Study23
PLEASE HELP! (Waiting for an hour..._) Find an equation of the tangent line to the curve at the given point??
\(\ \Large \frac{x^2}{16}-\frac{y^2}{9} =1\)
\(\ \Large \text{The point is: } (-5, \frac{9}{4}) \).
PLEASE HELP!
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jaersyn
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what math are you in?
Study23
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AP Calculus BC
jaersyn
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what's "BC"
Study23
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It's just a level of calculus.... I need to find the derivative of this equation...
jaersyn
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solve for y and take the derivative?
Study23
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This section involves implicit differentiation
jaersyn
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ohhh
anonymous
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did you take the derivative?
Study23
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No I'm still stuck on this problem!!
Study23
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I don't know how to with those fractions
anonymous
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the derivative of \(\frac{x^2}{16}\) is \(\frac{x}{8}\)
Study23
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Really? Wouldn't the 16 become a zero?
anonymous
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and the derivative with respect to \(x\) of \(-\frac{y^2}{9}\) is
\[-\frac{2y}{9}y'\]
anonymous
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no it is a constant, think
\[\frac{x^2}{16}=\frac{1}{16}x^2\]
Study23
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Am I just using power rule here? I don't need to use quotient rule (that's what I was thinking...?)
Study23
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@satellite73 I've been getting mixed answers from people. When do I know when I take the derivative of y to have yy' versus just y'???