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Study23
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PLEASE HELP! (Waiting for an hour..._) Find an equation of the tangent line to the curve at the given point??
\(\ \Large \frac{x^2}{16}\frac{y^2}{9} =1\)
\(\ \Large \text{The point is: } (5, \frac{9}{4}) \).
PLEASE HELP!
 one year ago
 one year ago
Study23 Group Title
PLEASE HELP! (Waiting for an hour..._) Find an equation of the tangent line to the curve at the given point?? \(\ \Large \frac{x^2}{16}\frac{y^2}{9} =1\) \(\ \Large \text{The point is: } (5, \frac{9}{4}) \). PLEASE HELP!
 one year ago
 one year ago

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jaersyn Group TitleBest ResponseYou've already chosen the best response.0
what math are you in?
 one year ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
AP Calculus BC
 one year ago

jaersyn Group TitleBest ResponseYou've already chosen the best response.0
what's "BC"
 one year ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
It's just a level of calculus.... I need to find the derivative of this equation...
 one year ago

jaersyn Group TitleBest ResponseYou've already chosen the best response.0
solve for y and take the derivative?
 one year ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
This section involves implicit differentiation
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
did you take the derivative?
 one year ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
No I'm still stuck on this problem!!
 one year ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
I don't know how to with those fractions
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
the derivative of \(\frac{x^2}{16}\) is \(\frac{x}{8}\)
 one year ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
Really? Wouldn't the 16 become a zero?
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
and the derivative with respect to \(x\) of \(\frac{y^2}{9}\) is \[\frac{2y}{9}y'\]
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
no it is a constant, think \[\frac{x^2}{16}=\frac{1}{16}x^2\]
 one year ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
Am I just using power rule here? I don't need to use quotient rule (that's what I was thinking...?)
 one year ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
@satellite73 I've been getting mixed answers from people. When do I know when I take the derivative of y to have yy' versus just y'???
 one year ago
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