Study23 3 years ago PLEASE HELP! (Waiting for an hour..._) Find an equation of the tangent line to the curve at the given point?? $$\ \Large \frac{x^2}{16}-\frac{y^2}{9} =1$$ $$\ \Large \text{The point is: } (-5, \frac{9}{4})$$. PLEASE HELP!

1. jaersyn

what math are you in?

2. Study23

AP Calculus BC

3. jaersyn

what's "BC"

4. Study23

It's just a level of calculus.... I need to find the derivative of this equation...

5. jaersyn

solve for y and take the derivative?

6. Study23

This section involves implicit differentiation

7. jaersyn

ohhh

8. anonymous

did you take the derivative?

9. Study23

No I'm still stuck on this problem!!

10. Study23

I don't know how to with those fractions

11. anonymous

the derivative of $$\frac{x^2}{16}$$ is $$\frac{x}{8}$$

12. Study23

Really? Wouldn't the 16 become a zero?

13. anonymous

and the derivative with respect to $$x$$ of $$-\frac{y^2}{9}$$ is $-\frac{2y}{9}y'$

14. anonymous

no it is a constant, think $\frac{x^2}{16}=\frac{1}{16}x^2$

15. Study23

Am I just using power rule here? I don't need to use quotient rule (that's what I was thinking...?)

16. Study23

@satellite73 I've been getting mixed answers from people. When do I know when I take the derivative of y to have yy' versus just y'???