## Study23 Group Title PLEASE HELP! (Waiting for an hour..._) Find an equation of the tangent line to the curve at the given point?? $$\ \Large \frac{x^2}{16}-\frac{y^2}{9} =1$$ $$\ \Large \text{The point is: } (-5, \frac{9}{4})$$. PLEASE HELP! one year ago one year ago

1. jaersyn Group Title

what math are you in?

2. Study23 Group Title

AP Calculus BC

3. jaersyn Group Title

what's "BC"

4. Study23 Group Title

It's just a level of calculus.... I need to find the derivative of this equation...

5. jaersyn Group Title

solve for y and take the derivative?

6. Study23 Group Title

This section involves implicit differentiation

7. jaersyn Group Title

ohhh

8. satellite73 Group Title

did you take the derivative?

9. Study23 Group Title

No I'm still stuck on this problem!!

10. Study23 Group Title

I don't know how to with those fractions

11. satellite73 Group Title

the derivative of $$\frac{x^2}{16}$$ is $$\frac{x}{8}$$

12. Study23 Group Title

Really? Wouldn't the 16 become a zero?

13. satellite73 Group Title

and the derivative with respect to $$x$$ of $$-\frac{y^2}{9}$$ is $-\frac{2y}{9}y'$

14. satellite73 Group Title

no it is a constant, think $\frac{x^2}{16}=\frac{1}{16}x^2$

15. Study23 Group Title

Am I just using power rule here? I don't need to use quotient rule (that's what I was thinking...?)

16. Study23 Group Title

@satellite73 I've been getting mixed answers from people. When do I know when I take the derivative of y to have yy' versus just y'???