## anonymous 3 years ago PLEASE HELP! (Waiting for an hour..._) Find an equation of the tangent line to the curve at the given point?? $$\ \Large \frac{x^2}{16}-\frac{y^2}{9} =1$$ $$\ \Large \text{The point is: } (-5, \frac{9}{4})$$. PLEASE HELP!

1. anonymous

what math are you in?

2. anonymous

AP Calculus BC

3. anonymous

what's "BC"

4. anonymous

It's just a level of calculus.... I need to find the derivative of this equation...

5. anonymous

solve for y and take the derivative?

6. anonymous

This section involves implicit differentiation

7. anonymous

ohhh

8. anonymous

did you take the derivative?

9. anonymous

No I'm still stuck on this problem!!

10. anonymous

I don't know how to with those fractions

11. anonymous

the derivative of $$\frac{x^2}{16}$$ is $$\frac{x}{8}$$

12. anonymous

Really? Wouldn't the 16 become a zero?

13. anonymous

and the derivative with respect to $$x$$ of $$-\frac{y^2}{9}$$ is $-\frac{2y}{9}y'$

14. anonymous

no it is a constant, think $\frac{x^2}{16}=\frac{1}{16}x^2$

15. anonymous

Am I just using power rule here? I don't need to use quotient rule (that's what I was thinking...?)

16. anonymous

@satellite73 I've been getting mixed answers from people. When do I know when I take the derivative of y to have yy' versus just y'???