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anonymous
 4 years ago
PLEASE HELP! (Waiting for an hour..._) Find an equation of the tangent line to the curve at the given point??
\(\ \Large \frac{x^2}{16}\frac{y^2}{9} =1\)
\(\ \Large \text{The point is: } (5, \frac{9}{4}) \).
PLEASE HELP!
anonymous
 4 years ago
PLEASE HELP! (Waiting for an hour..._) Find an equation of the tangent line to the curve at the given point?? \(\ \Large \frac{x^2}{16}\frac{y^2}{9} =1\) \(\ \Large \text{The point is: } (5, \frac{9}{4}) \). PLEASE HELP!

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what math are you in?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It's just a level of calculus.... I need to find the derivative of this equation...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0solve for y and take the derivative?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0This section involves implicit differentiation

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0did you take the derivative?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No I'm still stuck on this problem!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I don't know how to with those fractions

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the derivative of \(\frac{x^2}{16}\) is \(\frac{x}{8}\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Really? Wouldn't the 16 become a zero?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and the derivative with respect to \(x\) of \(\frac{y^2}{9}\) is \[\frac{2y}{9}y'\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no it is a constant, think \[\frac{x^2}{16}=\frac{1}{16}x^2\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Am I just using power rule here? I don't need to use quotient rule (that's what I was thinking...?)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@satellite73 I've been getting mixed answers from people. When do I know when I take the derivative of y to have yy' versus just y'???
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