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Study23
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PLEASE HELP! (Waiting for an hour..._) Find an equation of the tangent line to the curve at the given point??
\(\ \Large \frac{x^2}{16}\frac{y^2}{9} =1\)
\(\ \Large \text{The point is: } (5, \frac{9}{4}) \).
PLEASE HELP!
 2 years ago
 2 years ago
Study23 Group Title
PLEASE HELP! (Waiting for an hour..._) Find an equation of the tangent line to the curve at the given point?? \(\ \Large \frac{x^2}{16}\frac{y^2}{9} =1\) \(\ \Large \text{The point is: } (5, \frac{9}{4}) \). PLEASE HELP!
 2 years ago
 2 years ago

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jaersyn Group TitleBest ResponseYou've already chosen the best response.0
what math are you in?
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
AP Calculus BC
 2 years ago

jaersyn Group TitleBest ResponseYou've already chosen the best response.0
what's "BC"
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
It's just a level of calculus.... I need to find the derivative of this equation...
 2 years ago

jaersyn Group TitleBest ResponseYou've already chosen the best response.0
solve for y and take the derivative?
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
This section involves implicit differentiation
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
did you take the derivative?
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
No I'm still stuck on this problem!!
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
I don't know how to with those fractions
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
the derivative of \(\frac{x^2}{16}\) is \(\frac{x}{8}\)
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
Really? Wouldn't the 16 become a zero?
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
and the derivative with respect to \(x\) of \(\frac{y^2}{9}\) is \[\frac{2y}{9}y'\]
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
no it is a constant, think \[\frac{x^2}{16}=\frac{1}{16}x^2\]
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
Am I just using power rule here? I don't need to use quotient rule (that's what I was thinking...?)
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
@satellite73 I've been getting mixed answers from people. When do I know when I take the derivative of y to have yy' versus just y'???
 2 years ago
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