldn't the 16 become a zero?
anonymous
  • anonymous
and the derivative with respect to \(x\) of \(-\frac{y^2}{9}\) is \[-\frac{2y}{9}y'\]
anonymous
  • anonymous
no it is a constant, think \[\frac{x^2}{16}=\frac{1}{16}x^2\]
anonymous
  • anonymous
Am I just using power rule here? I don't need to use quotient rule (that's what I was thinking...?)
anonymous
  • anonymous
@satellite73 I've been getting mixed answers from people. When do I know when I take the derivative of y to have yy' versus just y'???

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